Insert at Middle Specific Position in DSA Rust - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does 'Insert at Middle Specific Position' mean in a linked list?

It means adding a new node at a given position inside the list, not at the start or end, but somewhere in the middle.

intermediate

In Rust, which data structure is commonly used to represent a singly linked list?

An enum with variants for 'Node' containing data and a Box pointing to the next node, and 'None' for the end of the list.

beginner

Why do we need to traverse the list to insert at a middle position?

Because linked lists do not have direct access by index, we must move node by node until we reach the desired position.

intermediate

What happens if you try to insert at a position greater than the list length?

The insertion can fail or be ignored because the position is invalid; some implementations add at the end instead.

advanced

How does Rust's ownership model affect linked list insertion?

Rust requires careful handling of ownership and borrowing, so nodes are often boxed to allow recursive types and safe mutation.

What is the first step to insert a node at a specific middle position in a singly linked list?

A Delete the node at the position

B Create a new node and set it as the head

C Traverse the list to the node before the desired position

D Reverse the list

To insert at a middle position, you first move to the node just before that position to adjust pointers.

In Rust, which keyword is used to allocate a node on the heap for a linked list?

A Rc

B Vec

C RefCell

D Box

Box is used to allocate data on the heap, which is necessary for recursive data structures like linked lists.

If you want to insert at position 3 in a list, which node do you link the new node to?

A Node at position 2

B Node at position 3

C Node at position 4

D Head node

You link the new node after the node at position 2 to insert it at position 3.

What is the time complexity of inserting at a middle position in a singly linked list?

A O(1)

B O(n)

C O(log n)

D O(n^2)

You must traverse up to the position, which takes linear time proportional to the list size.

Which Rust feature helps safely mutate nodes in a linked list during insertion?

A Mutable references (&mut)

B Immutable references (&)

C Unsafe pointers

D Static variables

Mutable references allow changing the node's next pointer safely during insertion.

Explain step-by-step how to insert a new node at a specific middle position in a singly linked list in Rust.

Think about how ownership and pointers work in Rust linked lists.

Describe how Rust's ownership and borrowing rules influence the design of a linked list and its insertion method.

Consider why Box and &mut are important in linked lists.

Practice

1. What does inserting a node at a specific middle position in a linked list mean?

easy

A. Removing a node from the middle of the list

B. Adding a new node only at the start of the list

C. Adding a new node only at the end of the list

D. Adding a new node exactly between two existing nodes at a given position

Solution

1. Step 1: Understand linked list positions

   Positions in a linked list start from 1 at the head. Inserting at a middle position means placing a new node between existing nodes.

2. Step 2: Define insertion at middle

   Inserting at a specific middle position means the new node will be placed after the node at position (pos-1) and before the node at position pos.

3. Final Answer:

   Adding a new node exactly between two existing nodes at a given position -> Option D

4. Quick Check:

   Insert at middle = Add node between nodes [OK]

Hint: Middle insertion means placing node between two nodes [OK]

Common Mistakes:

• Confusing insertion with deletion
• Thinking insertion only happens at start or end
• Ignoring position indexing starting at 1

2. Which Rust code snippet correctly inserts a new node with value 10 at position 3 in a singly linked list?

easy

A. let mut current = &mut head;
for _ in 1..2 {
current = &mut current.as_mut().unwrap().next;
}
let new_node = Some(Box::new(Node { val: 10, next: current.take() }));
*current = new_node;

B. let mut current = &head;
for _ in 1..3 {
current = ¤t.unwrap().next;
}
current = Some(Box::new(Node { val: 10, next: None }));

C. head = Some(Box::new(Node { val: 10, next: head }));

D. let new_node = Node { val: 10, next: None };
head.next = Some(Box::new(new_node));

Solution

1. Step 1: Traverse to position before insertion

   The loop runs from 1 to 2 (pos-1) to reach node at position 2, using mutable references to modify links.

2. Step 2: Insert new node at position 3

   Create new node with value 10, set its next to current node's next, then update current's next to new node.

