Find the Only Non Repeating Element Using XOR in DSA Rust - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does XOR operation do when applied between two identical bits?

XOR of two identical bits is 0. For example, 1 XOR 1 = 0 and 0 XOR 0 = 0.

beginner

Why does XOR help find the only non-repeating element in an array where every other element repeats twice?

Because XOR of a number with itself is 0, all repeating elements cancel out, leaving only the non-repeating element after XORing all elements.

beginner

What is the initial value used when XORing all elements to find the unique element?

The initial value is 0 because XOR with 0 leaves the number unchanged, so it does not affect the result.

beginner

How does the XOR operation behave when applied between a number and 0?

XOR of any number with 0 is the number itself. For example, 5 XOR 0 = 5.

beginner

What is the time complexity of finding the only non-repeating element using XOR in an array?

The time complexity is O(n), where n is the number of elements, because we XOR all elements once.

What is the result of XORing a number with itself?

A 0

B The number itself

C 1

D Undefined

XOR of a number with itself is always 0.

What initial value should you use when XORing all elements to find the unique element?

A 0

B The first element

C 1

D The last element

Start with 0 because XOR with 0 does not change the value.

If an array has elements [2, 3, 2, 4, 3], what is the unique element using XOR?

A 3

B 4

C 2

D None

XORing all elements cancels duplicates, leaving 4.

What is the time complexity of the XOR method to find the unique element?

A O(n^2)

B O(1)

C O(log n)

D O(n)

We iterate once over the array, so time complexity is O(n).

Which of these is NOT true about XOR operation?

A XOR is commutative and associative

B XOR of a number with itself is 0

C XOR of two different numbers is always 1

D XOR of a number with 0 is the number itself

XOR of two different numbers is not always 1; it depends on their bits.

Explain how XOR helps find the only non-repeating element in an array where every other element repeats twice.

Think about how pairs cancel each other out using XOR.

Describe the steps and time complexity of the XOR method to find the unique element in an array.

Focus on the iteration and XOR properties.

Practice

1. What does the XOR operation do when applied between two identical numbers?

easy

A. It returns 0

B. It returns the number itself

C. It returns 1

D. It returns the sum of the numbers

Solution

1. Step 1: Understand XOR property for identical numbers

   XOR of a number with itself is always 0 because bits cancel out.

2. Step 2: Apply this property to the question

   Since the two numbers are identical, XOR returns 0.

3. Final Answer:

   It returns 0 -> Option A

4. Quick Check:

   X XOR X = 0 [OK]

Hint: XOR of same numbers always zero [OK]

Common Mistakes:

• Thinking XOR returns the number itself
• Confusing XOR with addition
• Assuming XOR returns 1 for identical numbers

2. Which Rust syntax correctly initializes a variable to zero for XOR operation?

easy

A. let mut result = 0;

B. let result = 0;

C. let mut result = 1;

D. let mut result = None;

Solution

1. Step 1: Identify mutable variable declaration

   We need a mutable variable to update XOR results, so use 'mut'.

2. Step 2: Initialize variable to zero

   Zero is the identity for XOR, so initialize with 0.

3. Final Answer:

   let mut result = 0; -> Option A

4. Quick Check:

   Mutable zero initialization for XOR [OK]

Hint: Use 'let mut var = 0;' for XOR accumulator [OK]

Common Mistakes:

• Not using 'mut' for variable to update
• Initializing with 1 instead of 0
• Using Option type instead of integer

3. What is the output of this Rust code?

fn main() {
    let arr = [2, 3, 5, 4, 5, 3, 4];
    let mut result = 0;
    for &num in &arr {
        result ^= num;
    }
    println!("{}", result);
}

medium

A. 4

B. 5

C. 0

D. 2

Solution

1. Step 1: XOR all elements in the array

   Calculate XOR stepwise: 0^2=2, 2^3=1, 1^5=4, 4^4=0, 0^5=5, 5^3=6, 6^4=2.

2. Step 2: Identify the non-repeating element

   The final XOR result is 2, which is the only number not repeated.

3. Final Answer:

   2 -> Option D

4. Quick Check:

   Final XOR = 2 [OK]

Hint: XOR all numbers; result is unique element [OK]

Common Mistakes:

• Miscomputing XOR steps
• Assuming repeated numbers affect result
• Confusing output with repeated elements

4. Identify the error in this Rust code that tries to find the non-repeating element using XOR:

fn main() {
    let arr = [1, 2, 1, 3, 2];
    let mut result = 0;
    for num in arr {
        result = result ^ num;
    }
    println!("{}", result);
}

medium

A. Missing '&' in for loop to borrow elements

B. No error, code works correctly

C. Incorrect initialization of result variable

D. Using '=' instead of '^=' operator

Solution

1. Step 1: Check for borrowing in for loop

   Iterating over array by value is allowed; no '&' needed.

2. Step 2: Verify XOR operation and initialization

   Result initialized to 0 and XOR applied correctly with '=' operator.

3. Final Answer:

   No error, code works correctly -> Option B

4. Quick Check:

   Code runs and finds unique element [OK]

Hint: XOR with '=' works; no borrow needed for array iteration [OK]

Common Mistakes:

• Thinking '&' is mandatory in for loop
• Confusing '=' with '^=' operator
• Assuming initialization must be different

5. Given an array where every element repeats twice except one element which repeats thrice, can XOR find the unique element? Why or why not?

hard

A. Yes, XOR works for any number of duplicates

B. No, XOR works only if unique element appears once

C. No, XOR only works if all duplicates appear exactly twice

D. Yes, but only if array length is odd

Solution

1. Step 1: Understand XOR behavior with duplicates

   XOR cancels pairs of identical numbers (duplicates appearing twice).

2. Step 2: Analyze effect of triplicate duplicates

   Triplicates do not cancel out with XOR, so result is incorrect.

3. Final Answer:

   No, XOR only works if all duplicates appear exactly twice -> Option C

4. Quick Check:

   XOR cancels pairs, not triplets [OK]

Hint: XOR cancels pairs only, not triplets [OK]

Common Mistakes:

• Assuming XOR works for any duplicate count
• Confusing unique element count with duplicates
• Ignoring XOR cancellation properties