Multiple file uploads in FastAPI - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the correct class for handling file uploads in FastAPI.

FastAPI

from fastapi import FastAPI, [1]

Drag options to blanks, or click blank then click option'

AUploadFile

BRequest

CFile

DForm

Attempts:

3 left

💡 Hint

Common Mistakes

Using File instead of UploadFile

Importing Form instead of UploadFile

FastAPI uses UploadFile to handle file uploads efficiently.

2fill in blank

medium

Complete the code to accept multiple files in the endpoint function parameter.

FastAPI

async def upload_files(files: list[[1]]):

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Abytes

BFile

CUploadFile

Dstr

Attempts:

3 left

💡 Hint

Common Mistakes

Using list[File] instead of list[UploadFile]

Using list[str] which is incorrect for files

To accept multiple files, use a list of UploadFile objects.

3fill in blank

hard

Fix the error in the endpoint decorator to accept multiple files with the correct parameter.

FastAPI

@app.post("/upload")
async def upload(files: list[UploadFile] = [1]):

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AFile()

BFile(...)

CForm(...)

DDepends()

Attempts:

3 left

💡 Hint

Common Mistakes

Using File() which makes the parameter optional

Using Form(...) which is for form fields, not files

Use File(...) to mark the parameter as required for multiple file uploads.

4fill in blank

hard

Fill both blanks to read the filename and content of each uploaded file.

FastAPI

for file in files:
    filename = file.[1]
    content = await file.[2]()

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Afilename

Bread

Ccontent

Dwrite

Attempts:

3 left

💡 Hint

Common Mistakes

Using file.content instead of file.filename

Calling file.write() instead of file.read()

Use file.filename to get the file name and await file.read() to get its content.

5fill in blank

hard

Fill all three blanks to define the FastAPI app, import UploadFile and File, and create the upload endpoint.

FastAPI

from fastapi import [1], UploadFile, File

app = [2]()

@app.post("/upload")
async def upload(files: list[UploadFile] = File(...)):
    return {file.filename: await file.read() for file in [3]

Drag options to blanks, or click blank then click option'

AFastAPI

Bapp

Cfiles

DRequest

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'app' instead of 'FastAPI' in import

Using 'app' instead of 'FastAPI()' to create the app

Using wrong variable name instead of 'files' in the comprehension

Import FastAPI, create the app with FastAPI(), and iterate over files in the endpoint.