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DSA Javascriptprogramming~20 mins

Recursion vs Iteration When Each Wins in DSA Javascript - Compare & Choose

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Challenge - 5 Problems
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Recursion vs Iteration Master
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❓ Predict Output
intermediate
2:00remaining
Output of Recursive vs Iterative Factorial
What is the output of the following JavaScript code that calculates factorial using recursion and iteration?
DSA Javascript
function factorialRecursive(n) {
  if (n === 0) return 1;
  return n * factorialRecursive(n - 1);
}

function factorialIterative(n) {
  let result = 1;
  for (let i = 1; i <= n; i++) {
    result *= i;
  }
  return result;
}

console.log(factorialRecursive(5));
console.log(factorialIterative(5));
A120\n120
BError\n120
C120\n24
D24\n120
Attempts:
2 left
💡 Hint
Both functions calculate factorial of 5 but use different approaches.
🧠 Conceptual
intermediate
1:30remaining
When is recursion preferred over iteration?
Which scenario best explains when recursion is preferred over iteration?
AWhen memory usage must be minimal and stack overflow is a risk.
BWhen you want to avoid function call overhead and use simple loops.
CWhen the problem requires only a single loop with no nested calls.
DWhen the problem naturally fits a divide-and-conquer approach like tree traversal.
Attempts:
2 left
💡 Hint
Think about problems that break down into smaller similar problems.
❓ Predict Output
advanced
2:00remaining
Output of Recursive Fibonacci with Memoization
What is the output of this JavaScript code that calculates Fibonacci numbers using recursion with memoization?
DSA Javascript
function fibMemo(n, memo = {}) {
  if (n <= 1) return n;
  if (memo[n]) return memo[n];
  memo[n] = fibMemo(n - 1, memo) + fibMemo(n - 2, memo);
  return memo[n];
}

console.log(fibMemo(7));
A21
B13
C8
DError
Attempts:
2 left
💡 Hint
Fibonacci sequence starts 0,1,1,2,3,5,8,13...
🔧 Debug
advanced
2:00remaining
Identify the error in recursive sum function
What error does this recursive sum function produce when called with sumRecursive([1,2,3])?
DSA Javascript
function sumRecursive(arr) {
  if (arr.length === 0) return 0;
  return arr[0] + sumRecursive(arr.slice(1));
}

console.log(sumRecursive([1,2,3]));
A6
BTypeError: arr.slice is not a function
CRangeError: Maximum call stack size exceeded
DReferenceError: sumRecursive is not defined
Attempts:
2 left
💡 Hint
Check if the function correctly handles array slicing and recursion.
🚀 Application
expert
2:30remaining
Choosing between recursion and iteration for large input
You need to process a large dataset with a depth of 10,000 levels. Which approach is best to avoid stack overflow and why?
AUse recursion because it is always faster than iteration.
BUse recursion because JavaScript automatically optimizes deep recursion.
CUse iteration because recursion may cause stack overflow with deep calls.
DUse recursion with no memoization to save memory.
Attempts:
2 left
💡 Hint
Consider JavaScript call stack limits and how iteration handles deep loops.

Practice

(1/5)
1. Which scenario is best suited for using recursion instead of iteration?
easy
A. When the problem requires simple repeated loops
B. When the problem can be divided into smaller similar subproblems
C. When you want to avoid function call overhead
D. When memory usage must be minimal

Solution

  1. Step 1: Understand recursion use case

    Recursion works well when a problem can be broken down into smaller versions of itself, like tree traversals or factorial calculation.
  2. Step 2: Compare with iteration scenarios

    Iteration is better for simple repeated tasks without nested subproblems, so recursion is preferred for divide-and-conquer problems.
  3. Final Answer:

    When the problem can be divided into smaller similar subproblems -> Option B
  4. Quick Check:

    Recursion fits divide-and-conquer = C [OK]
Hint: Recursion fits problems breaking into smaller similar parts [OK]
Common Mistakes:
  • Thinking iteration is always faster
  • Ignoring function call overhead in recursion
  • Confusing simple loops with recursive problems
2. Which of the following is the correct syntax for a recursive function in JavaScript?
easy
A. function recurse(n) { while(n > 0) { n--; } return n; }
B. function recurse(n) { for(let i=0; i
C. function recurse(n) { if (n <= 0) return 0; return n + recurse(n - 1); }
D. function recurse(n) { if(n > 0) { return n * recurse(n + 1); } else { return 1; } }