3. Final Answer:

   Code snippet in option A correctly inserts at position 3 -> Option A

4. Quick Check:

   Traverse to pos-1, link new node next to current next, update current next [OK]

Hint: Traverse to pos-1, then link new node [OK]

Common Mistakes:

• Using immutable references when mutable needed
• Incorrect loop range causing wrong position
• Not updating links properly causing list break

3. What is the output linked list after inserting value 99 at position 2 in the list 1 -> 2 -> 3 -> null using the following Rust code?

let mut head = Some(Box::new(Node { val: 1, next: Some(Box::new(Node { val: 2, next: Some(Box::new(Node { val: 3, next: None })) })) }));

let mut current = &mut head;
for _ in 1..1 {
    current = &mut current.as_mut().unwrap().next;
}
let new_node = Some(Box::new(Node { val: 99, next: current.as_mut().unwrap().next.take() }));
current.as_mut().unwrap().next = new_node;

// Print list code omitted for brevity

medium

A. 1 -> 99 -> 2 -> 3 -> null

B. 1 -> 2 -> 99 -> 3 -> null

C. 99 -> 1 -> 2 -> 3 -> null

D. 1 -> 2 -> 3 -> 99 -> null

Solution

1. Step 1: Traverse to node at position 1

   The loop runs from 1 to 1, which is empty, so no iteration; current points to head node with value 1.

2. Step 2: Insert new node after current

   New node with value 99 is created with next pointing to current's next (node with value 2). Then current's next is updated to new node.

3. Final Answer:

   1 -> 99 -> 2 -> 3 -> null -> Option A

4. Quick Check:

   Insert after position 1 adds 99 between 1 and 2 [OK]

Hint: Insert after pos-1 node, new node points to old next [OK]

Common Mistakes:

• Miscounting loop iterations causing wrong position
• Not updating next pointers correctly
• Confusing node values and positions

4. Identify the error in this Rust code snippet that tries to insert a node at position 2 in a singly linked list:

let mut current = &mut head;
for _ in 0..2 {
    current = &mut current.as_mut().unwrap().next;
}
let new_node = Some(Box::new(Node { val: 5, next: current.take() }));
*current = new_node;

medium

A. The code uses immutable references instead of mutable

B. The loop runs too many times, moving current past the insertion point

C. The new node's next pointer is not set correctly

D. The head pointer is not updated after insertion

Solution

1. Step 1: Analyze loop iteration count

   The loop runs from 0 to 1 (0..2), so two iterations, moving current two nodes ahead, which is past position 2.

2. Step 2: Understand insertion position

   To insert at position 2, current should point to node at position 1 (pos-1). Loop should run once, not twice.

3. Final Answer:

   The loop runs too many times, moving current past the insertion point -> Option B

4. Quick Check:

   Loop count must be pos-1 to insert correctly [OK]

Hint: Loop must run pos-1 times to reach insertion point [OK]

Common Mistakes:

• Off-by-one error in loop range
• Not using mutable references for insertion
• Incorrectly setting new node's next pointer

5. Given a singly linked list and a position that may be beyond the current list length, how should you modify the insertion logic in Rust to insert a node with value 50 at position 5 in the list 10 -> 20 -> 30 -> null?

hard

A. Return an error and do not insert if position is beyond length

B. Insert at the head regardless of position

C. Traverse until the end if position exceeds length, then insert at the end

D. Insert at position 3 instead of 5 automatically

Solution

1. Step 1: Check position against list length

   Since position 5 is beyond current length 3, traverse until the last node to insert at the end.

2. Step 2: Insert new node at end

   Once at last node, set its next pointer to new node with value 50 and next as None.

3. Final Answer:

   Traverse until the end if position exceeds length, then insert at the end -> Option C

4. Quick Check:

   Insert at end if position too large [OK]

Hint: If position too big, insert at list end [OK]

Common Mistakes:

• Crashing or panicking when position is too large
• Ignoring position and inserting at wrong place
• Not handling None next pointers properly