Minimum Spanning Tree Kruskal's Algorithm in DSA Python - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the parent array for union-find.

DSA Python

parent = [[1] for i in range(n)]

Drag options to blanks, or click blank then click option'

Ai

B0

CNone

D-1

Attempts:

3 left

💡 Hint

Common Mistakes

Setting all parents to 0 causes incorrect union-find behavior.

Using None or -1 breaks the find operation.

Each node is initially its own parent, so we assign parent[i] = i.

2fill in blank

medium

Complete the code to find the root parent of a node with path compression.

DSA Python

def find(x):
    if parent[x] != x:
        parent[x] = [1](parent[x])
    return parent[x]

Drag options to blanks, or click blank then click option'

Aunion

Broot

Cfind

Dparent

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'union' instead of 'find' causes errors.

Using 'parent' or 'root' as function calls is invalid.

The find function calls itself recursively to find the root parent and compress the path.

3fill in blank

hard

Fix the error in the union function to correctly merge two sets.

DSA Python

def union(a, b):
    rootA = find(a)
    rootB = find(b)
    if rootA != rootB:
        parent[[1]] = rootB

Drag options to blanks, or click blank then click option'

ArootA

Bb

Ca

DrootB

Attempts:

3 left

💡 Hint

Common Mistakes

Assigning parent of 'a' or 'b' instead of their roots.

Assigning parent of rootB to rootB (no change).

We assign the parent of rootA to rootB to merge sets.

4fill in blank

hard

Fill in the blank to sort edges by weight.

DSA Python

edges = sorted(edges, key=lambda x: x[1])

Drag options to blanks, or click blank then click option'

A(1)

B(2)

C[1]

D[2]

Attempts:

3 left

💡 Hint

Common Mistakes

Using parentheses like (2) causes TypeError (tuple not callable).

Using index 1 or 0 sorts by node IDs instead of weight.

Edges are tuples (u, v, w); the weight is at index 2, accessed by x[2].

5fill in blank

hard

Fill all three blanks to add edge weight to result if union is successful.

DSA Python

result = 0
for u, v, w in edges:
    if find(u) != find(v):
        union([1], [2])
        result [3]= w

Drag options to blanks, or click blank then click option'

Au

Bv

C+

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong variables in union causes wrong merges.

Using '-=' instead of '+=' subtracts weight incorrectly.

We union the two nodes u and v, and add the weight w to the result.

Practice

1. What is the main goal of Kruskal's algorithm in graph theory?

easy

A. To find the shortest path between two nodes

B. To find the minimum spanning tree of a graph

C. To detect cycles in a graph

D. To find the maximum flow in a network

Solution

1. Step 1: Understand Kruskal's algorithm purpose

   Kruskal's algorithm is designed to find a subset of edges that connects all vertices with the minimum total edge weight.

2. Step 2: Compare with other graph problems

   Shortest path, cycle detection, and max flow are different problems with different algorithms.

3. Final Answer:

   To find the minimum spanning tree of a graph -> Option B

4. Quick Check:

   Kruskal's algorithm = Minimum Spanning Tree [OK]

Hint: Kruskal always builds minimum spanning tree by edge weights [OK]

Common Mistakes:

• Confusing MST with shortest path
• Thinking it detects cycles only
• Mixing with max flow problems

2. Which of the following is the correct syntax to sort edges by weight in Python for Kruskal's algorithm?

easy

A. edges.sort(key=lambda x: x[2])

B. edges.sort(key=lambda x: x[1])

C. edges.sort()

D. edges.sort(key=lambda x: x[0])

Solution

1. Step 1: Identify edge structure

   Edges are usually stored as tuples (node1, node2, weight), so weight is at index 2.

2. Step 2: Use sort with key on weight

   Sorting by weight means sorting by the third element, so key=lambda x: x[2] is correct.

