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Model classes from JSON in Flutter - Practice Problems & Coding Challenges

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Challenge - 5 Problems
🎖️
JSON Model Master
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📝 Syntax
intermediate
2:00remaining
Correct JSON parsing in Flutter model
Given this JSON string representing a user:
{"id": 1, "name": "Alice", "email": "alice@example.com"}

Which Dart code correctly parses this JSON into a User model?
Flutter
class User {
  final int id;
  final String name;
  final String email;

  User({required this.id, required this.name, required this.email});

  factory User.fromJson(Map<String, dynamic> json) {
    return User(
      id: json['id'],
      name: json['name'],
      email: json['email'],
    );
  }
}
Afactory User.fromJson(Map<String, dynamic> json) => User(id: json['id'], name: json['name'], email: json['email']);
BUser.fromJson(Map<String, dynamic> json) => User(id: json['id'].toString(), name: json['name'], email: json['email']);
CUser.fromJson(Map<String, dynamic> json) => User(id: json['id'], name: json['name'], email: json['email'].toInt());
DUser.fromJson(Map<String, dynamic> json) => User(id: json['id'], name: json['name'], email: json['email']);
Attempts:
2 left
💡 Hint
Check the data types expected by the User constructor and how JSON values are accessed.
❓ ui_behavior
intermediate
1:30remaining
Displaying parsed model data in Flutter UI
You have parsed a User model from JSON. Which Flutter widget code correctly displays the user's name and email in a column?
Flutter
final user = User(id: 1, name: "Alice", email: "alice@example.com");
ARow(children: [Text(user.name), Text(user.email)])
BColumn(children: [Text(user.name), Text(user.email.toString())])
CColumn(children: [Text(user.name), Text(user.email)])
DColumn(children: [Text(user.id), Text(user.email)])
Attempts:
2 left
💡 Hint
Use a vertical layout and display the correct fields as strings.
❓ lifecycle
advanced
2:00remaining
When to parse JSON in Flutter widget lifecycle
You receive JSON data asynchronously and want to parse it into a model and display it. Which Flutter widget lifecycle method is best to parse JSON after data is fetched?
AdidChangeDependencies()
BinitState()
Cbuild()
Ddispose()
Attempts:
2 left
💡 Hint
Consider when you want to initialize state once before UI builds.
❓ navigation
advanced
2:00remaining
Passing model data between Flutter screens
You have parsed a User model from JSON on Screen A. How do you pass this User object to Screen B when navigating?
ABoth B and C are valid ways to pass the model.
BNavigator.pushNamed(context, '/screenB', arguments: user);
CNavigator.push(context, MaterialPageRoute(builder: (_) => ScreenB(user: user)));
DYou cannot pass objects between screens in Flutter.
Attempts:
2 left
💡 Hint
Flutter supports passing data via constructor or route arguments.
🔧 Debug
expert
2:30remaining
Identify the cause of JSON parsing runtime error
Given this Dart code snippet parsing JSON:
final jsonString = '{"id": "1", "name": "Bob", "email": "bob@example.com"}';
final Map userMap = jsonDecode(jsonString);
final user = User.fromJson(userMap);

The User model expects id as int but JSON has id as string. What error will occur?
ANo error, code runs fine
BFormatException: Invalid JSON format
CNullPointerException
DTypeError: String cannot be assigned to int
Attempts:
2 left
💡 Hint
Check the type mismatch between JSON field and model field.

Practice

(1/5)
1. What is the main purpose of a model class when working with JSON in Flutter?
easy
A. To handle user input events
B. To display UI elements on the screen
C. To convert JSON data into Dart objects and back
D. To manage app navigation between screens

Solution

  1. Step 1: Understand the role of model classes

    Model classes are designed to represent data structures in Dart that match JSON data.
  2. Step 2: Identify the purpose related to JSON

    They convert JSON strings into Dart objects and convert Dart objects back to JSON for easy data handling.
  3. Final Answer:

    To convert JSON data into Dart objects and back -> Option C
  4. Quick Check:

