A map in Go is a collection of key-value pairs where each key is unique and is used to access its corresponding value.
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beginner
How do you access a value from a map in Go?
You access a value by using the key inside square brackets after the map variable, like: value := myMap[key].
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beginner
What happens if you try to access a key that does not exist in a Go map?
Go returns the zero value of the map's value type (e.g., 0 for int, "" for string) if the key is not found.
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intermediate
How can you check if a key exists in a Go map when accessing its value?
You can use the two-value assignment: value, ok := myMap[key]. The 'ok' is true if the key exists, false otherwise.
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intermediate
Why is it useful to check if a key exists in a Go map before using its value?
Because accessing a non-existent key returns a zero value, which might be misleading. Checking existence helps avoid bugs by confirming the key is present.
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How do you access the value for key "name" in a Go map called 'person'?
Aperson["name"]
Bperson.name
Cperson->name
Dperson.get("name")
✗ Incorrect
In Go, map values are accessed using square brackets with the key inside, like person["name"].
What does Go return if you access a key that does not exist in a map?
AAn error is thrown
BThe zero value of the map's value type
Cnil
DThe last inserted value
✗ Incorrect
Go returns the zero value for the map's value type if the key is missing, without throwing an error.
Which syntax correctly checks if a key exists in a Go map?
Avalue, ok := myMap[key]
Bvalue := myMap[key]
Cexists := myMap.contains(key)
Dif myMap[key] != nil
✗ Incorrect
The two-value assignment 'value, ok := myMap[key]' lets you check if the key exists with 'ok'.
What type is the variable 'ok' when checking map key existence in Go?
Aint
Bstring
Cbool
Dinterface{}
✗ Incorrect
'ok' is a boolean that is true if the key exists, false otherwise.
Why might you want to check if a key exists before using its value from a map?
ATo avoid runtime errors
BTo delete the key
CTo get the zero value
DTo confirm the key is present and avoid using default zero values mistakenly
✗ Incorrect
Checking existence helps avoid confusion caused by zero values returned for missing keys.
Explain how to access a value from a map in Go and how to check if the key exists.
Think about how you get a value and also know if it is really there.
You got /3 concepts.
Describe what happens when you access a key that does not exist in a Go map and why checking existence is important.
Consider what Go returns and how that might confuse your program.
You got /3 concepts.
Practice
(1/5)
1. What does the expression value, ok := myMap["key"] do in Go?
easy
A. It retrieves the value for "key" and checks if the key exists in the map.
B. It deletes the key "key" from the map.
C. It adds a new key "key" with value "ok" to the map.
D. It returns the number of keys in the map.
Solution
Step 1: Understand map access syntax
In Go, value, ok := myMap["key"] retrieves the value for the key and a boolean indicating if the key exists.
Step 2: Explain the boolean ok
The ok is true if the key is present, false otherwise.
Final Answer:
It retrieves the value for "key" and checks if the key exists in the map. -> Option A
Quick Check:
Map access with existence check = value, ok [OK]
Hint: Remember: value, ok checks key presence in map [OK]
Common Mistakes:
Thinking it deletes the key
Assuming it adds a key
Confusing it with map length
2. Which of the following is the correct way to check if a key exists in a Go map named m for key k?
easy
A. value, ok := m[k]; if ok { ... }
B. value := m[k]; if value != nil { ... }
C. if m.contains(k) { ... }
D. if m[k] != 0 { ... }
Solution
Step 1: Recall Go map existence check syntax
In Go, to check if a key exists, use value, ok := m[k] and then check ok.
Step 2: Analyze options
value := m[k]; if value != nil { ... } wrongly assumes value is nil for missing keys, which is not always true. if m.contains(k) { ... } uses a method that does not exist. if m[k] != 0 { ... } checks value but zero value can be valid.
Final Answer:
value, ok := m[k]; if ok { ... } -> Option A
Quick Check:
Use value, ok to check key presence [OK]
Hint: Use value, ok := map[key] to check key existence [OK]
Common Mistakes:
Checking value against nil or zero instead of ok
Using non-existent map methods
Assuming zero value means key missing
3. What will be the output of this Go code?
m := map[string]int{"a": 10, "b": 20}
value, ok := m["c"]
fmt.Println(value, ok)
medium
A. Compilation error
B. 0 true
C. 20 true
D. 0 false
Solution
Step 1: Understand map lookup for missing key
Key "c" is not in map m, so value gets zero value for int, which is 0, and ok is false.
Step 2: Print output values
Printing value and ok prints "0 false".
Final Answer:
0 false -> Option D
Quick Check:
Missing key returns zero value and false [OK]
Hint: Missing map keys return zero value and false [OK]
Common Mistakes:
Assuming missing key returns true
Expecting runtime error for missing key
Confusing zero value with actual stored value
4. Identify the error in this Go code snippet:
m := map[string]int{"x": 5}
value := m["y"]
if value {
fmt.Println("Key exists")
}
medium
A. Missing declaration of map m.
B. Map key "y" does not exist, causing runtime panic.
C. Cannot use int value as boolean in if condition.
D. Syntax error in map initialization.
Solution
Step 1: Analyze the if condition
The variable value is an int, but Go requires a boolean expression in if conditions.
Step 2: Understand Go type rules
Using an int directly as a boolean causes a compile-time error.
Final Answer:
Cannot use int value as boolean in if condition. -> Option C
Quick Check:
if conditions need boolean, not int [OK]
Hint: if needs boolean, not int value [OK]
Common Mistakes:
Assuming missing key causes panic
Ignoring type mismatch in if condition
Thinking map declaration is missing
5. Given a map m := map[string]int{"a": 1, "b": 0, "c": 3}, how can you print only keys that exist and have a non-zero value?
hard
A. for k := range m { if m[k] { fmt.Println(k) } }
B. for k, v := range m { if v != 0 { fmt.Println(k) } }
C. for k, v := range m { if m[k] != nil { fmt.Println(k) } }
D. for k, v := range m { if v { fmt.Println(k) } }
Solution
Step 1: Iterate over map with key and value
Use for k, v := range m to get keys and values.
Step 2: Check for non-zero values
Check if v != 0 to filter keys with non-zero values.
Step 3: Print keys that meet condition
Print the key k inside the if block.
Final Answer:
for k, v := range m { if v != 0 { fmt.Println(k) } } -> Option B
Quick Check:
Filter keys by value != 0 using range loop [OK]
Hint: Use for k,v := range map and check v != 0 [OK]
Common Mistakes:
Using value as boolean directly
Checking map key against nil
Ignoring zero values in condition
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