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DSA Pythonprogramming~20 mins

Overlapping Subproblems and Optimal Substructure in DSA Python - Practice Problems & Challenges

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Challenge - 5 Problems
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Master of Overlapping Subproblems and Optimal Substructure
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❓ Predict Output
intermediate
2:00remaining
Output of Fibonacci with Memoization
What is the output of the following Python code that uses memoization to compute Fibonacci numbers?
DSA Python
def fib(n, memo={}):
    if n in memo:
        return memo[n]
    if n <= 1:
        return n
    memo[n] = fib(n-1, memo) + fib(n-2, memo)
    return memo[n]

print(fib(5))
A5
B8
C13
D3
Attempts:
2 left
💡 Hint
Remember the Fibonacci sequence starts with 0, 1, 1, 2, 3, 5...
🧠 Conceptual
intermediate
2:00remaining
Identifying Overlapping Subproblems
Which of the following problems best demonstrates the concept of overlapping subproblems?
AComputing Fibonacci numbers using recursion without memoization
BFinding the shortest path in a graph using Dijkstra's algorithm
CCalculating factorial of a number using recursion
DSorting an array using merge sort
Attempts:
2 left
💡 Hint
Overlapping subproblems means the same smaller problems are solved multiple times.
❓ Predict Output
advanced
2:00remaining
Output of Dynamic Programming Table for Coin Change
What is the final value of dp[5] after running this code that counts ways to make change for 5 using coins [1,2,5]?
DSA Python
coins = [1, 2, 5]
dp = [0] * 6
dp[0] = 1
for coin in coins:
    for x in range(coin, 6):
        dp[x] += dp[x - coin]
print(dp[5])
A2
B3
C4
D1
Attempts:
2 left
💡 Hint
Count all combinations of coins that sum to 5.
🔧 Debug
advanced
2:00remaining
Identify the Error in Memoized Fibonacci
What error does this code raise when calling fib(3)?
DSA Python
def fib(n, memo={}):
    if n <= 1:
        return n
    if n in memo:
        return memo[n]
    memo[n] = fib(n-1, memo) + fib(n-2, memo)
    return memo[n]

print(fib(3))
ARecursionError due to infinite recursion
BNo error, output is 2
CTypeError because memo is not a dictionary
DKeyError when accessing memo
Attempts:
2 left
💡 Hint
Check the order of base case and memo check.
🧠 Conceptual
expert
2:00remaining
Optimal Substructure in Shortest Path Problem
Which statement best describes the optimal substructure property in shortest path problems?
AOptimal substructure means the problem can be solved without considering subproblems
BA shortest path can be improved by replacing any subpath with a longer path
CThe shortest path depends on the order of node visits but not on subpaths
DA shortest path between two nodes contains only shortest paths between intermediate nodes
Attempts:
2 left
💡 Hint
Optimal substructure means optimal solutions contain optimal subsolutions.

Practice

(1/5)
1. Which of the following best describes the overlapping subproblems property in dynamic programming?
easy
A. The problem can be broken down into smaller subproblems that are reused multiple times.
B. The problem has a unique solution without repeating any subproblems.
C. The problem requires sorting before solving.
D. The problem can only be solved using recursion without memoization.

Solution

  1. Step 1: Understand overlapping subproblems

    Overlapping subproblems means the same smaller problems appear multiple times during solving.
  2. Step 2: Match definition to options

    The problem can be broken down into smaller subproblems that are reused multiple times. correctly states that subproblems are reused multiple times, which is the key idea.
  3. Final Answer:

    The problem can be broken down into smaller subproblems that are reused multiple times. -> Option A
  4. Quick Check:

    Overlapping subproblems = reuse of subproblems [OK]
Hint: Look for repeated smaller problems in the main problem [OK]
Common Mistakes:
  • Confusing overlapping subproblems with unique subproblems
  • Thinking sorting is required for overlapping subproblems
  • Assuming recursion alone solves overlapping subproblems
2. Which of the following Python function definitions correctly uses memoization to solve overlapping subproblems?
easy
A. def fib(n): if n <= 1: return n else: return fib(n-1) + fib(n-2)
B. def fib(n): return n * fib(n-1)
C. def fib(n): for i in range(n): print(i)
D. def fib(n, memo={}): if n in memo: return memo[n] if n <= 1: memo[n] = n else: memo[n] = fib(n-1, memo) + fib(n-2, memo) return memo[n]