    Model class = JSON conversion [OK]
Hint: Model classes handle JSON to Dart object conversion [OK]
Common Mistakes:
  • Confusing model classes with UI widgets
  • Thinking model classes manage navigation
  • Assuming model classes handle user input
2. Which of the following is the correct syntax for a factory constructor named fromJson in a Dart model class?
easy
A. factory Model.fromJson(Map json) { return Model(json['id']); }
B. Model.fromJson(Map json) { return Model(json['id']); }
C. factory Model.fromJson(Map json) { Model(json['id']); }
D. Model.fromJson(Map json) => Model(json['id']);

Solution

  1. Step 1: Recall factory constructor syntax

    In Dart, a factory constructor uses the keyword 'factory' and returns an instance, often with a return statement.
  2. Step 2: Check each option for correct syntax

    factory Model.fromJson(Map json) { return Model(json['id']); } correctly uses 'factory', has the parameter, and returns a new Model instance inside braces.
  3. Final Answer:

    factory Model.fromJson(Map json) { return Model(json['id']); } -> Option A
  4. Quick Check:

    Factory constructor syntax = factory Model.fromJson(Map json) { return Model(json['id']); } [OK]
Hint: Factory constructors need 'factory' keyword and return statement [OK]
Common Mistakes:
  • Omitting the 'factory' keyword
  • Not returning an instance
  • Using arrow syntax without 'factory'
3. Given this Dart model class snippet, what will print(user.name); output?
class User {
  final String name;
  User(this.name);

  factory User.fromJson(Map json) {
    return User(json['name']);
  }
}

void main() {
  final json = {'name': 'Alice'};
  final user = User.fromJson(json);
  print(user.name);
}
medium
A. null
B. Alice
C. User Instance
D. Error: No such method

Solution

  1. Step 1: Understand fromJson factory usage

    The factory constructor takes the JSON map and extracts the 'name' value, passing it to the User constructor.
  2. Step 2: Trace the print statement

    The user object has name set to 'Alice', so printing user.name outputs 'Alice'.
  3. Final Answer:

    Alice -> Option B
  4. Quick Check:

    JSON 'name' value = printed name [OK]
Hint: fromJson sets fields from JSON keys [OK]
Common Mistakes:
  • Expecting print to show object instead of field
  • Confusing factory constructor with normal constructor
  • Assuming null if key missing
4. Identify the error in this Dart model class code for JSON parsing:
class Product {
  final int id;
  final String name;

  Product(this.id, this.name);

  factory Product.fromJson(Map json) {
    return Product(json['id'], json['title']);
  }
}
medium
A. The JSON key 'title' does not match the field 'name'
B. The constructor parameters are in wrong order
C. Missing semicolon after constructor
D. Factory constructor should not return Product instance

Solution

  1. Step 1: Compare JSON keys with class fields

    The class has a field 'name' but the factory uses 'json['title']' which does not match.
  2. Step 2: Understand impact of key mismatch

    This causes the 'name' field to get null or wrong value, leading to incorrect data mapping.
  3. Final Answer:

    The JSON key 'title' does not match the field 'name' -> Option A
  4. Quick Check:

    JSON keys must match field names [OK]
Hint: JSON keys must match model field names exactly [OK]
Common Mistakes:
  • Using wrong JSON keys
  • Ignoring field and parameter order
  • Thinking factory can't return instance
5. You have a JSON list of users: [{'id':1,'name':'Bob'},{'id':2,'name':'Eve'}]. How do you convert this list into a Dart list of User objects using a model class with fromJson factory?
hard
A. User.fromJson(jsonList[0])
B. User.fromJson(jsonList)
C. jsonList.forEach((json) => User.fromJson(json))
D. jsonList.map((json) => User.fromJson(json)).toList()

Solution

  1. Step 1: Understand JSON list to Dart list conversion

    Each JSON map in the list must be converted to a User object using fromJson.
  2. Step 2: Use map and toList for conversion

    Using map applies fromJson to each item, and toList collects results into a Dart list.
  3. Final Answer:

    jsonList.map((json) => User.fromJson(json)).toList() -> Option D
  4. Quick Check:

    Map each JSON to User, then toList [OK]
Hint: Use map + fromJson + toList to convert JSON list [OK]
Common Mistakes:
  • Passing whole list to fromJson expecting batch conversion
  • Using forEach without collecting results
  • Converting only first item
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