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DSA Rustprogramming~10 mins

Push Using Linked List Node in DSA Rust - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a new node with the given value.

DSA Rust
let new_node = Box::new(Node { data: value, next: [1] });
Drag options to blanks, or click blank then click option'
ASome(value)
BNone
Cnext
Dhead
Attempts:
3 left
💡 Hint
Common Mistakes
Setting next to Some(value) instead of None
Using head instead of None for next
2fill in blank
medium

Complete the code to link the new node to the current head of the list.

DSA Rust
new_node.next = [1];
Drag options to blanks, or click blank then click option'
Ahead.take()
BSome(value)
CNone
Dnew_node
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning None instead of head.take()
Assigning new_node to next causing self-reference
3fill in blank
hard

Fix the error in updating the head pointer to the new node.

DSA Rust
head = [1];
Drag options to blanks, or click blank then click option'
ASome(new_node)
Bnew_node
CNone
Dhead
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning new_node directly without Some()
Assigning None or head itself
4fill in blank
hard

Fill both blanks to complete the push function that adds a new node at the front.

DSA Rust
fn push(&mut self, value: i32) {
    let mut new_node = Box::new(Node { data: value, next: [1] });
    new_node.next = [2];
    self.head = Some(new_node);
}
Drag options to blanks, or click blank then click option'
ANone
Bself.head.take()
CSome(value)
Dself.head
Attempts:
3 left
💡 Hint
Common Mistakes
Setting next to Some(value) initially
Assigning self.head directly without take()
5fill in blank
hard

Fill all three blanks to complete the push method that safely adds a new node at the front of the linked list.

DSA Rust
fn push(&mut self, value: i32) {
    let mut new_node = Box::new(Node { data: value, next: [1] });
    new_node.next = [2];
    self.head = [3];
}
Drag options to blanks, or click blank then click option'
ANone
Bself.head.take()
CSome(new_node)
DSome(value)
Attempts:
3 left
💡 Hint
Common Mistakes
Not using take() causing ownership errors
Assigning head directly without Some()
Setting next incorrectly

Practice

(1/5)
1. What does the push operation do in a linked list when using a node?
easy
A. Adds a new node at the beginning of the list
B. Removes the last node from the list
C. Searches for a node with a specific value
D. Deletes the entire list

Solution

  1. Step 1: Understand push operation in linked list

    The push operation adds a new node to the linked list.
  2. Step 2: Identify where the new node is added

    In a singly linked list, push usually adds the new node at the start (head) of the list.
  3. Final Answer:

    Adds a new node at the beginning of the list -> Option A
  4. Quick Check:

    Push = Add at head [OK]
Hint: Push always adds node at the start of the list [OK]
Common Mistakes:
  • Thinking push adds at the end
  • Confusing push with pop
  • Assuming push deletes nodes
2. Which of the following Rust code snippets correctly creates a new node and pushes it to the front of a linked list?
easy
A. head = Some(Node { data: 5, next: None });
B. let new_node = Node { data: 5, next: None }; head = new_node.next;
C. let new_node = Box::new(Node { data: 5, next: head }); head = Some(new_node);
D. let new_node = Box::new(Node { data: 5 }); head = new_node.next;

Solution

  1. Step 1: Check node creation with Box and linking

    let new_node = Box::new(Node { data: 5, next: head }); head = Some(new_node); creates a boxed node with data 5 and next pointing to current head.
  2. Step 2: Assign new node as new head

    Then head is updated to Some(new_node), correctly pushing at front.
  3. Final Answer:

    let new_node = Box::new(Node { data: 5, next: head }); head = Some(new_node); -> Option C
  4. Quick Check:

    Boxed node with next=head, then head=Some(new_node) [OK]
Hint: Use Box::new and set next to current head [OK]
Common Mistakes:
  • Not boxing the node
  • Not updating head correctly
  • Setting next to None instead of head
3. What will be the printed linked list after executing this Rust code?
struct Node {
    data: i32,
    next: Option,
}

fn push(head: &mut Option, data: i32) {
    let new_node = Box::new(Node { data, next: head.take() });
    *head = Some(new_node);
}

fn print_list(head: &Option) {
    let mut current = head;
    while let Some(node) = current {
        print!("{} -> ", node.data);
        current = &node.next;
    }
    println!("null");
}

fn main() {
    let mut head = None;
    push(&mut head, 10);
    push(&mut head, 20);
    push(&mut head, 30);
    print_list(&head);
}
medium
A. 10 -> 20 -> 30 -> null
B. 30 -> 20 -> 10 -> null
C. null
D. Compilation error

Solution

  1. Step 1: Trace push calls and list building

    First push adds 10 as head. Second push adds 20 before 10. Third push adds 30 before 20.
  2. Step 2: Print list from head

    Print starts at head (30), then 20, then 10, then null.
  3. Final Answer:

    30 -> 20 -> 10 -> null -> Option B
  4. Quick Check:

    Last pushed node is head, so list is 30->20->10->null [OK]
Hint: Last pushed node appears first in list [OK]
Common Mistakes:
  • Assuming push adds at end
  • Confusing order of nodes
  • Ignoring Option and Box usage
4. Identify the error in this Rust function that tries to push a new node to the linked list head:
fn push(head: &mut Option, data: i32) {
    let new_node = Box::new(Node { data, next: head });
    *head = Some(new_node);
}
medium
A. Cannot assign &Option to next, must use head.take()
B. Missing return statement
C. Box::new cannot be used here
D. Data type i32 is incorrect

Solution

  1. Step 1: Analyze next field assignment

    The next field expects Option, but head is &mut Option, a reference.
  2. Step 2: Correct usage with head.take()

    Using head.take() moves the Option out, allowing ownership transfer to next.
  3. Final Answer:

    Cannot assign &Option to next, must use head.take() -> Option A
  4. Quick Check:

    Use head.take() to move ownership [OK]
Hint: Use head.take() to move Option ownership [OK]
Common Mistakes:
  • Assigning reference instead of owned Option
  • Ignoring Rust ownership rules
  • Thinking Box::new is invalid here
5. Given a linked list implemented with nodes in Rust, how would you modify the push function to prevent memory leaks when repeatedly pushing nodes?
hard
A. Use clone() on nodes to duplicate data
B. Use raw pointers instead of Box to manage nodes
C. Manually call drop() on old head before pushing
D. Use head.take() to transfer ownership and avoid dangling references

Solution

  1. Step 1: Understand ownership in Rust linked list

    Each node owns the next node via Box. To avoid leaks, ownership must be properly transferred.
  2. Step 2: Use head.take() to move ownership safely

    head.take() replaces head with None and moves ownership to new node's next, preventing leaks.
  3. Final Answer:

    Use head.take() to transfer ownership and avoid dangling references -> Option D
  4. Quick Check:

    head.take() safely moves ownership, preventing leaks [OK]
Hint: Use head.take() to transfer ownership safely [OK]
Common Mistakes:
  • Using raw pointers causing unsafe code
  • Calling drop manually causing double free
  • Cloning nodes causing unnecessary copies
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10 questions~5 mineasy hard