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FastAPIframework~10 mins

File validation (size, type) in FastAPI - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to import the FastAPI class.

FastAPI
from fastapi import [1]
app = [1]()
Drag options to blanks, or click blank then click option'
AFastAPI
BFile
CRequest
DUploadFile
Attempts:
3 left
💡 Hint
Common Mistakes
Importing UploadFile instead of FastAPI
Using Request instead of FastAPI
2fill in blank
medium

Complete the code to accept a file upload in the endpoint.

FastAPI
@app.post('/upload')
async def upload_file(file: [1]):
    return {'filename': file.filename}
Drag options to blanks, or click blank then click option'
Astr
BUploadFile
CFile
Dbytes
Attempts:
3 left
💡 Hint
Common Mistakes
Using str or bytes instead of UploadFile
Using File as a type instead of UploadFile
3fill in blank
hard

Fix the error in the code to limit file size to 1MB.

FastAPI
from fastapi import File, UploadFile

@app.post('/upload')
async def upload_file(file: UploadFile = File(..., [1]=1048576)):
    return {'filename': file.filename}
Drag options to blanks, or click blank then click option'
Amax_file_size
Bmax_length
Cmax_size
Dmax_bytes
Attempts:
3 left
💡 Hint
Common Mistakes
Using max_length or max_file_size which are invalid
Using max_bytes which is not recognized
4fill in blank
hard

Fill both blanks to check the uploaded file's content type and reject if not an image.

FastAPI
from fastapi import HTTPException

@app.post('/upload')
async def upload_file(file: UploadFile):
    if file.content_type != [1]:
        raise HTTPException(status_code=400, detail=[2])
    return {'filename': file.filename}
Drag options to blanks, or click blank then click option'
A'image/png'
B'Invalid file type'
C'application/pdf'
D'File type not allowed'
Attempts:
3 left
💡 Hint
Common Mistakes
Checking for wrong content type like 'application/pdf'
Using incorrect error messages
5fill in blank
hard

Fill all three blanks to create a file validation that accepts only JPEG images under 2MB.

FastAPI
from fastapi import File, UploadFile, HTTPException

@app.post('/upload')
async def upload_file(file: UploadFile = File(..., [1]=2097152)):
    if file.content_type != [2]:
        raise HTTPException(status_code=400, detail=[3])
    return {'filename': file.filename}
Drag options to blanks, or click blank then click option'
Amax_size
B'image/jpeg'
C'Only JPEG images under 2MB are allowed'
D'image/png'
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong max_size parameter
Checking for 'image/png' instead of 'image/jpeg'
Incorrect error messages

Practice

(1/5)
1. What is the main purpose of validating file size and type in a FastAPI upload endpoint?
easy
A. To ensure only allowed file types and sizes are accepted for security and performance
B. To automatically convert files to a specific format
C. To speed up the file upload process by skipping checks
D. To store files directly in the database without validation

Solution

  1. Step 1: Understand file validation purpose

    File validation ensures that only files meeting size and type rules are accepted.
  2. Step 2: Recognize security and performance reasons

    Validating prevents harmful files and avoids server overload from large files.
  3. Final Answer:

    To ensure only allowed file types and sizes are accepted for security and performance -> Option A
  4. Quick Check:

    File validation = security and performance [OK]
Hint: File validation protects server and users from bad files [OK]
Common Mistakes:
  • Thinking validation changes file content
  • Assuming validation speeds upload without checks
  • Ignoring security risks of unvalidated files
2. Which of the following is the correct way to declare a file upload parameter in a FastAPI endpoint to accept files asynchronously?
easy
A. def upload(file: UploadFile = File(...)):
B. def upload(file: str):
C. def upload(file: bytes):
D. def upload(file: int):

Solution

  1. Step 1: Identify FastAPI file upload type

    FastAPI uses UploadFile with File(...) to handle async file uploads.
  2. Step 2: Check parameter types

    Only UploadFile supports async file handling, bytes or str do not.
  3. Final Answer:

    def upload(file: UploadFile = File(...)): -> Option A
  4. Quick Check:

    UploadFile + File(...) = async file upload [OK]
Hint: Use UploadFile with File(...) for async uploads [OK]
Common Mistakes:
  • Using bytes or str instead of UploadFile
  • Missing File(...) dependency
  • Using int type for file parameter
3. Given this FastAPI code snippet, what will happen if a user uploads a 5MB PNG file?
from fastapi import FastAPI, File, UploadFile, HTTPException

app = FastAPI()

