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DSA Typescriptprogramming~10 mins

Tree Traversal Postorder Left Right Root in DSA Typescript - Execution Trace

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Concept Flow - Tree Traversal Postorder Left Right Root
Start at root node
Traverse left subtree
Traverse right subtree
Visit current node (root)
Back to parent node or end if root
Postorder traversal visits left subtree first, then right subtree, and finally the root node.
Execution Sample
DSA Typescript
function postorder(node) {
  if (!node) return;
  postorder(node.left);
  postorder(node.right);
  console.log(node.value);
}
This code visits nodes in postorder: left child, right child, then the node itself.
Execution Table
StepOperationNode VisitedActionTree State (Visited Nodes)
1Start at rootATraverse left subtree[]
2Traverse left subtreeBTraverse left subtree[]
3Traverse left subtreeDTraverse left subtree[]
4Traverse left subtreenullReturn (no node)[]
5Traverse right subtreenullReturn (no node)[]
6Visit nodeDPrint D[D]
7Traverse right subtreeETraverse left subtree[D]
8Traverse left subtreenullReturn (no node)[D]
9Traverse right subtreenullReturn (no node)[D]
10Visit nodeEPrint E[D, E]
11Visit nodeBPrint B[D, E, B]
12Traverse right subtreeCTraverse left subtree[D, E, B]
13Traverse left subtreeFTraverse left subtree[D, E, B]
14Traverse left subtreenullReturn (no node)[D, E, B]
15Traverse right subtreenullReturn (no node)[D, E, B]
16Visit nodeFPrint F[D, E, B, F]
17Traverse right subtreeGTraverse left subtree[D, E, B, F]
18Traverse left subtreenullReturn (no node)[D, E, B, F]
19Traverse right subtreenullReturn (no node)[D, E, B, F]
20Visit nodeGPrint G[D, E, B, F, G]
21Visit nodeCPrint C[D, E, B, F, G, C]
22Visit nodeAPrint A[D, E, B, F, G, C, A]
23EndnullTraversal complete[D, E, B, F, G, C, A]
💡 Traversal ends after visiting root node A and printing all nodes in postorder.
Variable Tracker
VariableStartAfter Step 6After Step 11After Step 16After Step 21Final
Current NodeADBFCnull
Visited Nodes[][D][D, E, B][D, E, B, F][D, E, B, F, G, C][D, E, B, F, G, C, A]
Call Stack Depth132320
Key Moments - 3 Insights
Why do we visit the current node only after traversing left and right subtrees?
Because postorder means Left, Right, Root order. The execution_table rows 6, 11, 16, 20, 21, and 22 show the node is printed only after both subtrees are fully traversed.
What happens when a node has no left or right child?
The traversal returns immediately (rows 4, 5, 8, 9, 14, 15, 18, 19) without printing, ensuring leaf nodes are visited correctly.
How does the call stack depth change during traversal?
It increases when going deeper into left/right children and decreases after visiting nodes, as shown in variable_tracker under Call Stack Depth.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what nodes have been visited after step 11?
A[D, E]
B[D]
C[D, E, B]
D[D, E, B, F]
💡 Hint
Check the 'Tree State (Visited Nodes)' column at step 11 in execution_table.
At which step does the traversal visit node 'C'?
AStep 21
BStep 20
CStep 22
DStep 16
💡 Hint
Look for 'Visit node' operation with node 'C' in execution_table.
If node 'B' had no right child, how would the visited nodes list change after step 11?
A[D, B, E]
B[D, B]
C[D, E, B]
D[B]
💡 Hint
Without right child 'E', node 'B' visits only left child 'D' before itself, see execution_table pattern.
Concept Snapshot
Postorder traversal visits nodes in Left → Right → Root order.
Use recursion: traverse left subtree, then right subtree, then visit node.
Useful for deleting trees or evaluating expression trees.
Print or process node only after children are done.
Handles empty (null) nodes by returning immediately.
Full Transcript
Postorder tree traversal means visiting the left subtree first, then the right subtree, and finally the root node. The code recursively calls itself on the left child, then the right child, and prints the node's value last. The execution table shows each step visiting nodes D, E, B, F, G, C, and finally A in that order. When a node is null, the function returns immediately without printing. The call stack grows as recursion goes deeper and shrinks as nodes are visited. This traversal is useful when you need to process children before their parent, such as deleting nodes or evaluating expressions.