A doubly linked list is a chain of nodes where each node has a value and two links: one to the next node and one to the previous node. This allows moving forward and backward through the list.
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beginner
What steps are needed to insert a new node at the end of a doubly linked list?
1. Create a new node with the given value. 2. If the list is empty, set the new node as the head. 3. Otherwise, find the last node. 4. Set the last node's next link to the new node. 5. Set the new node's previous link to the last node. 6. Set the new node's next link to None.
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intermediate
In Rust, why do we use Option> for doubly linked list nodes?
Because nodes can be shared and mutated, Rc allows multiple ownership, and RefCell allows mutable access at runtime. Option handles the possibility of no next or previous node (null).
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beginner
What happens if you forget to update the previous pointer of the new node when inserting at the end?
The new node will not correctly link back to the last node, breaking backward traversal. This can cause errors when moving backward through the list.
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beginner
How do you handle inserting into an empty doubly linked list?
If the list is empty (head is None), set the head to the new node. The new node's next and previous pointers are None.
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What pointer of the last node must be updated when inserting a new node at the end of a doubly linked list?
Aprevious
Bnext
Chead
Dtail
✗ Incorrect
The last node's next pointer must point to the new node to link it at the end.
In a doubly linked list, what does the new node's previous pointer point to after insertion at the end?
AThe last node before insertion
BThe head node
CNull
DItself
✗ Incorrect
The new node's previous pointer points to the old last node to maintain backward links.
Which Rust type helps manage multiple owners of a node in a doubly linked list?
ARc
BVec
CBox
DOption
✗ Incorrect
Rc allows multiple owners of the same data, useful for linked list nodes.
What should you do if the doubly linked list is empty when inserting a new node at the end?
ADelete the new node
BDo nothing
CSet the new node as the head
DSet the new node's next to head
✗ Incorrect
If the list is empty, the new node becomes the head of the list.
What is the time complexity of inserting at the end of a doubly linked list if you do not keep a tail pointer?
AO(1)
BO(n^2)
CO(log n)
DO(n)
✗ Incorrect
Without a tail pointer, you must traverse the list to find the last node, which takes O(n) time.
Explain how to insert a new node at the end of a doubly linked list step-by-step.
Think about links forward and backward.
You got /7 concepts.
Describe how Rust's Rc and RefCell help in implementing a doubly linked list.
Focus on ownership and mutability.
You got /4 concepts.
Practice
(1/5)
1. What is the main purpose of inserting a node at the end of a doubly linked list?
easy
A. To reverse the list
B. To remove the first node
C. To add a new element after the last node
D. To find the middle node
Solution
Step 1: Understand the structure of a doubly linked list
A doubly linked list has nodes connected forward and backward, allowing traversal in both directions.
Step 2: Purpose of insertion at the end
Inserting at the end means adding a new node after the current last node, updating pointers accordingly.
Final Answer:
To add a new element after the last node -> Option C
Quick Check:
Insert at end = add after last node [OK]
Hint: Insert at end means add after last node [OK]
Common Mistakes:
Confusing insertion at end with deletion
Thinking insertion reverses the list
Assuming insertion happens at the start
2. Which Rust code snippet correctly creates a new node and inserts it at the end of a doubly linked list?
easy
A. let new_node = Node::new(value); new_node.prev = Some(head); head.next = Some(new_node);
B. let new_node = Node::new(value); head.prev = Some(new_node); new_node.next = Some(head);
C. let new_node = Node::new(value); new_node.next = Some(tail); tail.prev = Some(new_node);
D. let new_node = Node::new(value); tail.next = Some(new_node); new_node.prev = Some(tail);
Solution
Step 1: Create new node with given value
Use Node::new(value) to create a new node.
Step 2: Link new node after tail
Set tail.next to new_node and new_node.prev to tail to insert at end.
Final Answer:
let new_node = Node::new(value); tail.next = Some(new_node); new_node.prev = Some(tail); -> Option D
Quick Check:
New node after tail = let new_node = Node::new(value); tail.next = Some(new_node); new_node.prev = Some(tail); [OK]
Hint: New node's prev points to tail; tail's next points to new node [OK]
Common Mistakes:
Linking new node before head instead of after tail
Swapping next and prev pointers incorrectly
Not updating tail's next pointer
3. Given the Rust code below, what will be the printed list after inserting 4 at the end?
struct Node {
value: i32,
prev: Option,
next: Option,
}
// Assume list initially: 1 <-> 2 <-> 3
// Insert 4 at end
// Print list from head to tail
medium
A. 1 <-> 2 <-> 3 <-> 4 <-> null
B. 4 <-> 1 <-> 2 <-> 3 <-> null
C. 1 <-> 2 <-> 4 <-> 3 <-> null
D. 1 <-> 2 <-> 3 <-> null
Solution
Step 1: Understand initial list structure
The list is 1 linked to 2, linked to 3, with 3 as tail.
Step 2: Insert 4 at the end
Adding 4 after 3 updates 3.next to 4 and 4.prev to 3.
Final Answer:
1 <-> 2 <-> 3 <-> 4 <-> null -> Option A
Quick Check:
Insert at end adds 4 after 3 [OK]
Hint: New node appears after last node in printed list [OK]
Common Mistakes:
Inserting new node at start instead of end
Not updating next pointer of last node
Printing list without new node
4. Identify the error in this Rust code snippet for inserting at the end of a doubly linked list:
A. tail is not updated correctly; should update tail's next pointer
B. new_node.prev should be None for end insertion
C. new_node should not be boxed
D. value should be mutable
Solution
Step 1: Check pointer updates
tail is reassigned locally, but tail's next pointer is not updated to link new_node.
Step 2: Correct linking needed
Must set tail's next to new_node and new_node.prev to tail, then update tail reference.
Final Answer:
tail is not updated correctly; should update tail's next pointer -> Option A
Quick Check:
Update tail.next to new_node [OK]
Hint: Always update tail's next pointer when inserting at end [OK]
Common Mistakes:
Only reassigning tail without linking nodes
Setting prev pointer incorrectly
Ignoring ownership rules in Rust
5. You have a doubly linked list with nodes: 10 <-> 20 <-> 30. You want to insert 25 at the end but also keep a pointer to the middle node for quick access. After insertion, which node should the middle pointer reference to keep it as the middle of the list?
hard
A. 25
B. 20
C. 30
D. 10
Solution
Step 1: Understand list before insertion
List is 10 <-> 20 <-> 30; middle is 20 (second of three nodes).
Step 2: Insert 25 at end and find new middle
List becomes 10 <-> 20 <-> 30 <-> 25. With 4 nodes, middle is between 20 and 30, usually the second node (20) to keep balance.
Final Answer:
20 -> Option B
Quick Check:
Middle of 4 nodes = 2nd node [OK]
Hint: Middle of even nodes is lower middle [OK]
Common Mistakes:
Moving middle pointer to last inserted node
Choosing last node as middle
Not updating middle pointer after insertion
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