Two Pointer Technique on Arrays in DSA Rust - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the Two Pointer Technique on Arrays?

It is a method where two pointers move through the array to solve problems efficiently, often from different ends or at different speeds.

beginner

How do the two pointers typically move in the Two Pointer Technique?

Usually, one pointer starts at the beginning and the other at the end, moving towards each other, or both move forward at different speeds.

intermediate

Why is the Two Pointer Technique efficient compared to nested loops?

Because it reduces time complexity by avoiding repeated scanning, often solving problems in linear time instead of quadratic.

intermediate

Example problem: Find if there are two numbers in a sorted array that add up to a target sum. How does Two Pointer Technique help?

Start one pointer at the start and one at the end. If sum is too big, move the end pointer left; if too small, move the start pointer right. Repeat until found or pointers cross.

beginner

What is a common use case of Two Pointer Technique in arrays?

Removing duplicates, partitioning arrays, checking palindromes, and finding pairs with a given sum.

In the Two Pointer Technique, if the sum of elements at pointers is greater than the target, what should you do?

A Stop the process

B Move the pointer at the start towards the end

C Move both pointers towards the end

D Move the pointer at the end towards the start

If the sum is too big, moving the end pointer left reduces the sum.

Which of these problems is best solved using Two Pointer Technique?

A Finding pairs in a sorted array that sum to a target

B Sorting an unsorted array

C Finding the maximum element in an array

D Calculating factorial of a number

Two Pointer Technique efficiently finds pairs with a target sum in sorted arrays.

What is the typical time complexity of Two Pointer Technique on arrays?

A O(n log n)

B O(n)

C O(n^2)

D O(log n)

Two Pointer Technique usually runs in linear time, O(n).

When using Two Pointer Technique, what condition usually stops the process?

A When pointers meet or cross

B When pointers are at the start

C When pointers are at the end

D After fixed number of steps

The process stops when pointers meet or cross each other.

In Two Pointer Technique, if the sum of elements at pointers is less than the target, what should you do?

A Move the pointer at the end towards the start

B Move both pointers towards the start

C Move the pointer at the start towards the end

D Stop the process

If the sum is too small, moving the start pointer right increases the sum.

Explain the Two Pointer Technique on Arrays and how it helps solve problems efficiently.

Think about how two people walking from opposite ends can meet faster than checking every pair.

Describe a step-by-step approach to find two numbers in a sorted array that add up to a target using Two Pointer Technique.

Imagine adjusting your guess by moving left or right based on whether the sum is too big or too small.

Practice

1. What is the main idea behind the Two Pointer Technique when used on arrays?

easy

A. Use recursion to divide the array into two parts

B. Use two arrays to store intermediate results

C. Sort the array twice before processing

D. Use two indices to scan the array from different ends or positions simultaneously

Solution

1. Step 1: Understand the technique

   The two pointer technique uses two indices or pointers to traverse the array, often from opposite ends or different positions.

2. Step 2: Identify the purpose

   This helps solve problems like finding pairs, removing duplicates, or partitioning efficiently without extra space.

3. Final Answer:

   Use two indices to scan the array from different ends or positions simultaneously -> Option D

4. Quick Check:

   Two pointers = two indices scanning array [OK]

Hint: Think of two fingers moving on array from different sides [OK]

Common Mistakes:

• Confusing two pointers with two separate arrays
• Assuming sorting is always required
• Thinking recursion is part of two pointer technique

2. Which of the following Rust code snippets correctly initializes two pointers for the two pointer technique on a vector arr?

easy

A. let (left, right) = (arr.len() - 1, 0);

B. let (mut left, mut right) = (0, arr.len() - 1);

C. let (mut left, mut right) = (1, arr.len());

D. let (left, right) = (arr.len(), 0);

Solution

1. Step 1: Check pointer initialization

   Two pointers usually start at the beginning (0) and end (length - 1) of the array.

