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Maximum Path Sum in Binary Tree in DSA Typescript - Practice Problems & Challenges

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Challenge - 5 Problems
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Maximum Path Sum Master
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❓ Predict Output
intermediate
2:00remaining
Output of Maximum Path Sum Calculation
What is the output of the following TypeScript code that calculates the maximum path sum in a binary tree?
DSA Typescript
class TreeNode {
  val: number;
  left: TreeNode | null;
  right: TreeNode | null;
  constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
    this.val = val === undefined ? 0 : val;
    this.left = left === undefined ? null : left;
    this.right = right === undefined ? null : right;
  }
}

function maxPathSum(root: TreeNode | null): number {
  let maxSum = -Infinity;
  function dfs(node: TreeNode | null): number {
    if (!node) return 0;
    const left = Math.max(dfs(node.left), 0);
    const right = Math.max(dfs(node.right), 0);
    maxSum = Math.max(maxSum, node.val + left + right);
    return node.val + Math.max(left, right);
  }
  dfs(root);
  return maxSum;
}

const tree = new TreeNode(-10,
  new TreeNode(9),
  new TreeNode(20, new TreeNode(15), new TreeNode(7))
);
console.log(maxPathSum(tree));
A27
B35
C42
D20
Attempts:
2 left
💡 Hint
Consider the path that includes the root's right subtree and its children.
🧠 Conceptual
intermediate
1:30remaining
Understanding Maximum Path Sum Concept
Which statement best describes the maximum path sum in a binary tree?
AIt is the largest sum of values from any path between two nodes, which may or may not include the root.
BIt is the sum of all node values in the tree.
CIt is the largest sum of values from any path starting at the root and ending at a leaf.
DIt is the largest sum of values from any path that must include the root node.
Attempts:
2 left
💡 Hint
Think about paths that can start and end anywhere in the tree.
🔧 Debug
advanced
2:00remaining
Identify the Error in Maximum Path Sum Code
What error will the following TypeScript code produce when calculating maximum path sum?
DSA Typescript
function maxPathSum(root: TreeNode | null): number {
  let maxSum = -Infinity;
  function dfs(node: TreeNode | null): number {
    if (!node) return 0;
    const left = dfs(node.left);
    const right = dfs(node.right);
    maxSum = Math.max(maxSum, node.val + left + right);
    return node.val + Math.max(left, right);
  }
  dfs(root);
  return maxSum;
}

const tree = new TreeNode(1, new TreeNode(-2), new TreeNode(3));
console.log(maxPathSum(tree));
AReturns 0
BReturns 4
CReturns 1
DReturns 3
Attempts:
2 left
💡 Hint
Check how negative values affect the path sums.
❓ Predict Output
advanced
1:30remaining
Output of Maximum Path Sum with Negative Nodes
What is the output of this TypeScript code calculating maximum path sum in a tree with negative values?
DSA Typescript
class TreeNode {
  val: number;
  left: TreeNode | null;
  right: TreeNode | null;
  constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
    this.val = val === undefined ? 0 : val;
    this.left = left === undefined ? null : left;
    this.right = right === undefined ? null : right;
  }
}

function maxPathSum(root: TreeNode | null): number {
  let maxSum = -Infinity;
  function dfs(node: TreeNode | null): number {
    if (!node) return 0;
    const left = Math.max(dfs(node.left), 0);
    const right = Math.max(dfs(node.right), 0);
    maxSum = Math.max(maxSum, node.val + left + right);
    return node.val + Math.max(left, right);
  }
  dfs(root);
  return maxSum;
}

const tree = new TreeNode(-3);
console.log(maxPathSum(tree));
A-Infinity
B0
C3
D-3
Attempts:
2 left
💡 Hint
Consider that the tree has only one node with a negative value.
🧠 Conceptual
expert
1:30remaining
Why Use Math.max with 0 in Maximum Path Sum DFS?
Why does the maximum path sum algorithm use Math.max(dfs(child), 0) when calculating left and right gains?
ATo ignore negative path sums from children that would reduce the total sum.
BTo ensure the path always includes both children.
CTo convert all negative values to zero permanently in the tree.
DTo count only leaf nodes in the path sum calculation.
Attempts:
2 left
💡 Hint
Think about how negative values affect the sum of a path.

