Autocomplete System with Trie in DSA Typescript - Time & Space Complexity
We want to understand how fast an autocomplete system using a trie can find suggestions.
The question is: how does the time to find words grow as we add more words or type longer prefixes?
Analyze the time complexity of the following code snippet.
class TrieNode {
children: Map = new Map();
isWord: boolean = false;
}
function searchPrefix(root: TrieNode, prefix: string): TrieNode | null {
let node = root;
for (const char of prefix) {
if (!node.children.has(char)) return null;
node = node.children.get(char)!;
}
return node;
}
This code finds the node in the trie that matches the given prefix, if it exists.
- Primary operation: Looping over each character in the prefix string.
- How many times: Exactly once per character in the prefix (length m).
As the prefix length grows, the search takes longer, but it does not depend on the total number of words stored.
| Input Size (prefix length m) | Approx. Operations |
|---|---|
| 10 | About 10 steps |
| 100 | About 100 steps |
| 1000 | About 1000 steps |
Pattern observation: The time grows linearly with the prefix length, not with the number of stored words.
Time Complexity: O(m)
This means the search time grows only with how long the prefix is, regardless of how many words are stored.
[X] Wrong: "The search time depends on the total number of words stored in the trie."
[OK] Correct: The search only follows the prefix characters, so it depends on prefix length, not total words.
Understanding this helps you explain why tries are efficient for autocomplete, showing you know how data structure choice affects speed.
"What if we also count the time to collect all words under the prefix node? How would the time complexity change?"
Practice
Trie in an autocomplete system?Solution
Step 1: Understand the role of Trie in prefix search
A Trie is a tree-like data structure designed to store strings by their prefixes, allowing fast prefix-based searches.Step 2: Connect Trie usage to autocomplete
Autocomplete requires quick lookup of words starting with a given prefix, which Trie supports efficiently.Final Answer:
To efficiently store and search prefixes of words -> Option AQuick Check:
Trie = prefix search [OK]
- Confusing Trie with sorting algorithms
- Thinking Trie encrypts data
- Assuming Trie counts word frequency only
Solution
Step 1: Identify correct data type for children
Children should map characters (string) to TrieNode objects, so Map is correct.Step 2: Check initialization and isEnd flag
Children initialized as new Map(), and isEnd defaults to false indicating not end of word initially.Final Answer:
class TrieNode { children: Map = new Map(); isEnd: boolean = false; } -> Option BQuick Check:
Map for children [OK]
- Using array instead of Map for children
- Using number keys instead of string keys
- Setting isEnd to true by default
autocomplete.getSuggestions('ca')?
class TrieNode {
children: Map = new Map();
isEnd: boolean = false;
}
class AutocompleteSystem {
root: TrieNode = new TrieNode();
insert(word: string) {
let node = this.root;
for (const char of word) {
if (!node.children.has(char)) {
node.children.set(char, new TrieNode());
}
node = node.children.get(char)!;
}
node.isEnd = true;
}
getSuggestions(prefix: string): string[] {
let node = this.root;
for (const char of prefix) {
if (!node.children.has(char)) return [];
node = node.children.get(char)!;
}
const results: string[] = [];
const dfs = (currNode: TrieNode, path: string) => {
if (currNode.isEnd) results.push(path);
for (const [ch, nextNode] of currNode.children) {
dfs(nextNode, path + ch);
}
};
dfs(node, prefix);
return results;
}
}
const autocomplete = new AutocompleteSystem();
autocomplete.insert('cat');
autocomplete.insert('car');
autocomplete.insert('cap');
autocomplete.insert('dog');
console.log(autocomplete.getSuggestions('ca'));Solution
Step 1: Insert words and traverse prefix 'ca'
Words 'cat', 'car', 'cap' are inserted. Searching prefix 'ca' finds node with children 't', 'r', 'p'.Step 2: DFS collects all words starting with 'ca'
DFS from 'ca' node collects 'cat', 'car', and 'cap' as all end nodes under that prefix.Final Answer:
["cat", "car", "cap"] -> Option DQuick Check:
Prefix 'ca' matches cat, car, cap [OK]
- Returning empty list if prefix found
- Returning unrelated words like 'dog'
- Missing one or more words starting with prefix
insert method in a Trie has a bug. What is the bug?
insert(word: string) {
let node = this.root;
for (const char of word) {
if (!node.children.has(char)) {
node.children.set(char, new TrieNode());
}
node = node.children.get(char);
}
node.isEnd = true;
}Solution
Step 1: Identify potential null or undefined access
node.children.get(char) can return undefined if key missing, so TypeScript requires non-null assertion or check.Step 2: Fix by adding non-null assertion operator
Adding '!' after get(char) tells TypeScript the value is not undefined, fixing the bug.Final Answer:
Missing non-null assertion operator (!) when getting child node -> Option AQuick Check:
Use get(char)! to avoid undefined [OK]
- Ignoring TypeScript undefined error
- Changing data structure unnecessarily
- Setting isEnd incorrectly
Solution
Step 1: Understand frequency tracking in Trie
Adding a frequency count to nodes marking word ends allows tracking how often each word was inserted.Step 2: Use frequency to sort suggestions efficiently
During DFS for suggestions, use frequency counts to sort or prioritize words without extra data structures.Final Answer:
Add a frequency count field to each Trie node marking end of word -> Option CQuick Check:
Frequency field in Trie nodes enables sorting [OK]
- Sorting all words on each query (slow)
- Replacing Trie with BST loses prefix efficiency
- Removing isEnd loses word boundary info
Ready to prove it?
Pass the test and this pattern moves unknown
