It means removing the last element from an array, making the array one element shorter.
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beginner
In Rust, which method removes the last element from a vector?
The pop() method removes the last element from a vector and returns it as an Option.
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beginner
What happens if you call pop() on an empty vector in Rust?
It returns None, meaning there is no element to remove.
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intermediate
Why is deleting at the end of an array efficient?
Because it does not require shifting other elements, so it runs in constant time (O(1)).
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beginner
Show a simple Rust code snippet to delete the last element from a vector and print the vector.
let mut v = vec![1, 2, 3];
v.pop();
println!("{:?}", v); // Output: [1, 2]
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What does the pop() method do in Rust vectors?
ARemoves the first element
BRemoves the last element and returns it
CAdds an element at the end
DClears the entire vector
✗ Incorrect
The pop() method removes the last element from the vector and returns it wrapped in Some. If the vector is empty, it returns None.
What is the time complexity of deleting the last element from an array?
AO(n)
BO(n^2)
CO(1)
DO(log n)
✗ Incorrect
Deleting the last element is done in constant time because no other elements need to be moved.
If a Rust vector is empty, what does pop() return?
ANone
BAn error
CThe last element
DZero
✗ Incorrect
pop() returns None when the vector is empty, indicating no element was removed.
Which Rust type wraps the result of pop()?
AResult
BVec
CBox
DOption
✗ Incorrect
pop() returns an Option type because the vector might be empty.
What happens to the vector size after calling pop()?
AIt decreases by one
BIt stays the same
CIt increases by one
DIt becomes zero
✗ Incorrect
The vector size decreases by one because the last element is removed.
Explain how to delete the last element from an array or vector and why this operation is efficient.
Think about what happens to the array size and element positions.
You got /4 concepts.
Describe what happens when you call the pop() method on an empty Rust vector.
Consider how Rust handles absence of values safely.
You got /4 concepts.
Practice
(1/5)
1. What happens when you remove the last element from a Rust Vec using pop()?
easy
A. The last element is removed and returned as Some(value).
B. The first element is removed and returned.
C. The entire vector is cleared.
D. The vector becomes immutable.
Solution
Step 1: Understand pop() behavior
The pop() method removes the last element from the vector and returns it wrapped in Some(value) if the vector is not empty.
Step 2: Confirm it does not affect other elements
Only the last element is removed; the rest of the vector remains unchanged.
Final Answer:
The last element is removed and returned as Some(value). -> Option A
Quick Check:
pop() removes last element [OK]
Hint: pop() removes and returns last element wrapped in Some [OK]
Common Mistakes:
Thinking pop() removes the first element
Assuming pop() clears the entire vector
Believing pop() makes vector immutable
2. Which of the following is the correct syntax to remove the last element from a mutable vector v in Rust?
easy
A. v.erase_last();
B. v.remove_last();
C. v.delete_end();
D. v.pop();
Solution
Step 1: Recall Rust vector methods
The standard method to remove the last element from a vector is pop().
Step 2: Check method names
Methods like remove_last(), delete_end(), and erase_last() do not exist in Rust's Vec API.
Final Answer:
v.pop(); -> Option D
Quick Check:
Correct method to remove last element is pop() [OK]
Hint: Use pop() to remove last element from vector [OK]
Common Mistakes:
Using non-existent methods like remove_last()
Confusing pop() with remove() which removes by index
Trying to use erase_last() or delete_end() which are invalid
3. What is the output of the following Rust code?
let mut v = vec![10, 20, 30];
let x = v.pop();
println!("{:?}", v);
println!("{:?}", x);
medium
A. [10, 20]
None
B. [10, 20, 30]
None
C. [10, 20]
Some(30)
D. [20, 30]
Some(10)
Solution
Step 1: Understand pop() effect on vector
The pop() removes the last element, which is 30, and returns Some(30).
Step 2: Check vector after pop
After removal, the vector contains [10, 20].
Final Answer:
[10, 20]
Some(30) -> Option C
Quick Check:
pop() removes last element 30, vector left with [10, 20] [OK]
Hint: pop() returns last element and shortens vector [OK]
Common Mistakes:
Expecting pop() to remove first element
Assuming pop() returns None when vector is not empty
Confusing vector contents after pop
4. Identify the error in the following Rust code that tries to remove the last element from a vector:
let v = vec![1, 2, 3];
v.pop();
medium
A. pop() method does not exist for vectors.
B. Cannot call pop() on an immutable vector.
C. pop() removes the first element, not the last.
D. The vector must be empty before calling pop().
Solution
Step 1: Check vector mutability
The vector v is declared immutable with let. To modify it, it must be mutable.
Step 2: Understand pop() requirements
The pop() method requires a mutable vector to remove the last element.
Final Answer:
Cannot call pop() on an immutable vector. -> Option B
Quick Check:
pop() needs mutable vector [OK]
Hint: Make vector mutable with 'mut' before pop() [OK]
Common Mistakes:
Trying to pop from immutable vector
Thinking pop() removes first element
Assuming pop() works on empty vector without error
5. Given a vector v with elements [5, 10, 15, 20], write Rust code to remove the last two elements and print the resulting vector. What will be printed?
hard
A. [5, 10]
B. [5, 10, 15]
C. [15, 20]
D. [5, 10, 15, 20]
Solution
Step 1: Remove last element twice using pop()
Calling pop() twice removes 20 then 15, leaving [5, 10].
Step 2: Print the vector after removals
Printing v now shows [5, 10].
Final Answer:
[5, 10] -> Option A
Quick Check:
Two pops remove last two elements [OK]
Hint: Call pop() twice to remove last two elements [OK]
Common Mistakes:
Removing only one element instead of two
Confusing pop() with remove(index)
Expecting vector to be empty after two pops
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