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DSA Rustprogramming~5 mins

Sort a Linked List Using Merge Sort in DSA Rust - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is the main idea behind merge sort when sorting a linked list?
Merge sort divides the linked list into two halves, sorts each half recursively, and then merges the two sorted halves back together.
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intermediate
Why is merge sort preferred over quicksort for sorting linked lists?
Merge sort works well with linked lists because it does not require random access and can merge sorted lists efficiently by changing pointers, while quicksort relies on random access which linked lists do not support efficiently.
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beginner
In merge sort for linked lists, how do you find the middle point to split the list?
Use two pointers: a slow pointer that moves one step at a time and a fast pointer that moves two steps at a time. When the fast pointer reaches the end, the slow pointer will be at the middle.
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beginner
What is the time complexity of merge sort on a linked list?
The time complexity is O(n log n), where n is the number of nodes in the linked list.
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beginner
How does merging two sorted linked lists work in merge sort?
Compare the head nodes of both lists, attach the smaller one to the result, and move that list's pointer forward. Repeat until all nodes are merged into a sorted list.
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What technique is used to find the middle of a linked list in merge sort?
ACounting nodes then dividing by two
BRandom access by index
CUsing a stack
DTwo pointers: slow and fast
What is the best time complexity of merge sort on a linked list?
AO(log n)
BO(n^2)
CO(n log n)
DO(n)
Why is merge sort efficient for linked lists compared to quicksort?
AMerge sort changes pointers without extra space
BMerge sort requires extra arrays
CQuicksort is faster on linked lists
DMerge sort uses random access
What happens after splitting the linked list in merge sort?
AReverse the halves
BSort each half recursively
CMerge without sorting
DDelete one half
How do you merge two sorted linked lists?
ACompare heads and link smaller node first
BSort both lists again
CAppend one list to the other
DUse an array to merge
Explain step-by-step how merge sort sorts a linked list.
Think about dividing the list and then combining sorted parts.
You got /4 concepts.
    Describe why merge sort is a good choice for sorting linked lists compared to other sorting algorithms.
    Consider how linked lists store data and how merge sort works with pointers.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is the main advantage of using merge sort to sort a linked list compared to quicksort?
      easy
      A. Merge sort is faster than quicksort in all cases.
      B. Merge sort uses less memory than quicksort.
      C. Merge sort does not require random access, which suits linked lists well.
      D. Merge sort sorts the list in place without extra space.

      Solution

      1. Step 1: Understand linked list access

        Linked lists do not support fast random access, unlike arrays.
      2. Step 2: Compare sorting algorithms

        Merge sort works well with sequential access by splitting and merging, while quicksort relies on random access for partitioning.
      3. Final Answer:

        Merge sort does not require random access, which suits linked lists well. -> Option C
      4. Quick Check:

        Linked list + merge sort = no random access needed [OK]
      Hint: Merge sort fits linked lists because it avoids random access [OK]
      Common Mistakes:
      • Thinking quicksort is always faster
      • Assuming merge sort sorts in place without extra space
      • Confusing memory usage between merge sort and quicksort
      2. Which Rust code snippet correctly defines a singly linked list node struct for merge sort?
      easy
      A. struct ListNode { val: i32, next: Box<ListNode> }
      B. struct ListNode { val: i32, next: Option }
      C. struct ListNode { val: i32, next: &ListNode }
      D. struct ListNode { val: i32, next: Option<&ListNode> }

      Solution

      1. Step 1: Understand ownership in Rust linked lists

        Rust requires ownership for heap data; Box<T> owns heap data, Option allows None or a node.
      2. Step 2: Analyze options

        struct ListNode { val: i32, next: Option } uses Option which is correct for nullable next pointer. Others use references without ownership or missing Option.
      3. Final Answer:

        struct ListNode { val: i32, next: Option } -> Option B
      4. Quick Check:

        Rust linked list node uses Option [OK]
      Hint: Use Option for nullable next in Rust linked lists [OK]
      Common Mistakes:
      • Using references (&) without lifetime management
      • Omitting Option for nullable next pointer
      • Using Box<T> without Option causing no null
      3. Given the following linked list: 4 -> 2 -> 1 -> 3 -> null, what is the sorted list after applying merge sort?
      medium
      A. 1 -> 2 -> 3 -> 4 -> null
      B. 4 -> 3 -> 2 -> 1 -> null
      C. 2 -> 1 -> 3 -> 4 -> null
      D. 1 -> 3 -> 2 -> 4 -> null

      Solution

      1. Step 1: Split the list into halves

        Split 4->2->1->3 into 4->2 and 1->3.
      2. Step 2: Recursively sort and merge

        Sort halves: 4->2 becomes 2->4, 1->3 becomes 1->3. Merge sorted halves: 1->2->3->4.
      3. Final Answer:

        1 -> 2 -> 3 -> 4 -> null -> Option A
      4. Quick Check:

        Sorted ascending linked list = 1->2->3->4 [OK]
      Hint: Merge sort splits and merges sorted halves for linked lists [OK]
      Common Mistakes:
      • Not splitting list correctly
      • Merging without sorting halves
      • Confusing order of merged nodes
      4. In the Rust merge sort implementation for linked lists, which mistake causes infinite recursion?
      medium
      A. Using Box instead of Rc for next pointers
      B. Using a mutable reference instead of ownership for nodes
      C. Sorting the list without splitting it
      D. Not updating the next pointer to None when splitting the list

      Solution

      1. Step 1: Understand splitting in merge sort

        Splitting requires breaking the list into two halves by setting the middle node's next pointer to None.
      2. Step 2: Identify infinite recursion cause

        If next pointer is not set to None, recursive calls never reach base case, causing infinite recursion.
      3. Final Answer:

        Not updating the next pointer to None when splitting the list -> Option D
      4. Quick Check:

        Broken split causes infinite recursion [OK]
      Hint: Set middle.next = None to stop recursion [OK]
      Common Mistakes:
      • Forgetting to break the list at midpoint
      • Confusing Box and Rc usage
      • Misusing references causing borrow errors
      5. You have a linked list with duplicate values: 5 -> 3 -> 5 -> 2 -> 3 -> null. After applying merge sort, what is the correct sorted list?
      hard
      A. 2 -> 3 -> 3 -> 5 -> 5 -> null
      B. 5 -> 5 -> 3 -> 3 -> 2 -> null
      C. 2 -> 3 -> 5 -> null
      D. 3 -> 2 -> 5 -> 3 -> 5 -> null

      Solution

      1. Step 1: Recognize duplicates in the list

        The list contains duplicates: two 5s and two 3s.
      2. Step 2: Apply merge sort preserving duplicates

        Merge sort sorts all nodes including duplicates, resulting in ascending order with duplicates preserved: 2->3->3->5->5.
      3. Final Answer:

        2 -> 3 -> 3 -> 5 -> 5 -> null -> Option A
      4. Quick Check:

        Sorted list keeps duplicates in order [OK]
      Hint: Merge sort keeps duplicates sorted in order [OK]
      Common Mistakes:
      • Removing duplicates by mistake
      • Sorting incorrectly ignoring duplicates
      • Confusing output order with duplicates
      Recommended

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