Bird
Raised Fist0
DSA Rustprogramming~10 mins

Why Queue Exists and What Problems It Solves in DSA Rust - Test Your Knowledge

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to add an element to the end of the queue.

DSA Rust
queue.push_back([1]);
Drag options to blanks, or click blank then click option'
A5
Bfront()
Cpop_front()
Dlen()
Attempts:
3 left
💡 Hint
Common Mistakes
Using pop_front() instead of push_back()
Trying to access front() to add an element
2fill in blank
medium

Complete the code to remove the first element from the queue.

DSA Rust
let first = queue.[1]();
Drag options to blanks, or click blank then click option'
Apush_back
Bpush_front
Cpop_front
Dpop_back
Attempts:
3 left
💡 Hint
Common Mistakes
Using pop_back() which removes from the end
Using push_back() which adds instead of removes
3fill in blank
hard

Fix the error in the code to check if the queue is empty.

DSA Rust
if queue.[1]() { println!("Queue is empty"); }
Drag options to blanks, or click blank then click option'
Ais_empty
Blen
Cfront
Dpop_front
Attempts:
3 left
💡 Hint
Common Mistakes
Using len() which returns a number, not a boolean
Using pop_front() which removes an element
4fill in blank
hard

Fill both blanks to create a queue and add an element to it.

DSA Rust
let mut queue = VecDeque::[1]();
queue.[2](10);
Drag options to blanks, or click blank then click option'
Anew
Bpop_front
Cpush_back
Dwith_capacity
Attempts:
3 left
💡 Hint
Common Mistakes
Using pop_front() to add elements
Using with_capacity() without adding elements
5fill in blank
hard

Fill all three blanks to remove an element and check the queue size.

DSA Rust
if let Some(value) = queue.[1]() {
    println!("Removed: {}", value);
}
let size = queue.[2]();
println!("Queue size: {}", [3]);
Drag options to blanks, or click blank then click option'
Apop_front
Blen
Csize
Dpop_back
Attempts:
3 left
💡 Hint
Common Mistakes
Using pop_back() instead of pop_front()
Using size() method which does not exist
Printing len() call instead of variable

Practice

(1/5)
1. Why do we use a Queue data structure instead of just using a simple list or array?
easy
A. Because a queue allows processing elements in the order they arrive (FIFO).
B. Because a queue stores elements in random order for faster access.
C. Because a queue can only store unique elements.
D. Because a queue automatically sorts elements in ascending order.

Solution

  1. Step 1: Understand the queue behavior

    A queue processes elements in First-In-First-Out (FIFO) order, meaning the first element added is the first to be removed.
  2. Step 2: Compare with other data structures

    Simple lists or arrays do not enforce this order automatically; they allow random access and do not guarantee processing order.
  3. Final Answer:

    Because a queue allows processing elements in the order they arrive (FIFO). -> Option A
  4. Quick Check:

    Queue = FIFO order [OK]
Hint: Queues process items in arrival order (FIFO) [OK]
Common Mistakes:
  • Thinking queues sort elements automatically
  • Assuming queues store only unique items
  • Confusing queue with stack (LIFO)
2. Which of the following is the correct way to add an element to a queue in Rust using the VecDeque type?
easy
A. queue.add(element);
B. queue.push_front(element);
C. queue.insert(0, element);
D. queue.push_back(element);

Solution

  1. Step 1: Recall VecDeque methods for queue operations

    In Rust, VecDeque is used as a queue. To add an element at the end (enqueue), use push_back.
  2. Step 2: Check other options

    push_front adds at the front (not typical enqueue), insert is for vectors but not idiomatic for queues, and add is not a method on VecDeque.
  3. Final Answer:

    queue.push_back(element); -> Option D
  4. Quick Check:

    Enqueue = push_back in VecDeque [OK]
Hint: Use push_back to enqueue in VecDeque [OK]
Common Mistakes:
  • Using push_front to enqueue instead of push_back
  • Trying to use insert method on VecDeque
  • Using non-existent add method
3. What will be the output of the following Rust code using a queue?
use std::collections::VecDeque;

fn main() {
    let mut queue = VecDeque::new();
    queue.push_back(10);
    queue.push_back(20);
    queue.push_back(30);
    let first = queue.pop_front();
    println!("{:?}", queue);
    println!("First removed: {:?}", first);
}
medium
A. [20, 30]\nFirst removed: Some(10)
B. [10, 20, 30]\nFirst removed: None
C. [30, 20]\nFirst removed: Some(10)
D. [20, 30]\nFirst removed: None

Solution

  1. Step 1: Trace queue operations

    Elements 10, 20, 30 are added in order. pop_front() removes the first element (10).
  2. Step 2: Check remaining queue and removed element

    After removal, queue contains 20 and 30. The removed element is Some(10) because pop_front returns an Option.
  3. Final Answer:

    [20, 30] First removed: Some(10) -> Option A
  4. Quick Check:

    pop_front removes first = 10, queue left = [20, 30] [OK]
Hint: pop_front removes first element, queue shrinks from front [OK]
Common Mistakes:
  • Assuming pop_front removes last element
  • Expecting None instead of Some(value) on pop
  • Confusing push_back with push_front
4. The following Rust code tries to implement a queue but has a bug. What is the error?
use std::collections::VecDeque;

fn main() {
    let mut queue = VecDeque::new();
    queue.push_back(1);
    queue.push_back(2);
    let removed = queue.pop_back();
    println!("Queue: {:?}", queue);
    println!("Removed: {:?}", removed);
}
medium
A. The queue is empty before pop_back is called.
B. Using pop_back removes the last element, not the first, breaking FIFO.
C. pop_back returns a boolean, not an Option.
D. VecDeque does not support push_back method.

Solution

  1. Step 1: Understand queue removal operation

    A queue removes elements in FIFO order, so removal should be from the front using pop_front().
  2. Step 2: Identify the bug in code

    The code uses pop_back(), which removes the last element, breaking the FIFO principle.
  3. Final Answer:

    Using pop_back removes the last element, not the first, breaking FIFO. -> Option B
  4. Quick Check:

    Queue removal must be pop_front for FIFO [OK]
Hint: Use pop_front to dequeue, not pop_back [OK]
Common Mistakes:
  • Using pop_back instead of pop_front for queue
  • Thinking pop_back returns boolean
  • Assuming VecDeque lacks push_back
5. You need to process tasks in the order they arrive but also want to peek at the next task without removing it. Which queue operation combination in Rust's VecDeque solves this problem?
hard
A. Use pop_back() to remove and back() to peek the next task.
B. Use push_back() to remove and pop_front() to peek the next task.
C. Use pop_front() to remove and front() to peek the next task.
D. Use push_front() to remove and pop_back() to peek the next task.

Solution

  1. Step 1: Identify correct removal operation for FIFO

    To process tasks in arrival order, remove with pop_front() which removes the first element.
  2. Step 2: Identify correct peek operation

    To peek without removing, use front() which returns a reference to the first element.
  3. Final Answer:

    Use pop_front() to remove and front() to peek the next task. -> Option C
  4. Quick Check:

    Dequeue = pop_front, Peek = front [OK]
Hint: pop_front removes, front() peeks next element [OK]
Common Mistakes:
  • Using pop_back and back() which breaks FIFO
  • Confusing push_back with removal
  • Using push_front incorrectly for removal
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard