FastAPI - File HandlingHow do you define a FastAPI POST endpoint that accepts multiple files under the parameter name 'documents'?Aasync def upload(documents: List[UploadFile] = File(...))Basync def upload(documents: UploadFile)Casync def upload(documents: List[bytes])Dasync def upload(documents: List[str])Check Answer
Step-by-Step SolutionSolution:Step 1: Use List[UploadFile]To accept multiple files, the parameter type must be a list of UploadFile objects.Step 2: Use File(...) dependencyFile(...) is required to tell FastAPI to expect files in the request.Final Answer:async def upload(documents: List[UploadFile] = File(...)) -> Option AQuick Check:List with File(...) is mandatory for multiple files [OK]Quick Trick: Use List[UploadFile] with File(...) for multiple files [OK]Common Mistakes:MISTAKESOmitting File(...) when using List[UploadFile]Using UploadFile without List for multiple filesUsing List[str] or List[bytes] instead of UploadFile
Master "File Handling" in FastAPI9 interactive learning modes - each teaches the same concept differentlyLearnWhyDeepVisualTryChallengeProjectRecallPerf
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