Solution

  1. Step 1: Identify memoization usage

    Memoization stores results of subproblems to avoid repeated work, usually with a dictionary.
  2. Step 2: Check each option

    def fib(n, memo={}): if n in memo: return memo[n] if n <= 1: memo[n] = n else: memo[n] = fib(n-1, memo) + fib(n-2, memo) return memo[n] uses a dictionary 'memo' to save and reuse results, correctly implementing memoization.
  3. Final Answer:

    def fib(n, memo={}): if n in memo: return memo[n] if n <= 1: memo[n] = n else: memo[n] = fib(n-1, memo) + fib(n-2, memo) return memo[n] -> Option D
  4. Quick Check:

    Memoization = caching results [OK]
Hint: Look for a cache (dictionary) storing computed results [OK]
Common Mistakes:
  • Missing memo dictionary parameter
  • Not returning cached results
  • Using loops without caching results
3. What is the output of the following code?
def fib(n, memo={}):
    if n in memo:
        return memo[n]
    if n <= 1:
        memo[n] = n
    else:
        memo[n] = fib(n-1, memo) + fib(n-2, memo)
    return memo[n]

print(fib(5))
medium
A. 13
B. 8
C. 5
D. 3

Solution

  1. Step 1: Trace fib(5) calls with memoization

    fib(5) calls fib(4) and fib(3), which further call smaller fib values, caching results to avoid repeats.
  2. Step 2: Calculate fib(5)

    fib(0)=0, fib(1)=1, fib(2)=1, fib(3)=2, fib(4)=3, fib(5)=5
  3. Final Answer:

    5 -> Option C
  4. Quick Check:

    Fibonacci(5) = 5 [OK]
Hint: Recall Fibonacci sequence: 0,1,1,2,3,5,8... [OK]
Common Mistakes:
  • Confusing fib(5) with fib(6)
  • Ignoring memoization effect
  • Miscounting base cases
4. The following code attempts to use memoization for Fibonacci numbers but has a bug. What is the error?
def fib(n, memo={}):
    if n <= 1:
        return n
    if n not in memo:
        memo[n] = fib(n-1) + fib(n-2)
    return memo[n]

print(fib(4))
medium
A. Missing memo argument in recursive calls causes infinite recursion.
B. Base case is incorrect for n <= 1.
C. Memo dictionary is not initialized.
D. Return statement is missing.

Solution

  1. Step 1: Check recursive calls

    Recursive calls fib(n-1) and fib(n-2) do not pass 'memo', so memo is empty each time.
  2. Step 2: Understand effect of missing memo argument

    Without passing memo, caching fails and recursion repeats infinitely, causing a stack overflow.
  3. Final Answer:

    Missing memo argument in recursive calls causes infinite recursion. -> Option A
  4. Quick Check:

    Pass memo in recursive calls to fix [OK]
Hint: Always pass memo/cache in recursive calls [OK]
Common Mistakes:
  • Forgetting to pass memo in recursive calls
  • Assuming base case alone stops recursion
  • Not initializing memo outside function
5. You want to find the minimum cost to reach the top of stairs where each step has a cost. You can climb 1 or 2 steps at a time. Which approach best uses optimal substructure and overlapping subproblems to solve this?
hard
A. Use recursion without caching to try all paths.
B. Use dynamic programming to store minimum cost for each step and build up solution.
C. Sort the costs and pick the smallest steps first.
D. Use a greedy approach to always pick the next step with minimum cost.

Solution

  1. Step 1: Understand problem structure

    Minimum cost to reach step i depends on minimum cost to reach steps i-1 and i-2 plus cost at i.
  2. Step 2: Apply dynamic programming

    Store minimum costs for each step to avoid recomputing (overlapping subproblems) and use previous results (optimal substructure).
  3. Final Answer:

    Use dynamic programming to store minimum cost for each step and build up solution. -> Option B
  4. Quick Check:

    DP uses optimal substructure + overlapping subproblems [OK]
Hint: Build solution step-by-step storing results [OK]
Common Mistakes:
  • Using recursion without memoization causing slow solution
  • Trying greedy approach which may fail
  • Sorting costs which is irrelevant
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