Solution

  1. Step 1: Identify recursive call and base case

    function recurse(n) { if (n <= 0) return 0; return n + recurse(n - 1); } has a base case (n <= 0) and calls itself with a smaller argument (n - 1), which is correct recursion.
  2. Step 2: Check other options for recursion errors

    function recurse(n) { while(n > 0) { n--; } return n; } uses a loop, not recursion. function recurse(n) { for(let i=0; i 0) { return n * recurse(n + 1); } else { return 1; } } calls recurse with n + 1, causing infinite recursion.
  3. Final Answer:

    function recurse(n) { if (n <= 0) return 0; return n + recurse(n - 1); } -> Option C
  4. Quick Check:

    Base case + smaller recursive call = B [OK]
Hint: Look for base case and smaller recursive call [OK]
Common Mistakes:
  • Missing base case causing infinite recursion
  • Using loops instead of recursive calls
  • Increasing argument in recursive call causing stack overflow
3. What is the output of the following JavaScript code?
function factorial(n) {
  if (n === 0) return 1;
  return n * factorial(n - 1);
}
console.log(factorial(4));
medium
A. 24
B. 10
C. 16
D. Error

Solution

  1. Step 1: Trace recursive calls for factorial(4)

    factorial(4) calls factorial(3), factorial(3) calls factorial(2), factorial(2) calls factorial(1), factorial(1) calls factorial(0) which returns 1.
  2. Step 2: Calculate return values step-by-step

    factorial(1) = 1 * 1 = 1, factorial(2) = 2 * 1 = 2, factorial(3) = 3 * 2 = 6, factorial(4) = 4 * 6 = 24.
  3. Final Answer:

    24 -> Option A
  4. Quick Check:

    4! = 24 [OK]
Hint: Factorial n! = n * (n-1)! [OK]
Common Mistakes:
  • Confusing factorial with sum
  • Forgetting base case returns 1
  • Miscomputing multiplication order
4. Identify the error in this recursive function and choose the fix:
function sumTo(n) {
  if (n === 1) return 1;
  return n + sumTo(n);
}
medium
A. Change return to console.log
B. Add a base case for n === 0
C. Replace recursion with a for loop
D. Change sumTo(n) to sumTo(n - 1) in the return statement

Solution

  1. Step 1: Analyze recursive call argument

    The function calls sumTo(n) again without changing n, causing infinite recursion and stack overflow.
  2. Step 2: Fix recursive call to reduce problem size

    Changing sumTo(n) to sumTo(n - 1) reduces n each call, eventually reaching base case n === 1.
  3. Final Answer:

    Change sumTo(n) to sumTo(n - 1) in the return statement -> Option D
  4. Quick Check:

    Recursive call must reduce argument = A [OK]
Hint: Recursive calls must progress toward base case [OK]
Common Mistakes:
  • Calling function with same argument causing infinite loop
  • Missing or wrong base case
  • Confusing recursion with iteration fixes
5. You want to process a large list of numbers to find their sum. Which approach is better and why?
hard
A. Iteration is better because it uses less memory and avoids stack overflow
B. Recursion is better because it is easier to write for large lists
C. Recursion with memoization is best for summing lists
D. Recursive function without base case is best for performance

Solution

  1. Step 1: Consider recursion limits for large lists

    Recursion uses call stack for each call, which can cause stack overflow for large lists.
  2. Step 2: Compare iteration benefits

    Iteration uses constant memory and avoids stack overflow, making it safer and more efficient for large data.
  3. Final Answer:

    Iteration is better because it uses less memory and avoids stack overflow -> Option A
  4. Quick Check:

    Iteration safer for large data = A [OK]
Hint: Use iteration for large data to avoid stack overflow [OK]
Common Mistakes:
  • Assuming recursion always simpler for large data
  • Ignoring stack overflow risk
  • Misusing memoization for simple sums
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