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DSA Pythonprogramming~30 mins

Buy and Sell Stocks All Variants in DSA Python - Build from Scratch

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Buy and Sell Stocks All Variants
📖 Scenario: You are helping a friend who wants to understand how to make money by buying and selling stocks. They have a list of stock prices for several days and want to find the best way to buy and sell to maximize profit.
🎯 Goal: Build a simple program that finds the maximum profit from buying and selling stocks once, then extend it to multiple transactions, and finally print the results.
📋 What You'll Learn
Create a list called prices with exact daily stock prices
Create a variable called max_profit initialized to 0
Write a loop to find the maximum profit from one buy and one sell
Print the max_profit value
💡 Why This Matters
🌍 Real World
This project helps understand how to analyze stock prices to make smart buy and sell decisions for profit.
💼 Career
Knowing how to find maximum profit from stock prices is useful in finance, trading, and algorithmic problem solving.
Progress0 / 4 steps
1
Create the stock prices list
Create a list called prices with these exact values: [7, 1, 5, 3, 6, 4]
DSA Python
Hint

Use square brackets to create a list and separate numbers with commas.

2
Set up the max profit variable
Create a variable called max_profit and set it to 0
DSA Python
Hint

Use an integer variable to keep track of the best profit found so far.

3
Find the maximum profit from one transaction
Create a variable called min_price and set it to the first price in prices. Then use a for loop with variable price to go through each price in prices. Inside the loop, update min_price to the smaller of min_price and price. Also update max_profit to the larger of max_profit and price - min_price.
DSA Python
Hint

Keep track of the lowest price so far and calculate profit by subtracting it from the current price.

4
Print the maximum profit
Write a print statement to display the value of max_profit
DSA Python
Hint

The maximum profit is the highest difference between a later price and an earlier lower price.

Practice

(1/5)
1. What is the main goal when solving the Buy and Sell Stocks problem variants?
easy
A. Find the day with the lowest stock price only
B. Minimize the number of transactions regardless of profit
C. Maximize the profit by choosing the best days to buy and sell stocks
D. Calculate the average stock price over all days

Solution

  1. Step 1: Understand the problem goal

    The problem asks to find the best days to buy and sell stocks to get the highest profit.
  2. Step 2: Identify the objective

    Maximizing profit means buying low and selling high at the right times.
  3. Final Answer:

    Maximize the profit by choosing the best days to buy and sell stocks -> Option C
  4. Quick Check:

    Goal = Maximize profit [OK]
Hint: Focus on profit maximization, not just prices or counts [OK]
Common Mistakes:
  • Thinking the goal is to minimize transactions
  • Only finding lowest price day without selling
  • Calculating averages instead of profit
2. Which of the following Python code snippets correctly initializes variables to track minimum price and maximum profit for the stock problem?
easy
A. min_price = float('inf'); max_profit = 0
B. min_price = 0; max_profit = float('-inf')
C. min_price = None; max_profit = None
D. min_price = 0; max_profit = 0

Solution

  1. Step 1: Understand initialization needs

    We want min_price to start very high so any price is lower, and max_profit to start at zero.
  2. Step 2: Check each option

    min_price = float('inf'); max_profit = 0 sets min_price to infinity and max_profit to zero, which is correct for tracking minimum and maximum values.
  3. Final Answer:

    min_price = float('inf'); max_profit = 0 -> Option A
  4. Quick Check:

    Initialization = min_price high, max_profit zero [OK]
Hint: Use infinity for min_price start, zero for max_profit [OK]
Common Mistakes:
  • Setting min_price to zero causes wrong minimum tracking
  • Using None without checks causes errors
  • Setting max_profit to negative infinity can confuse logic
3. What is the output of the following code snippet for prices = [7,1,5,3,6,4]?
min_price = float('inf')
max_profit = 0
for price in prices:
    if price < min_price:
        min_price = price
    elif price - min_price > max_profit:
        max_profit = price - min_price
print(max_profit)
medium
A. 6
B. 7
C. 4
D. 5

Solution

  1. Step 1: Trace the loop with given prices

    Prices: 7,1,5,3,6,4 - Start min_price=inf, max_profit=0 - price=7: min_price=7 - price=1: min_price=1 (lower) - price=5: profit=5-1=4 > 0, max_profit=4 - price=3: profit=3-1=2 < 4, no change - price=6: profit=6-1=5 > 4, max_profit=5 - price=4: profit=4-1=3 < 5, no change
  2. Step 2: Final max_profit after loop

    max_profit is 5 after checking all prices.
  3. Final Answer:

    5 -> Option D
  4. Quick Check:

    Max profit = 5 [OK]
Hint: Track min price and update max profit on higher prices [OK]
Common Mistakes:
  • Confusing max profit with max price
  • Not updating min_price correctly
  • Calculating profit incorrectly
4. Identify the error in this code snippet for the stock problem:
prices = [7,1,5,3,6,4]
min_price = 0
max_profit = 0
for price in prices:
    if price < min_price:
        min_price = price
    elif price - min_price > max_profit:
        max_profit = price - min_price
print(max_profit)
medium
A. Loop should start from second element
B. min_price initialized to 0 instead of a high value
C. max_profit should start at float('inf')
D. Using elif instead of if causes logic error

Solution

  1. Step 1: Check variable initialization

    min_price is set to 0, but prices include values greater than 0, so min_price never updates to actual minimum (1).
  2. Step 2: Effect of wrong min_price initialization

    Since min_price=0, price < min_price is never true, so min_price stays 0, causing incorrect profit calculations.
  3. Final Answer:

    min_price initialized to 0 instead of a high value -> Option B
  4. Quick Check:

    min_price must start high to track minimum [OK]
Hint: Initialize min_price to infinity, not zero [OK]
Common Mistakes:
  • Starting min_price at zero causes wrong minimum tracking
  • Confusing max_profit initialization
  • Thinking elif causes logic error here
5. Given the prices array [3,3,5,0,0,3,1,4], what is the maximum profit with at most two transactions?
hard
A. 6
B. 7
C. 5
D. 4

Solution

  1. Step 1: Understand two transactions limit

    We can buy and sell stocks at most twice to maximize total profit.
  2. Step 2: Calculate profits for two transactions

    First transaction: buy at 3, sell at 5 = 2 profit Second transaction: buy at 0, sell at 4 = 4 profit Total profit = 2 + 4 = 6
  3. Final Answer:

    6 -> Option A
  4. Quick Check:

    Two transactions max profit = 6 [OK]
Hint: Split array, find max profit in two parts [OK]
Common Mistakes:
  • Counting overlapping transactions
  • Only considering one transaction
  • Adding profits incorrectly
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10 questions~5 mineasy hard