2. Step 2: Verify mutability and valid indices

   Pointers must be mutable to move, and indices must be within array bounds (0 to len-1).

3. Final Answer:

   let (mut left, mut right) = (0, arr.len() - 1); -> Option B

4. Quick Check:

   Start pointers at 0 and len-1 with mut [OK]

Hint: Start pointers at 0 and last index, make them mutable [OK]

Common Mistakes:

• Using non-mutable pointers when they need to move
• Setting pointers outside array bounds
• Swapping start and end indices

3. What will be the output of the following Rust code using two pointers?

let arr = vec![1, 2, 3, 4, 5];
let (mut left, mut right) = (0, arr.len() - 1);
let mut sum_pairs = Vec::new();
while left < right {
    sum_pairs.push(arr[left] + arr[right]);
    left += 1;
    right -= 1;
}
println!("{:?}", sum_pairs);

medium

A. [6, 6]

B. [6, 7]

C. [6, 5]

D. [5, 7]

Solution

1. Step 1: Trace pointer movements and sums

   Initially, left=0, right=4: sum = 1+5=6; then left=1, right=3: sum = 2+4=6; loop stops when left=2, right=2.

2. Step 2: Collect sums in vector

   The sums collected are [6, 6].

3. Final Answer:

   [6, 6] -> Option A

4. Quick Check:

   Pairs sums = [6, 6] [OK]

Hint: Add elements at left and right, move pointers inward [OK]

Common Mistakes:

• Not stopping loop when pointers meet
• Adding wrong pairs or indices
• Off-by-one errors in pointer updates

4. Identify the bug in this Rust code snippet using two pointers to find if a sorted array contains two numbers that sum to 10:

let arr = vec![1, 2, 3, 7, 8];
let (mut left, mut right) = (0, arr.len());
while left < right {
    let sum = arr[left] + arr[right];
    if sum == 10 {
        println!("Found");
        break;
    } else if sum < 10 {
        left += 1;
    } else {
        right -= 1;
    }
}

medium

A. The loop condition should be left <= right

B. left pointer should start at arr.len() - 1

C. right is initialized to arr.len(), which is out of bounds

D. The sum calculation should use arr[left] - arr[right]

Solution

1. Step 1: Check pointer initialization

   right is set to arr.len(), which is one past the last valid index (arr.len() - 1).

2. Step 2: Understand consequences

   Accessing arr[right] causes an out-of-bounds error and program panic.

3. Final Answer:

   right is initialized to arr.len(), which is out of bounds -> Option C

4. Quick Check:

   Array indices go 0 to len-1 [OK]

Hint: Check if pointers are within valid index range [OK]

Common Mistakes:

• Using arr.len() as index instead of arr.len() - 1
• Incorrect loop condition allowing invalid access
• Mixing addition and subtraction in sum calculation

5. Given a sorted array of integers, write a Rust function using the two pointer technique to return all unique pairs that sum to a target value. Which approach correctly avoids duplicate pairs?

hard

A. Move left and right pointers inward, skipping duplicates after finding a valid pair

B. Use nested loops to check all pairs and store unique pairs in a set

C. Sort the array again inside the loop to remove duplicates

D. Only move the left pointer forward regardless of sum comparison

Solution

1. Step 1: Use two pointers from start and end

   Initialize left at 0 and right at last index, move inward based on sum comparison.

2. Step 2: Skip duplicates after finding a valid pair

   After adding a pair, increment left while next value equals current, decrement right similarly to avoid duplicates.

3. Final Answer:

   Move left and right pointers inward, skipping duplicates after finding a valid pair -> Option A

4. Quick Check:

   Skip duplicates by moving pointers after valid pair [OK]

Hint: After finding pair, skip duplicates by moving pointers [OK]

Common Mistakes:

• Not skipping duplicates causing repeated pairs
• Using nested loops instead of two pointers
• Moving only one pointer regardless of sum