Control structures (if, for) in Flask - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to loop over the list and print each item.

Flask

items = ['apple', 'banana', 'cherry']
for [1] in items:
    print([1])

Drag options to blanks, or click blank then click option'

Ai

Bitem

Cfruit

Dx

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that is not consistent inside the loop.

Forgetting to use the loop variable in the print statement.

The variable item is used to represent each element in the list during the loop.

2fill in blank

medium

Complete the code to check if a user is logged in and show a welcome message.

Flask

if [1] == True:
    print('Welcome back!')
else:
    print('Please log in.')

Drag options to blanks, or click blank then click option'

Alogged_in

Buser_logged

Clogin_status

Dis_logged

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that is not defined or inconsistent.

Forgetting to compare the variable to True explicitly.

The variable logged_in is commonly used to check if the user is logged in.

3fill in blank

hard

Fix the error in the for loop to correctly iterate over the range of numbers.

Flask

for num in range([1]):
    print(num)

Drag options to blanks, or click blank then click option'

Arange(10)

B1, 10

C0, 10

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Passing multiple arguments without unpacking.

Using range(10) inside the range function.

The range function needs a single integer to define the stop value. Using 10 iterates from 0 to 9.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths for words longer than 3 letters.

Flask

lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using the wrong comparison operator.

The dictionary maps each word to its length using len(word). The condition filters words longer than 3 letters using >.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths for words longer than 4 letters.

Flask

result = { [1]: [2] for w in words if len(w) [3] 4 }

Drag options to blanks, or click blank then click option'

Aw.upper()

Blen(w)

C>

Dw

Attempts:

3 left

💡 Hint

Common Mistakes

Using the original word as the key instead of uppercase.

Using the wrong comparison operator or value.

The key is the uppercase word using w.upper(). The value is the length len(w). The condition filters words longer than 4 letters using >.