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DP on Trees Maximum Path Sum in DSA Python - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is the main goal of the DP on Trees Maximum Path Sum problem?
To find the maximum sum of values along any path in a tree, where a path can start and end at any nodes.
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intermediate
In DP on Trees Maximum Path Sum, why do we use a post-order traversal?
Because we need to calculate the maximum path sums of child nodes before computing the parent's maximum path sum, ensuring all child information is ready.
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intermediate
What does the 'single path max sum' represent in the DP on Trees Maximum Path Sum solution?
It represents the maximum sum of a path starting from the current node and extending down to one of its children, or just the node itself if children reduce the sum.
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advanced
How do we update the global maximum path sum during the DP on Trees Maximum Path Sum computation?
At each node, we consider the sum of the node's value plus the maximum path sums from both left and right children (if any), and update the global max if this sum is larger.
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intermediate
Why do we ignore negative path sums from children in the DP on Trees Maximum Path Sum problem?
Because including negative sums would reduce the total path sum, so we treat negative sums as zero to maximize the path sum.
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What traversal is best suited for solving the DP on Trees Maximum Path Sum problem?
APre-order traversal
BPost-order traversal
CIn-order traversal
DLevel-order traversal
When calculating the maximum path sum at a node, which of these is NOT considered?
ANode's own value
BMaximum path sum from left child
CMinimum path sum from children
DMaximum path sum from right child
Why do we treat negative child path sums as zero in this problem?
ATo avoid decreasing the total path sum
BBecause negative sums are invalid
CTo simplify the code
DBecause the tree has only positive values
What does the global maximum path sum represent in this problem?
AThe largest sum of any path in the tree
BThe sum of all nodes in the tree
CThe maximum sum from root to leaf
DThe minimum sum path in the tree
Which of these paths can be considered when finding the maximum path sum in a tree?
AOnly paths from root to leaf
BOnly paths that include the root
COnly paths from leaf to leaf
DPaths starting and ending at any nodes
Explain how dynamic programming is applied to find the maximum path sum in a tree.
Think about how you combine child results to solve the parent's problem.
You got /5 concepts.
    Describe the difference between the 'single path max sum' and the 'global maximum path sum' in this problem.
    One is local to a node and returned up, the other is the best overall found so far.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the "maximum path sum" in a binary tree represent?
      Maximum path sum means:
      easy
      A. The largest sum of node values along any path between two nodes
      B. The sum of all node values in the tree
      C. The maximum value of a single node in the tree
      D. The longest path length in the tree

      Solution

      1. Step 1: Understand the path definition

        A path in a tree is any sequence of nodes connected by edges, not necessarily starting at the root.
      2. Step 2: Define maximum path sum meaning

        The maximum path sum is the highest sum of node values along any such path, which can start and end anywhere.
      3. Final Answer:

        The largest sum of node values along any path between two nodes -> Option A
      4. Quick Check:

        Maximum path sum = largest node value sum [OK]
      Hint: Maximum path sum is about sums, not counts or single nodes [OK]
      Common Mistakes:
      • Confusing path sum with total tree sum
      • Thinking path must start at root
      • Considering only single nodes
      2. Which of the following Python function signatures is correct for a recursive helper to find maximum path sum in a binary tree node?
      def max_path_sum_helper(node: Optional[TreeNode]) -> int:
      easy
      A. def max_path_sum_helper(node: TreeNode) -> int:
      B. def max_path_sum_helper(node: int) -> TreeNode:
      C. def max_path_sum_helper(node: Optional[TreeNode]) -> int:
      D. def max_path_sum_helper(node: TreeNode) -> None:

      Solution

      1. Step 1: Understand parameter type

        The node can be None (empty), so Optional[TreeNode] is correct to allow None.
      2. Step 2: Understand return type

        The helper returns an integer representing max path sum from that node, so return type is int.
      3. Final Answer:

        def max_path_sum_helper(node: Optional[TreeNode]) -> int: -> Option C
      4. Quick Check:

