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Prompt Engineering / GenAIml~10 mins

Prompt injection defense in Prompt Engineering / GenAI - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to safely add user input to the prompt.

Prompt Engineering / GenAI
safe_prompt = base_prompt + ' User says: ' + [1]
Drag options to blanks, or click blank then click option'
Auser_input
Bsanitize(user_input)
Craw_input
Dinput()
Attempts:
3 left
💡 Hint
Common Mistakes
Using raw user input without cleaning.
Using input() which reads new input instead of the variable.
2fill in blank
medium

Complete the code to detect prompt injection keywords.

Prompt Engineering / GenAI
if '[1]' in user_input.lower():
    alert('Possible injection detected')
Drag options to blanks, or click blank then click option'
Aignore previous command
Bdelete all
Cignore previous
Dignore previous instructions
Attempts:
3 left
💡 Hint
Common Mistakes
Using incomplete or incorrect phrases that don't match injection attempts.
Checking for unrelated words.
3fill in blank
hard

Fix the error in the function that blocks injection by replacing dangerous words.

Prompt Engineering / GenAI
def block_injection(text):
    blocked_text = text.replace([1], '[REDACTED]')
    return blocked_text
Drag options to blanks, or click blank then click option'
A'ignore previous instructions'
Bignore previous instructions
C'ignore previous'
D'delete all'
Attempts:
3 left
💡 Hint
Common Mistakes
Passing a variable name without quotes causes a NameError.
Using incomplete phrases that don't match the injection.
4fill in blank
hard

Fill both blanks to create a safe prompt by filtering and then formatting user input.

Prompt Engineering / GenAI
def create_safe_prompt(user_input):
    filtered = [1](user_input)
    prompt = f"System: Follow rules. User says: [2]"
    return prompt
Drag options to blanks, or click blank then click option'
Asanitize
Buser_input
Cfiltered
Dclean_input
Attempts:
3 left
💡 Hint
Common Mistakes
Using the original user_input directly in the prompt.
Mixing variable names incorrectly.
5fill in blank
hard

Fill all three blanks to check for injection and respond safely.

Prompt Engineering / GenAI
def respond(user_input):
    if [1] in user_input.lower():
        return '[2]'
    safe_input = [3](user_input)
    return f"Processed: {safe_input}"
Drag options to blanks, or click blank then click option'
A'ignore previous instructions'
B'Injection detected. Input blocked.'
Csanitize
Duser_input
Attempts:
3 left
💡 Hint
Common Mistakes
Not checking for the exact injection phrase.
Returning unsafe input directly.
Not sanitizing input before use.

Practice

(1/5)
1. What is the main purpose of prompt injection defense in AI systems?
easy
A. To protect AI from harmful or tricky user inputs
B. To improve AI's speed in processing data
C. To increase the size of the AI model
D. To reduce the cost of running AI models

Solution

  1. Step 1: Understand the role of prompt injection defense

    Prompt injection defense is designed to stop harmful or tricky inputs from confusing or misguiding the AI.
  2. Step 2: Compare options with this purpose

    Only To protect AI from harmful or tricky user inputs matches this goal; others relate to speed, size, or cost, which are unrelated.
  3. Final Answer:

    To protect AI from harmful or tricky user inputs -> Option A
  4. Quick Check:

    Purpose of prompt injection defense = Protect AI inputs [OK]
Hint: Focus on defense meaning protection from bad inputs [OK]
Common Mistakes:
  • Confusing defense with performance improvement
  • Thinking it changes AI model size
  • Assuming it reduces costs
2. Which of the following is a correct way to implement a simple prompt injection defense filter in Python?
easy
A. if user_input = 'DROP TABLE': block_request()
B. if 'DROP TABLE' in user_input.upper(): block_request()
C. if user_input.contains('DROP TABLE'): block_request()
D. if user_input == 'drop table': block_request()

Solution

  1. Step 1: Check syntax for string containment in Python

    Python uses in to check if a substring exists in a string, and upper() helps catch case differences.
  2. Step 2: Evaluate each option's correctness

    if 'DROP TABLE' in user_input.upper(): block_request() uses correct syntax and case normalization. if user_input = 'DROP TABLE': block_request() uses assignment instead of comparison. if user_input.contains('DROP TABLE'): block_request() uses a non-existent method contains. if user_input == 'drop table': block_request() checks exact lowercase match, missing case variations.
  3. Final Answer:

    if 'DROP TABLE' in user_input.upper(): block_request() -> Option B
  4. Quick Check:

