Iterating over arrays in Go - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print each number in the array.

Go

numbers := [3]int{1, 2, 3}
for [1] := 0; i < len(numbers); i++ {
    fmt.Println(numbers[i])
}

Drag options to blanks, or click blank then click option'

Ai

Bj

Cnum

Dindex

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that is not used inside the loop.

Using a variable name that is not declared.

The variable i is commonly used as the index in for loops. Here, it iterates from 0 to the length of the array.

2fill in blank

medium

Complete the code to use a range loop to print each element in the array.

Go

numbers := [3]int{4, 5, 6}
for [1], value := range numbers {
    fmt.Println(value)
}

Drag options to blanks, or click blank then click option'

Aindex

Bi

C_

Dval

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that is not declared.

Trying to use only one variable without the index.

The variable i is commonly used as the index in range loops. It is ignored here but must be declared.

3fill in blank

hard

Fix the error in the for loop to correctly iterate over the array.

Go

arr := [3]string{"a", "b", "c"}
for i := 0; i <= len(arr); i++ {
    fmt.Println(arr[[1]])
}

Drag options to blanks, or click blank then click option'

A0

Bi-1

Ci+1

Di

Attempts:

3 left

💡 Hint

Common Mistakes

Using <= in the loop condition causing index out of range.

Using incorrect index inside the loop.

The loop should use i as the index. The condition should be i < len(arr) to avoid out-of-range errors.

4fill in blank

hard

Fill both blanks to create a map of words and their lengths for words longer than 3 characters.

Go

words := []string{"go", "code", "fun", "learn"}
lengths := map[string]int{word: [1] for _, word := range words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Bword

Clen(word) > 3

Dword == "go"

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself instead of its length.

Using the wrong condition to filter words.

The map stores the length of each word. The condition filters words longer than 3 characters.

5fill in blank

hard

Fill all three blanks to create a map of uppercase words and their lengths for words with length greater than 2.

Go

words := []string{"go", "code", "fun", "learn"}
lengths := map[string]int[1]: [2] for _, word := range words if [3]

Drag options to blanks, or click blank then click option'

Astrings.ToUpper(word)

Blen(word)

Clen(word) > 2

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Not converting words to uppercase for keys.

Using wrong length condition.

Mixing up keys and values in the map.

The map keys are uppercase words, values are their lengths, filtered by length greater than 2.

Practice

1. What does the range keyword do when used with an array in Go?

easy

A. It creates a new array with copied elements.

B. It changes the size of the array during iteration.

C. It lets you loop over each element and get its index and value.

D. It sorts the array elements automatically.

Solution

1. Step 1: Understand the role of range in loops

   The range keyword in Go is used to iterate over elements in arrays, slices, maps, and more, providing both the index and the value of each element.

2. Step 2: Identify what range does with arrays

   When used with an array, range returns the index and the value of each element one by one, allowing you to process or read each item.

3. Final Answer:

   It lets you loop over each element and get its index and value. -> Option C

4. Quick Check:

   range loops with index and value [OK]

Hint: Remember: range gives index and value for each element [OK]

Common Mistakes:

• Thinking range changes array size
• Assuming range sorts elements
• Believing range copies the array

2. Which of the following is the correct syntax to iterate over an array named nums in Go?

easy

A. for i, v := range nums { fmt.Println(i, v) }

B. for i in nums { fmt.Println(i) }

C. foreach i, v in nums { fmt.Println(i, v) }

D. for (i, v) in nums { fmt.Println(i, v) }

Solution

1. Step 1: Recall Go's for-range loop syntax

   In Go, the correct way to iterate over arrays or slices is using for index, value := range array syntax.

2. Step 2: Match the syntax with the options

   for i, v := range nums { fmt.Println(i, v) } uses for i, v := range nums, which is the correct Go syntax. Other options use invalid or non-Go syntax.

3. Final Answer:

   for i, v := range nums { fmt.Println(i, v) } -> Option A

4. Quick Check:

   Go uses for i, v := range array [OK]

Hint: Use 'for i, v := range array' for Go array loops [OK]

Common Mistakes:

• Using 'for i in nums' like Python
• Using 'foreach' which is not Go syntax
• Using parentheses in for loop header

3. What will be the output of this Go code?

nums := [3]int{10, 20, 30}
for i, v := range nums {
    fmt.Println(i, v)
}

medium

A. 0 0
1 1
2 2

B. 10 0
20 1
30 2

C. Syntax error

D. 0 10
1 20
2 30

Solution

1. Step 1: Understand the array and loop

   The array nums has 3 elements: 10 at index 0, 20 at index 1, and 30 at index 2. The loop uses range to get index and value.

2. Step 2: Trace the loop output

   Each iteration prints the index and the value: first line prints "0 10", second "1 20", third "2 30".

3. Final Answer:

   0 10 1 20 2 30 -> Option D

4. Quick Check:

   Index and value printed in order [OK]

Hint: range returns index then value in order [OK]

Common Mistakes:

• Swapping index and value in print
• Expecting values as indexes
• Thinking code has syntax error

4. Identify the error in this Go code snippet:

nums := [3]int{1, 2, 3}
for i, v = range nums {
    fmt.Println(i, v)
}

medium

A. Missing colon in 'for i, v = range nums' should be ':='

B. Using '=' instead of '==' in loop condition

C. Array declaration syntax is wrong

D. fmt.Println cannot print two variables

Solution

1. Step 1: Check the for loop variable declaration

   In Go, when declaring variables in a for-range loop, you must use ':=' to declare and assign variables, not '='.

2. Step 2: Identify the syntax error

   The code uses '=' instead of ':=' in for i, v = range nums, which causes a syntax error.

3. Final Answer:

   Missing colon in 'for i, v = range nums' should be ':=' -> Option A

4. Quick Check:

   Use ':=' to declare variables in for-range loops [OK]

Hint: Use ':=' not '=' in for-range variable declaration [OK]

Common Mistakes:

• Using '=' instead of ':=' in for loop
• Confusing assignment with comparison
• Incorrect array syntax blamed

5. Given an array nums := [5]int{1, 2, 3, 4, 5}, how can you create a new slice containing only the even numbers using iteration?

hard

A. Use a for loop to change the array size and remove odd numbers.

B. Use a for-range loop to check each value and append even numbers to a slice.

C. Use range to multiply all numbers by 2 and store in a new array.

D. Use a for loop with index only and ignore values.

Solution

1. Step 1: Understand the goal and array

   The goal is to create a new slice with only even numbers from the array nums. Arrays have fixed size, so we cannot remove elements from it.

2. Step 2: Use for-range loop and append even values

   We iterate over nums using for _, v := range nums, check if v % 2 == 0, and append those values to a new slice.

3. Final Answer:

   Use a for-range loop to check each value and append even numbers to a slice. -> Option B

4. Quick Check:

   Filter with for-range and append even numbers [OK]

Hint: Filter with for-range and append to slice [OK]

Common Mistakes:

• Trying to change array size directly
• Ignoring values in loop
• Multiplying instead of filtering