Nested structs in Go - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a nested struct field.

Go

type Person struct {
    Name string
    Address [1]
}

type Address struct {
    City string
    Zip  int
}

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AAddress

Bstring

Cstruct

Dint

Attempts:

3 left

💡 Hint

Common Mistakes

Using basic types like string or int instead of the struct type.

Forgetting to use the struct type name.

The field Address inside Person must be of type Address to nest the struct.

2fill in blank

medium

Complete the code to create a variable of nested struct type.

Go

var p [1]
p = Person{
    Name: "Alice",
    Address: Address{
        City: "Wonderland",
        Zip: 12345,
    },
}

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AAddress

Bstring

Cstruct

DPerson

Attempts:

3 left

💡 Hint

Common Mistakes

Using the nested struct type Address instead of Person.

Using basic types like string.

The variable p must be of type Person to hold the nested Address struct.

3fill in blank

hard

Fix the error in accessing the nested struct field.

Go

fmt.Println(p.[1].City)

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AName

BAddress

CZip

DCity

Attempts:

3 left

💡 Hint

Common Mistakes

Trying to access City directly from p.

Using the wrong field name.

To access the city, you must first access the Address field inside p.

4fill in blank

hard

Fill both blanks to define and initialize a nested struct inline.

Go

p := Person{
    Name: "Bob",
    Address: [1]{
        City: "[2]",
        Zip: 54321,
    },
}

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AAddress

BPerson

CWondercity

DCityville

Attempts:

3 left

💡 Hint

Common Mistakes

Using the outer struct name instead of the nested struct type.

Putting a variable name instead of a string for the city.

The nested struct type is Address, and the city name is a string like Cityville.

5fill in blank

hard

Fill all three blanks to create a nested struct and print a nested field.

Go

type Company struct {
    Name    string
    Founder [1]
}

type Founder struct {
    FirstName string
    LastName  string
}

func main() {
    c := Company{
        Name: "TechCorp",
        Founder: [2]{
            FirstName: "Jane",
            LastName: "Doe",
        },
    }
    fmt.Println(c.Founder.[3])
}

Drag options to blanks, or click blank then click option'

AFounder

CFirstName

DLastName

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong struct type or field names.

Trying to print the whole struct instead of a field.

The Founder field in Company is of type Founder. We initialize it with Founder{...} and print the FirstName field.