Querying with where clause in Firebase - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to query documents where the field 'age' equals 25.

Firebase

const query = collectionRef.where('age', '==', [1]);

Drag options to blanks, or click blank then click option'

A35

B25

C20

D30

Attempts:

3 left

💡 Hint

Common Mistakes

Using a wrong number in the filter.

Confusing the operator '==' with other operators.

The where clause filters documents where the 'age' field is exactly 25.

2fill in blank

medium

Complete the code to query documents where the field 'status' is 'active'.

Firebase

const activeUsers = collectionRef.where('status', '==', [1]);

Drag options to blanks, or click blank then click option'

A'inactive'

B'pending'

C'active'

D'deleted'

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting to put quotes around the string value.

Using the wrong status value.

The query filters documents where the 'status' field is exactly 'active'.

3fill in blank

hard

Fix the error in the query to find documents where 'score' is greater than 80.

Firebase

const highScores = collectionRef.where('score', [1], 80);

Drag options to blanks, or click blank then click option'

A==

B<

C<=

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' instead of '>'.

Using '<' which finds lower scores.

The operator '>' means greater than, so it finds documents with score above 80.

4fill in blank

hard

Fill both blanks to query documents where 'age' is less than 30 and 'status' is 'active'.

Firebase

const query = collectionRef.where('age', [1], 30).where('status', [2], 'active');

Drag options to blanks, or click blank then click option'

A<

B==

C>

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '<' for age.

Using '!=' instead of '==' for status.

The first condition filters ages less than 30, the second filters status equal to 'active'.

5fill in blank

hard

Fill all three blanks to query documents where 'score' is greater than 50, 'age' is less than 40, and 'status' is 'active'.

Firebase

const complexQuery = collectionRef.where('score', [1], 50).where('age', [2], 40).where('status', [3], 'active');

Drag options to blanks, or click blank then click option'

A>

B<

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up comparison operators.

Using '!=' instead of '==' for status.

The query filters documents with score > 50, age < 40, and status equal to 'active'.