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DSA Typescriptprogramming~10 mins

Heap Insert Operation Bubble Up in DSA Typescript - Execution Trace

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Concept Flow - Heap Insert Operation Bubble Up
Add new element at end of array
Compare new element with parent
Swap with parent
Move pointer to parent
Back to Compare
Insert element at the end, then compare and swap with parent until heap property is restored.
Execution Sample
DSA Typescript
heap = [10, 15, 30, 40, 50, 100, 40]
insert(8)
// Bubble up to restore heap
Insert 8 into min-heap and bubble it up to maintain heap order.
Execution Table
StepOperationArray StatePointer (index)ActionVisual State
1Insert 8 at end[10, 15, 30, 40, 50, 100, 40, 8]7 (new element)Add 8 at index 7Array: [10, 15, 30, 40, 50, 100, 40, 8]
2Compare with parent[10, 15, 30, 40, 50, 100, 40, 8]7 (8) vs 3 (40)8 < 40 → SwapSwap index 7 and 3
3After swap[10, 15, 30, 8, 50, 100, 40, 40]3 (8)Move pointer to 3Array: [10, 15, 30, 8, 50, 100, 40, 40]
4Compare with parent[10, 15, 30, 8, 50, 100, 40, 40]3 (8) vs 1 (15)8 < 15 → SwapSwap index 3 and 1
5After swap[10, 8, 30, 15, 50, 100, 40, 40]1 (8)Move pointer to 1Array: [10, 8, 30, 15, 50, 100, 40, 40]
6Compare with parent[10, 8, 30, 15, 50, 100, 40, 40]1 (8) vs 0 (10)8 < 10 → SwapSwap index 1 and 0
7After swap[8, 10, 30, 15, 50, 100, 40, 40]0 (8)Move pointer to 0Array: [8, 10, 30, 15, 50, 100, 40, 40]
8Compare with parent[8, 10, 30, 15, 50, 100, 40, 40]0 (8) has no parentStop bubbling upHeap property restored
💡 Pointer reached root (index 0), no parent to compare, bubble up stops.
Variable Tracker
VariableStartAfter Step 1After Step 3After Step 5After Step 7Final
heap array[10, 15, 30, 40, 50, 100, 40][10, 15, 30, 40, 50, 100, 40, 8][10, 15, 30, 8, 50, 100, 40, 40][10, 8, 30, 15, 50, 100, 40, 40][8, 10, 30, 15, 50, 100, 40, 40][8, 10, 30, 15, 50, 100, 40, 40]
pointer indexN/A73100
pointer valueN/A88888
Key Moments - 3 Insights
Why do we compare the new element with its parent during bubble up?
Because the heap property depends on parent-child order. We check if the new element is smaller than its parent to decide if swapping is needed (see execution_table steps 2, 4, 6).
What happens when the pointer reaches the root during bubble up?
There is no parent to compare with, so the bubble up stops (see execution_table step 8). This means the heap property is restored.
Why do we swap elements during bubble up instead of just inserting at the end?
Inserting at the end may break the heap order. Swapping with parents moves the new element up to restore the heap property (see execution_table steps 2, 4, 6).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, what is the heap array after step 5?
A[10, 8, 30, 15, 50, 100, 40, 40]
B[10, 15, 30, 8, 50, 100, 40, 40]
C[8, 10, 30, 15, 50, 100, 40, 40]
D[10, 15, 30, 40, 50, 100, 40, 8]
💡 Hint
Check the 'Array State' column at step 5 in the execution_table.
At which step does the pointer reach the root and stop bubbling up?
AStep 6
BStep 8
CStep 7
DStep 5
💡 Hint
Look for the step where the pointer index is 0 and no parent exists in execution_table.
If the inserted element was 50 instead of 8, how would the bubble up process change?
AIt would bubble up to the root.
BIt would swap once with the parent.
CNo swaps would happen; insertion stops immediately.
DIt would cause an error.
💡 Hint
Refer to the comparison logic in execution_table steps 2, 4, 6 where swaps happen only if new element is less than parent.
Concept Snapshot
Heap Insert Bubble Up:
- Insert new element at array end
- Compare with parent node
- If new < parent, swap
- Move pointer to parent
- Repeat until root or no swap needed
- Restores heap property efficiently
Full Transcript
This visual trace shows how inserting a new element into a min-heap works by adding it at the end of the array and then bubbling it up. The bubble up compares the new element with its parent and swaps if the new element is smaller. This process repeats until the new element reaches the root or no swap is needed, restoring the heap property. The execution table tracks each step, showing array states and pointer movements. Key moments clarify why comparisons and swaps happen and when the process stops. The quiz tests understanding of array states and stopping conditions.