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GCPcloud~15 mins

Organization node in GCP - Mini Project: Build & Apply

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Create a GCP Organization Node Configuration
📖 Scenario: You are setting up a Google Cloud Platform (GCP) environment for a company. The company wants to organize its cloud resources under a single Organization node to manage policies and billing centrally.
🎯 Goal: Build a basic configuration that defines a GCP Organization node with its ID and display name.
📋 What You'll Learn
Create a variable called organization_id with the exact value "123456789012".
Create a variable called organization_display_name with the exact value "Example Corp".
Define a dictionary called organization_node that includes id and display_name keys using the variables above.
Add a final key lifecycle_state with the value "ACTIVE" to the organization_node dictionary.
💡 Why This Matters
🌍 Real World
Organizations in GCP help companies manage all their cloud projects and resources under one roof, making it easier to apply policies and billing.
💼 Career
Understanding how to define and configure organization nodes is essential for cloud administrators and architects managing enterprise cloud environments.
Progress0 / 4 steps
1
Set the Organization ID
Create a variable called organization_id and set it to the string "123456789012".
GCP
Need a hint?

The organization ID is a string of numbers. Use quotes around it.

2
Set the Organization Display Name
Create a variable called organization_display_name and set it to the string "Example Corp".
GCP
Need a hint?

Use quotes to set the display name as a string.

3
Define the Organization Node Dictionary
Create a dictionary called organization_node with keys id and display_name. Set their values to the variables organization_id and organization_display_name respectively.
GCP
Need a hint?

Use curly braces to create the dictionary and colons to assign keys to values.

4
Add Lifecycle State to Organization Node
Add a key lifecycle_state with the value "ACTIVE" to the organization_node dictionary.
GCP
Need a hint?

Add the new key and value inside the dictionary with a comma after the previous entry.