Memoization is a technique to store the results of expensive function calls and reuse them when the same inputs occur again, avoiding repeated calculations.
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beginner
How does memoization improve the performance of recursive functions?
It saves previously computed results in a cache, so the function does not recompute the same values multiple times, reducing time complexity.
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beginner
In Python, which data structure is commonly used to implement memoization?
A dictionary is commonly used to store input-output pairs for memoization in Python.
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intermediate
What is the difference between memoization and dynamic programming?
Memoization is a top-down approach that caches results during recursion, while dynamic programming is often a bottom-up approach that builds solutions iteratively.
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beginner
Show a simple example of memoization for the Fibonacci sequence in Python.
def fib(n, memo={}):
if n in memo:
return memo[n]
if n <= 1:
return n
memo[n] = fib(n-1, memo) + fib(n-2, memo)
return memo[n]
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What problem does memoization solve in recursive functions?
AAvoids repeated calculations by caching results
BMakes the function run in parallel
CChanges recursion to iteration
DRemoves the need for base cases
✗ Incorrect
Memoization stores results of function calls to avoid recalculating the same values.
Which Python data structure is best suited for memoization?
ASet
BList
CTuple
DDictionary
✗ Incorrect
Dictionaries store key-value pairs, perfect for caching inputs and outputs.
What is the time complexity improvement when using memoization for Fibonacci numbers?
AFrom exponential to linear
BFrom linear to constant
CFrom quadratic to exponential
DNo improvement
✗ Incorrect
Memoization reduces Fibonacci calculation from exponential time to linear time.
Memoization is an example of which programming technique?
ADivide and conquer
BGreedy algorithm
CDynamic programming
DBacktracking
✗ Incorrect
Memoization is a top-down dynamic programming technique.
What happens if you forget to add a base case in a recursive function with memoization?
AMemoization will fix the problem automatically
BFunction will run infinitely or cause an error
CFunction will return zero
DFunction will run faster
✗ Incorrect
Base cases stop recursion; without them, recursion never ends.
Explain how memoization works to optimize a recursive Fibonacci function.
Think about storing answers to smaller problems to avoid recalculating.
You got /4 concepts.
Describe the difference between memoization and a simple recursive approach without optimization.
Focus on what changes in how the function handles repeated inputs.
You got /4 concepts.
Practice
(1/5)
1. What is the main purpose of using memoization in recursive functions?
easy
A. To replace recursion with iteration
B. To make the function run slower by adding extra steps
C. To store results of expensive function calls and reuse them
D. To increase the memory usage without any benefit
Solution
Step 1: Understand what memoization does
Memoization saves the results of function calls so that if the same inputs occur again, the function can return the saved result instead of recalculating.
Step 2: Identify the benefit of memoization
This saves time by avoiding repeated calculations, making recursive functions faster.
Final Answer:
To store results of expensive function calls and reuse them -> Option C
Quick Check:
Memoization = Store and reuse results [OK]
Hint: Memoization saves repeated work by caching results [OK]
Common Mistakes:
Thinking memoization slows down the function
Confusing memoization with converting recursion to loops
Believing memoization always increases memory without benefit
2. Which of the following is the correct way to define a memo dictionary inside a recursive function in Python?
easy
A. def fib(n, memo={}):
B. def fib(n, memo=None): memo = {}
C. def fib(n, memo=[]):
D. def fib(n, memo=0):
Solution
Step 1: Understand default mutable arguments problem
Using a mutable default argument like a dictionary directly can cause unexpected behavior because the same dictionary is shared across calls.
Step 2: Use None as default and initialize inside
Setting memo=None and then initializing memo = {} inside the function avoids this problem and is the correct pattern.
Final Answer:
def fib(n, memo=None): memo = {} -> Option B
Quick Check:
Use None default and initialize dict inside [OK]
Hint: Use None default and create dict inside function [OK]
Common Mistakes:
Using mutable default arguments directly
Using list instead of dictionary for memo
Setting memo default to 0 which is invalid
3. What will be the output of the following code?
def fib(n, memo=None):
if memo is None:
memo = {}
if n in memo:
return memo[n]
if n <= 1:
return n
memo[n] = fib(n-1, memo) + fib(n-2, memo)
return memo[n]
print(fib(5))
medium
A. 8
B. None
C. 3
D. 5
Solution
Step 1: Trace fib(5) with memoization
fib(5) = fib(4) + fib(3), fib(4) = fib(3) + fib(2), and so on. Using memoization avoids repeated calls.
Hint: Remember fib(5) = 5 in Fibonacci sequence [OK]
Common Mistakes:
Confusing fib(5) with fib(6)
Ignoring memo and recalculating values
Returning None due to missing return
4. Identify the error in this memoized factorial function and select the fix:
def factorial(n, memo=None):
if memo is None:
memo = {}
if n == 0:
return 1
if n in memo:
return memo[n]
memo[n] = n * factorial(n-1)
return memo[n]
medium
A. Add memo argument in recursive call: factorial(n-1, memo)
B. Change base case to n == 1
C. Initialize memo as a list instead of dict
D. Remove memo dictionary completely
Solution
Step 1: Check recursive call parameters
The recursive call factorial(n-1) misses passing memo, so memo is reset each time, losing stored results.
Step 2: Fix by passing memo in recursive call
Change to factorial(n-1, memo) to keep using the same memo dictionary.
Final Answer:
Add memo argument in recursive call: factorial(n-1, memo) -> Option A
Quick Check:
Pass memo in recursion to keep cache [OK]
Hint: Always pass memo in recursive calls [OK]
Common Mistakes:
Forgetting to pass memo in recursive call
Changing base case unnecessarily
Using list instead of dictionary for memo
5. You want to optimize a recursive function that calculates the number of ways to climb n stairs, taking 1 or 2 steps at a time. Which memoization approach below correctly avoids redundant calculations and handles edge cases?
hard
A. Use memo=None default, initialize inside, pass memo in recursive calls, and handle base cases for n=0 and n=1
B. Use a default mutable argument dictionary and update it inside the function
C. Do not use memoization; rely on simple recursion for clarity
D. Use a global dictionary outside the function to store results and pass n only
Solution
Step 1: Understand memoization best practice
Using memo=None default and initializing inside avoids shared mutable defaults and ensures fresh memo per call.
Step 2: Pass memo in recursive calls and handle base cases
Passing memo keeps cache consistent. Base cases n=0 (1 way) and n=1 (1 way) prevent infinite recursion and define correct results.
Final Answer:
Use memo=None default, initialize inside, pass memo in recursion, handle base cases -> Option A
Quick Check:
Proper memo init and passing + base cases = correct [OK]
Hint: Initialize memo inside and pass it in recursion [OK]
Common Mistakes:
Using global variables causing side effects
Using mutable default arguments directly
Ignoring base cases causing infinite recursion
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