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DSA Rustprogramming~10 mins

Why Strings Are a Data Structure Not Just Text in DSA Rust - Test Your Knowledge

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a new empty String in Rust.

DSA Rust
let mut s = String::[1]();
Drag options to blanks, or click blank then click option'
Anew
Bfrom
Cpush
Dlen
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'from' instead of 'new' creates a String from a value, not empty.
Using 'push' is for adding characters, not creating a String.
2fill in blank
medium

Complete the code to add the text "hello" to the String variable s.

DSA Rust
s.[1]("hello");
Drag options to blanks, or click blank then click option'
Apop
Bpush_str
Cclear
Dlen
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'pop' removes the last character instead of adding.
Using 'len' returns length, not modifies the String.
3fill in blank
hard

Fix the error in the code to convert a &str to a String.

DSA Rust
let s = "hello".[1]();
Drag options to blanks, or click blank then click option'
Alen
Bpush_str
Cto_string
Dclear
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'push_str' on a &str causes error because it's a method for String.
Using 'len' returns length, not converts.
4fill in blank
hard

Fill both blanks to create a String from a &str and then get its length.

DSA Rust
let s = String::[1]("hello");
let length = s.[2]();
Drag options to blanks, or click blank then click option'
Afrom
Blen
Cnew
Dpush_str
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'new' instead of 'from' does not create from &str.
Using 'push_str' instead of 'len' does not get length.
5fill in blank
hard

Fill all three blanks to create a String, append text, and print it.

DSA Rust
let mut s = String::[1]();
s.[2](" world");
println!("{}", s[3]);
Drag options to blanks, or click blank then click option'
Anew
Bpush_str
C.as_str()
D.len()
Attempts:
3 left
💡 Hint
Common Mistakes
Using '.len()' in print shows length, not content.
Forgetting to make String mutable before push_str.

Practice

(1/5)
1. Why are strings considered a data structure and not just plain text in Rust?
easy
A. Because strings cannot be changed once created
B. Because strings are only used for printing text
C. Because strings store characters in a sequence with indexing and length properties
D. Because strings are always fixed size arrays

Solution

  1. Step 1: Understand what a data structure is

    A data structure organizes data to allow operations like indexing, length checking, and iteration.
  2. Step 2: Analyze string properties in Rust

    Rust strings store characters in order, support length queries, and allow access to parts, so they behave like a data structure.
  3. Final Answer:

    Because strings store characters in a sequence with indexing and length properties -> Option C
  4. Quick Check:

    Strings = Data structure [OK]
Hint: Strings hold ordered characters with length and indexing [OK]
Common Mistakes:
  • Thinking strings are just plain text without structure
  • Assuming strings are immutable fixed arrays
  • Confusing strings with single characters
2. Which of the following is the correct way to create a mutable String in Rust?
easy
A. let mut s = String::new();
B. let s = 'hello';
C. let s = String::new();
D. let s = String::from("hello");

Solution

  1. Step 1: Identify mutable string creation syntax

    In Rust, to create a mutable String, you declare it with mut and initialize with String::new() or String::from().
  2. Step 2: Verify the correct syntax

    The correct way is let mut s = String::new();, which creates an empty mutable String. Without mut the String is immutable. Single quotes denote characters, not strings, and String::from() requires a string slice like "hello".
  3. Final Answer:

    let mut s = String::new(); -> Option A
  4. Quick Check:

    Mutable String = let mut s = String::new(); [OK]
Hint: Use 'mut' keyword to make String mutable [OK]
Common Mistakes:
  • Forgetting 'mut' keyword for mutability
  • Using single quotes for strings instead of double quotes
  • Confusing &str with String type
3. What will be the output of this Rust code?
let mut s = String::from("hello");
s.push_str(", world!");
println!("{}", s);
medium
A. "hello"
B. "hello, world!"
C. Compilation error
D. "hello world"

Solution

  1. Step 1: Understand push_str method

    The push_str method appends a string slice to the existing String.
  2. Step 2: Trace the code execution

    Initially, s = "hello". After s.push_str(", world!"), s becomes "hello, world!". The print statement outputs this full string.
  3. Final Answer:

    "hello, world!" -> Option B
  4. Quick Check:

    push_str appends text = "hello, world!" [OK]
Hint: push_str adds text to String, so output includes appended text [OK]
Common Mistakes:
  • Expecting original string without appended text
  • Confusing push_str with push (which adds single char)
  • Thinking code causes compile error
4. Identify the error in this Rust code snippet:
let s = String::from("hello");
s.push('!');
medium
A. Cannot push a character to an immutable String
B. push method does not exist for String
C. Missing semicolon after push
D. String::from cannot create a String

Solution

  1. Step 1: Check mutability of String

    The variable s is declared without mut, so it is immutable.
  2. Step 2: Understand push method requirements

    The push method modifies the String by adding a character, which requires the String to be mutable.
  3. Final Answer:

    Cannot push a character to an immutable String -> Option A
  4. Quick Check:

    push needs mutable String = error if not mutable [OK]
Hint: Make String mutable with 'mut' before push [OK]
Common Mistakes:
  • Ignoring mut keyword requirement
  • Thinking push is invalid method
  • Assuming missing semicolon causes error
5. Given a String in Rust, how can you efficiently count the number of characters (not bytes) it contains?
hard
A. Use s.capacity() to find character count
B. Use s.len() to get the character count
C. Use s.bytes().count() to count characters
D. Convert to chars iterator and count elements with s.chars().count()

Solution

  1. Step 1: Understand difference between bytes and characters

    Rust strings store UTF-8 bytes; len() returns byte count, not character count.
  2. Step 2: Use chars iterator to count characters

    The chars() method returns an iterator over Unicode scalar values (characters). Counting these gives the correct character count.
  3. Final Answer:

    Convert to chars iterator and count elements with s.chars().count() -> Option D
  4. Quick Check:

    chars().count() = character count [OK]
Hint: Use s.chars().count() for accurate character count [OK]
Common Mistakes:
  • Using s.len() which counts bytes, not characters
  • Using bytes().count() which counts bytes
  • Confusing capacity() with length
Recommended

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10 questions~5 mineasy hard