@app.post('/upload')
async def upload(file: UploadFile = File(...)):
    if file.content_type not in ['image/png', 'image/jpeg']:
        raise HTTPException(status_code=400, detail='Invalid file type')
    contents = await file.read()
    if len(contents) > 2_000_000:
        raise HTTPException(status_code=400, detail='File too large')
    return {'filename': file.filename, 'size': len(contents)}
medium
A. Returns filename and size successfully
B. Raises HTTPException with 'File too large'
C. Raises HTTPException with 'Invalid file type'
D. Raises a syntax error

Solution

  1. Step 1: Check file type condition

    The file is PNG, which is allowed, so no error here.
  2. Step 2: Check file size condition

    The file size is 5MB (5,000,000 bytes), exceeding 2,000,000 limit, so it raises 'File too large'.
  3. Final Answer:

    Raises HTTPException with 'File too large' -> Option B
  4. Quick Check:

    File size > 2MB = 'File too large' error [OK]
Hint: Check size limit after reading file contents [OK]
Common Mistakes:
  • Confusing file type error with size error
  • Not reading file contents before size check
  • Assuming no error for large files
4. Identify the error in this FastAPI file validation code:
from fastapi import FastAPI, File, UploadFile, HTTPException

app = FastAPI()

@app.post('/upload')
async def upload(file: UploadFile = File(...)):
    if file.content_type != 'image/png' or file.content_type != 'image/jpeg':
        raise HTTPException(status_code=400, detail='Invalid file type')
    contents = await file.read()
    if len(contents) > 1_000_000:
        raise HTTPException(status_code=400, detail='File too large')
    return {'filename': file.filename}
medium
A. The file size check uses wrong comparison operator
B. UploadFile should not be used with File(...)
C. The file type condition always raises error due to incorrect logic
D. Missing await keyword before file.read()

Solution

  1. Step 1: Analyze file type condition logic

    The condition uses 'or' with != checks, so it is always true (a file can't be both types).
  2. Step 2: Understand consequence of condition

    This causes the error to always raise, rejecting all files incorrectly.
  3. Final Answer:

    The file type condition always raises error due to incorrect logic -> Option C
  4. Quick Check:

    Incorrect 'or' with != always true = logic error [OK]
Hint: Use 'and' when checking multiple 'not equals' conditions [OK]
Common Mistakes:
  • Using 'or' instead of 'and' in file type checks
  • Forgetting to await file.read()
  • Misunderstanding UploadFile usage
5. You want to create a FastAPI endpoint that accepts only PDF files smaller than 3MB. Which code snippet correctly implements this validation?
hard
A. async def upload(file: UploadFile = File(...)): contents = await file.read() if file.content_type == 'application/pdf' or len(contents) < 3_000_000: return {'filename': file.filename} raise HTTPException(400, 'Invalid file')
B. async def upload(file: UploadFile = File(...)): if file.content_type == 'application/pdf' or len(await file.read()) < 3_000_000: return {'filename': file.filename} raise HTTPException(400, 'Invalid file')
C. async def upload(file: UploadFile = File(...)): if file.content_type == 'application/pdf' or len(await file.read()) > 3_000_000: raise HTTPException(400, 'Invalid file') return {'filename': file.filename}
D. async def upload(file: UploadFile = File(...)): if file.content_type != 'application/pdf': raise HTTPException(400, 'Invalid type') contents = await file.read() if len(contents) > 3_000_000: raise HTTPException(400, 'Too large') return {'filename': file.filename}

Solution

  1. Step 1: Check file type validation

    Correct snippet uses != 'application/pdf' to reject invalid types before reading contents. Distractors misuse operators like 'or' instead of 'and' or check type after reading.
  2. Step 2: Check file size validation

    After type approval, read contents once and raise if len > 3_000_000. Combined conditions fail due to incorrect logic.
  3. Final Answer:

    Separate type (!=) and size (> 3MB) checks -> Option D
  4. Quick Check:

    != type reject + read then > size reject [OK]
Hint: Check type and size separately with correct logic [OK]
Common Mistakes:
  • Using 'or' instead of 'and' in conditions
  • Reading file multiple times causing empty content
  • Incorrect comparison operators in conditions