    Use 'in' and upper() for case-insensitive check [OK]
Hint: Remember Python uses 'in' for substring checks [OK]
Common Mistakes:
  • Using '=' instead of '==' for comparison
  • Using non-existent string methods
  • Ignoring case sensitivity in checks
3. Given the code below, what will be the output if user_input = "Please DROP TABLE users"?
def block_request():
    return "Blocked"

def process_input(user_input):
    if 'DROP TABLE' in user_input.upper():
        return block_request()
    return "Allowed"

print(process_input(user_input))
medium
A. SyntaxError
B. Allowed
C. Blocked
D. None

Solution

  1. Step 1: Analyze the condition in process_input

    The input string uppercased is "PLEASE DROP TABLE USERS" which contains "DROP TABLE".
  2. Step 2: Determine which branch runs

    Since the condition is true, block_request() is called, returning "Blocked".
  3. Final Answer:

    Blocked -> Option C
  4. Quick Check:

    Input contains 'DROP TABLE' -> Blocked [OK]
Hint: Check if uppercase input contains 'DROP TABLE' [OK]
Common Mistakes:
  • Ignoring case and expecting 'Allowed'
  • Thinking code has syntax errors
  • Assuming function returns None by default
4. Identify the error in this prompt injection defense code snippet:
def check_input(text):
    if text.lower().find('delete'):
        return 'Blocked'
    return 'Allowed'
medium
A. The find method returns -1 if not found, so condition is wrong
B. Using lower() is incorrect for filtering
C. The function should return a boolean, not strings
D. The function is missing a parameter

Solution

  1. Step 1: Understand find method behavior

    find returns the index of substring or -1 if not found. In Python, -1 is truthy, so condition fails.
  2. Step 2: Explain why this causes wrong logic

    If 'delete' is not found, condition is true (wrong). It should check if result is not -1 explicitly.
  3. Final Answer:

    The find method returns -1 if not found, so condition is wrong -> Option A
  4. Quick Check:

    Check find() != -1 for correct condition [OK]
Hint: Remember find() returns -1 if substring missing [OK]
Common Mistakes:
  • Assuming find() returns False when not found
  • Ignoring that -1 is truthy in Python
  • Thinking lower() is the error
5. You want to defend an AI prompt from injection attacks by blocking inputs containing any of these words: ['DROP', 'DELETE', 'SHUTDOWN']. Which code snippet correctly implements this defense?
hard
A. if user_input.upper() == 'DROP' or 'DELETE' or 'SHUTDOWN': block_request()
B. if all(word in user_input.upper() for word in ['DROP', 'DELETE', 'SHUTDOWN']): block_request()
C. if 'DROP' or 'DELETE' or 'SHUTDOWN' in user_input.upper(): block_request()
D. if any(word in user_input.upper() for word in ['DROP', 'DELETE', 'SHUTDOWN']): block_request()

Solution

  1. Step 1: Understand the goal to block if any word is present

    We want to block if at least one of the words appears in the input.
  2. Step 2: Evaluate each option's logic

    if any(word in user_input.upper() for word in ['DROP', 'DELETE', 'SHUTDOWN']): block_request() uses any() correctly to check presence of any word. if all(word in user_input.upper() for word in ['DROP', 'DELETE', 'SHUTDOWN']): block_request() requires all words, which is too strict. if 'DROP' or 'DELETE' or 'SHUTDOWN' in user_input.upper(): block_request() has incorrect syntax; it always evaluates to true due to or chaining. if user_input.upper() == 'DROP' or 'DELETE' or 'SHUTDOWN': block_request() compares whole input to each word incorrectly.
  3. Final Answer:

    if any(word in user_input.upper() for word in ['DROP', 'DELETE', 'SHUTDOWN']): block_request() -> Option D
  4. Quick Check:

    Use any() to check multiple keywords [OK]
Hint: Use any() to check if any keyword is in input [OK]
Common Mistakes:
  • Using all() instead of any()
  • Incorrect or chaining causing always true
  • Comparing whole string instead of substring