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Flaskframework~10 mins

Serving images in Flask - Step-by-Step Execution

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Concept Flow - Serving images
Start Flask app
Client requests image URL
Flask route matches URL
Flask reads image file
Flask sends image data with correct headers
Browser receives and displays image
End
The Flask app waits for an image request, reads the image file, sends it with proper headers, and the browser shows the image.
Execution Sample
Flask
from flask import Flask, send_file
app = Flask(__name__)

@app.route('/image')
def image():
    return send_file('cat.jpg', mimetype='image/jpeg')
This code serves a JPEG image file named 'cat.jpg' when the '/image' URL is visited.
Execution Table
StepActionInput/RequestFlask ResponseBrowser Behavior
1Start Flask appNoneApp running, waiting for requestsNone
2Client requests '/image'GET /imageRoute '/image' matchedNone
3Flask reads 'cat.jpg'File path 'cat.jpg'Image file loadedNone
4Flask sends image dataImage bytes with mimetype 'image/jpeg'HTTP response with image dataBrowser starts loading image
5Browser displays imageImage data receivedRendered image shown on pageImage visible to user
6EndRequest completeConnection closed or kept aliveImage stays visible
💡 Request ends after image data is sent and browser displays it.
Variable Tracker
VariableStartAfter Step 3After Step 4Final
appFlask instance createdRunning and waitingRunning and serving imageRunning
requestNoneGET /image receivedHandledNone
image fileNot loadedLoaded 'cat.jpg' bytesSent in responseSent
responseNonePreparingImage data with headersSent
Key Moments - 3 Insights
Why do we need to specify the mimetype when sending an image?
The mimetype tells the browser what kind of file it is receiving so it can display it correctly. See execution_table step 4 where 'image/jpeg' is sent.
What happens if the image file path is wrong or missing?
Flask will raise an error because it cannot find the file to send. This would stop the flow at step 3 in the execution_table.
Can Flask serve images without using send_file?
Yes, but send_file is the easiest and safest way to serve files with correct headers. Manually sending bytes requires setting headers yourself.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what does Flask do at step 3?
ASends the image data to the browser
BReads the image file from disk
CStarts the Flask app
DDisplays the image in the browser
💡 Hint
Check the 'Action' and 'Flask Response' columns at step 3 in the execution_table.
At which step does the browser start showing the image?
AStep 2
BStep 4
CStep 5
DStep 6
💡 Hint
Look for 'Browser displays image' in the execution_table.
If the mimetype was missing in step 4, what would happen?
AThe browser might not display the image correctly
BFlask would crash immediately
CThe image file would not be read
DThe client would not send a request
💡 Hint
Refer to the importance of mimetype in key_moments and execution_table step 4.
Concept Snapshot
Serving images in Flask:
- Use @app.route to define URL
- Use send_file('path', mimetype='image/type') to send image
- Browser requests URL, Flask sends image bytes with headers
- Browser displays image automatically
- Always specify correct mimetype for proper display
Full Transcript
This example shows how Flask serves images. The app starts and waits for requests. When a client asks for '/image', Flask reads the image file 'cat.jpg' from disk. It then sends the image data with the correct mimetype 'image/jpeg'. The browser receives this data and displays the image on the page. The process ends after the image is shown. Specifying mimetype is important so the browser knows how to handle the file. If the file is missing, Flask will error. Using send_file is the easiest way to serve images with proper headers.