        Optional node input and int output [OK]
      Hint: Use Optional for nullable nodes and int return for sums [OK]
      Common Mistakes:
      • Not allowing None as input node
      • Returning wrong type like None or TreeNode
      • Using wrong parameter types
      3. What is the output of the following code snippet?
      class TreeNode:
          def __init__(self, val=0, left=None, right=None):
              self.val = val
              self.left = left
              self.right = right
      
      def max_path_sum(root):
          max_sum = float('-inf')
          def helper(node):
              nonlocal max_sum
              if not node:
                  return 0
              left = max(helper(node.left), 0)
              right = max(helper(node.right), 0)
              max_sum = max(max_sum, node.val + left + right)
              return node.val + max(left, right)
          helper(root)
          return max_sum
      
      root = TreeNode(-10, TreeNode(9), TreeNode(20, TreeNode(15), TreeNode(7)))
      print(max_path_sum(root))
      medium
      A. 35
      B. 42
      C. 27
      D. 20

      Solution

      1. Step 1: Calculate max path sums for subtrees

        Left subtree max path sum is 9. Right subtree max path sum includes 20 + 15 + 7 = 42.
      2. Step 2: Calculate max path sum including root

        Root value is -10, so max path sum including root is max(9, 0) + -10 + max(35, 0) = 34, but max_sum is updated to 42 from right subtree.
      3. Final Answer:

        42 -> Option B
      4. Quick Check:

        Max path sum = 15+20+7 = 42 [OK]
      Hint: Ignore negative sums by max with 0 to maximize path [OK]
      Common Mistakes:
      • Adding negative paths instead of ignoring
      • Confusing return value with max_sum
      • Missing nonlocal max_sum update
      4. Find the bug in this code for maximum path sum in a binary tree:
      def max_path_sum(root):
          max_sum = float('-inf')
          def helper(node):
              if not node:
                  return 0
              left = helper(node.left)
              right = helper(node.right)
              max_sum = max(max_sum, node.val + left + right)
              return node.val + max(left, right)
          helper(root)
          return max_sum
      medium
      A. max_sum is not declared as nonlocal inside helper
      B. helper returns wrong value for leaf nodes
      C. Should return max_sum inside helper function
      D. Missing base case for empty tree

      Solution

      1. Step 1: Check variable scope of max_sum

        max_sum is assigned inside helper but declared outside, so it needs 'nonlocal' to modify outer variable.
      2. Step 2: Understand effect of missing nonlocal

        Without 'nonlocal', max_sum inside helper is local, so outer max_sum never updates, causing wrong result.
      3. Final Answer:

        max_sum is not declared as nonlocal inside helper -> Option A
      4. Quick Check:

        Use nonlocal to update outer max_sum [OK]
      Hint: Declare nonlocal for outer variables modified inside nested functions [OK]
      Common Mistakes:
      • Forgetting nonlocal keyword
      • Returning max_sum inside helper incorrectly
      • Ignoring base case for None nodes
      5. Given a binary tree where nodes can have negative values, how would you modify the maximum path sum algorithm to handle the case where all node values are negative?
      Choose the best approach:
      hard
      A. Add absolute values of nodes to maximize sum
      B. Ignore negative values and return 0 as max path sum
      C. Only consider paths starting at the root
      D. Return the maximum single node value if all sums are negative

      Solution

      1. Step 1: Understand negative values impact

        If all nodes are negative, the maximum path sum is the largest (least negative) single node value, since no path sums to 0 and longer paths sum to less.
      2. Step 2: Modify algorithm to track max single node

        Keep track of the maximum node value separately and return it if all path sums are negative.
      3. Final Answer:

        Return the maximum single node value if all sums are negative -> Option D
      4. Quick Check:

        Handle all-negative by max single node value [OK]
      Hint: Track max node value separately to handle all negatives [OK]
      Common Mistakes:
      • Returning 0 when all nodes are negative
      • Adding absolute values incorrectly
      • Restricting paths to root only
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