3. Final Answer:

   edges.sort(key=lambda x: x[2]) -> Option A

4. Quick Check:

   Sort edges by weight = key=lambda x: x[2] [OK]

Hint: Weight is usually third element in edge tuple [OK]

Common Mistakes:

• Sorting by wrong tuple index
• Using sort() without key when edges are tuples
• Confusing node indices with weight index

3. What is the output of the following code snippet that applies Kruskal's algorithm on a graph with edges [(0, 1, 10), (0, 2, 6), (0, 3, 5), (1, 3, 15), (2, 3, 4)]?

edges = [(0, 1, 10), (0, 2, 6), (0, 3, 5), (1, 3, 15), (2, 3, 4)]
edges.sort(key=lambda x: x[2])
parent = list(range(4))
def find(x):
    while parent[x] != x:
        x = parent[x]
    return x
def union(a, b):
    rootA = find(a)
    rootB = find(b)
    if rootA != rootB:
        parent[rootB] = rootA
        return True
    return False
mst = []
for u, v, w in edges:
    if union(u, v):
        mst.append((u, v, w))
print(mst)

medium

A. [(0, 2, 6), (0, 3, 5), (2, 3, 4)]

B. [(0, 3, 5), (2, 3, 4), (1, 3, 15)]

C. [(0, 1, 10), (0, 2, 6), (1, 3, 15)]

D. [(2, 3, 4), (0, 3, 5), (0, 1, 10)]

Solution

1. Step 1: Sort edges by weight

   Sorted edges: (2,3,4), (0,3,5), (0,2,6), (0,1,10), (1,3,15)

2. Step 2: Apply union-find to select edges without cycles

   Pick (2,3,4), union success; pick (0,3,5), union success; pick (0,2,6), union fails (cycle); pick (0,1,10), union success; stop as MST has 3 edges for 4 nodes.

3. Final Answer:

   [(2, 3, 4), (0, 3, 5), (0, 1, 10)] -> Option D

4. Quick Check:

   Edges chosen = minimum weights without cycles [OK]

Hint: Sort edges, pick smallest without cycle until MST complete [OK]

Common Mistakes:

• Not sorting edges correctly
• Adding edges that form cycles
• Stopping too early or too late

4. Identify the bug in this Kruskal's algorithm snippet and select the fix:

edges = [(0,1,1), (1,2,2), (0,2,3)]
parent = [0, 1, 2]
def find(x):
    if parent[x] == x:
        return x
    return find(parent[x])
def union(a, b):
    rootA = find(a)
    rootB = find(b)
    if rootA != rootB:
        parent[a] = b  # Bug here
        return True
    return False
mst = []
for u,v,w in sorted(edges, key=lambda x: x[2]):
    if union(u,v):
        mst.append((u,v,w))
print(mst)

medium

A. Change 'parent[a] = b' to 'parent[rootB] = rootA'

B. Change 'parent[a] = b' to 'parent[rootA] = rootB'

C. Change 'parent[a] = b' to 'parent[b] = a'

D. No bug, code is correct

Solution

1. Step 1: Analyze union function

   Union should link roots of sets, not original nodes directly.

2. Step 2: Fix parent assignment

   Assign parent of rootB to rootA to merge sets correctly: 'parent[rootB] = rootA'.

3. Final Answer:

   Change 'parent[a] = b' to 'parent[rootB] = rootA' -> Option A

4. Quick Check:

   Union sets by root parents, not nodes [OK]

Hint: Always union by root parents, not direct nodes [OK]

Common Mistakes:

• Assigning parent of node instead of root
• Confusing rootA and rootB in assignment
• Skipping path compression in find

5. Given a graph with vertices 0 to 4 and edges [(0,1,2), (0,3,6), (1,2,3), (1,3,8), (1,4,5), (2,4,7), (3,4,9)], what is the total weight of the minimum spanning tree found by Kruskal's algorithm?

hard

A. 19

B. 20

C. 16

D. 18

Solution

1. Step 1: Sort edges by weight

   Sorted edges: (0,1,2), (1,2,3), (1,4,5), (0,3,6), (2,4,7), (1,3,8), (3,4,9)

2. Step 2: Select edges without cycles until all vertices connected

   Pick (0,1,2), (1,2,3), (1,4,5), (0,3,6). Total weight = 2+3+5+6 = 16. But check if (2,4,7) creates cycle: yes, skip. (1,3,8) and (3,4,9) create cycles, skip.

3. Step 3: Verify MST completeness

   All 5 vertices connected with 4 edges, total weight 16.

4. Final Answer:

   16 -> Option C

5. Quick Check:

   MST total weight = sum of chosen edges [OK]

Hint: Sum smallest edges connecting all nodes without cycles [OK]

Common Mistakes:

• Including edges that form cycles
• Missing edges needed to connect all vertices
• Adding heavier edges unnecessarily