Practice

(1/5)
1. What does the "Maximum Path Sum in Binary Tree" problem ask you to find?
easy
A. The highest sum of node values along any path in the tree
B. The longest path length in the tree
C. The sum of all node values in the tree
D. The minimum value node in the tree

Solution

  1. Step 1: Understand the problem goal

    The problem asks for the maximum sum of values along any path in the binary tree, where a path can start and end at any nodes.
  2. Step 2: Differentiate from other tree sums

    This is different from longest path or total sum; it focuses on the maximum sum achievable on any path.
  3. Final Answer:

    The highest sum of node values along any path in the tree -> Option A
  4. Quick Check:

    Maximum path sum = highest node value sum [OK]
Hint: Focus on sums along paths, not lengths or totals [OK]
Common Mistakes:
  • Confusing path sum with longest path length
  • Summing all nodes instead of a path
  • Looking for minimum instead of maximum
2. Which TypeScript function signature correctly represents a function to find maximum path sum in a binary tree node?
easy
A. function maxPathSum(root: number[]): number
B. function maxPathSum(root: TreeNode | null): number
C. function maxPathSum(root: string): string
D. function maxPathSum(root: TreeNode): void

Solution

  1. Step 1: Identify correct parameter type

    The function should accept a binary tree node or null, so TreeNode | null is correct.
  2. Step 2: Identify correct return type

    The function returns a number representing the maximum path sum, so return type is number.
  3. Final Answer:

    function maxPathSum(root: TreeNode | null): number -> Option B
  4. Quick Check:

    Input: TreeNode or null, Output: number [OK]
Hint: Function input is tree node or null, output is number [OK]
Common Mistakes:
  • Using array or string instead of TreeNode
  • Returning void instead of number
  • Not allowing null as input
3. Given the following TypeScript code, what is the output?
class TreeNode {
  val: number;
  left: TreeNode | null;
  right: TreeNode | null;
  constructor(val: number, left: TreeNode | null = null, right: TreeNode | null = null) {
    this.val = val;
    this.left = left;
    this.right = right;
  }
}

function maxPathSum(root: TreeNode | null): number {
  let maxSum = -Infinity;
  function helper(node: TreeNode | null): number {
    if (!node) return 0;
    const left = Math.max(helper(node.left), 0);
    const right = Math.max(helper(node.right), 0);
    maxSum = Math.max(maxSum, node.val + left + right);
    return node.val + Math.max(left, right);
  }
  helper(root);
  return maxSum;
}

const tree = new TreeNode(1, new TreeNode(2), new TreeNode(3));
console.log(maxPathSum(tree));
medium
A. 3
B. 5
C. 1
D. 6

Solution

  1. Step 1: Calculate max path sums for each node

    Node 2 and 3 have no children, so max path sums are 2 and 3. For root 1, left=2, right=3, total=1+2+3=6.
  2. Step 2: Determine maximum path sum

    Maximum path sum is max of all nodes' sums: max(2,3,6) = 6.
  3. Final Answer:

    6 -> Option D
  4. Quick Check:

    Sum(1+2+3) = 6 [OK]
Hint: Sum node + max left + max right, ignore negatives [OK]
Common Mistakes:
  • Ignoring zero floor for negative sums
  • Returning sum of only root and one child
  • Confusing return value with maxSum variable
4. Identify the bug in this TypeScript function for maximum path sum:
function maxPathSum(root: TreeNode | null): number {
  let maxSum = 0;
  function helper(node: TreeNode | null): number {
    if (!node) return 0;
    const left = helper(node.left);
    const right = helper(node.right);
    maxSum = Math.max(maxSum, node.val + left + right);
    return node.val + Math.max(left, right);
  }
  helper(root);
  return maxSum;
}
medium
A. Returns node.val + min(left, right) instead of max
B. helper function missing base case
C. maxSum initialized to 0 instead of -Infinity
D. Does not call helper on root

Solution

  1. Step 1: Check maxSum initialization

    maxSum initialized to 0 can cause wrong result if all node values are negative.
  2. Step 2: Correct initialization for negative values

    Initialize maxSum to -Infinity to handle negative node values correctly.
  3. Final Answer:

    maxSum initialized to 0 instead of -Infinity -> Option C
  4. Quick Check:

    maxSum must start at -Infinity for negative nodes [OK]
Hint: Initialize maxSum to -Infinity to handle negatives [OK]
Common Mistakes:
  • Starting maxSum at 0 causes wrong max for negative trees
  • Forgetting base case returns 0
  • Using min instead of max for return
5. Given a binary tree with nodes: root= -10, left=9, right=20, right.left=15, right.right=7, what is the maximum path sum?
hard
A. 42
B. 35
C. 27
D. 20

Solution

  1. Step 1: Calculate max path sums for subtrees

    Right subtree max path: 15 + 20 + 7 = 42. Left subtree max is 9. Root is -10.
  2. Step 2: Determine overall max path sum

    Max path sum is max of 42 (right subtree path), 9 (left), and paths including root. The max is 42.
  3. Final Answer:

    42 -> Option A
  4. Quick Check:

    Sum(15+20+7) = 42 [OK]
Hint: Check all subtree sums including root, pick max [OK]
Common Mistakes:
  • Ignoring path through both children and root
  • Choosing sum of root and one child only
  • Not considering negative root value impact
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