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DSA Javascriptprogramming~20 mins

Recursion Base Case and Recursive Case in DSA Javascript - Practice Problems & Challenges

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Challenge - 5 Problems
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❓ Predict Output
intermediate
2:00remaining
Output of Recursive Sum Function
What is the output of the following JavaScript code that uses recursion to sum numbers from n down to 1?
DSA Javascript
function recursiveSum(n) {
  if (n <= 0) {
    return 0;
  }
  return n + recursiveSum(n - 1);
}

console.log(recursiveSum(4));
A0
B24
C10
DUndefined
Attempts:
2 left
💡 Hint
Think about what happens when n reaches 0 and how the function adds up the numbers.
❓ Predict Output
intermediate
2:00remaining
Output of Recursive Factorial Function
What will be printed when this recursive factorial function is called with 3?
DSA Javascript
function factorial(n) {
  if (n === 1) {
    return 1;
  }
  return n * factorial(n - 1);
}

console.log(factorial(3));
A1
B6
C9
D3
Attempts:
2 left
💡 Hint
Factorial means multiplying all numbers from n down to 1.
🔧 Debug
advanced
2:00remaining
Identify the Error in Recursive Fibonacci Function
What error will this recursive Fibonacci function cause when called with 5?
DSA Javascript
function fibonacci(n) {
  if (n === 0) {
    return 0;
  }
  if (n === 1) {
    return 1;
  }
  return fibonacci(n - 1) + fibonacci(n - 2);
}

console.log(fibonacci(5));
ANo error, output is 5
BStack overflow error
CTypeError
DReferenceError
Attempts:
2 left
💡 Hint
Check if the base cases cover all needed conditions to stop recursion.
❓ Predict Output
advanced
2:00remaining
Output of Recursive String Reversal
What is the output of this recursive function that reverses a string?
DSA Javascript
function reverseString(str) {
  if (str === "") {
    return "";
  }
  return reverseString(str.substr(1)) + str[0];
}

console.log(reverseString("code"));
A"edoc"
B"code"
C"odec"
D""
Attempts:
2 left
💡 Hint
The function takes the first character off and adds it to the end after reversing the rest.
🧠 Conceptual
expert
2:00remaining
Understanding Base Case Importance in Recursion
Why is the base case essential in a recursive function?
AIt allows the function to call itself more times
BIt makes the function run faster
CIt helps the function use more memory
DIt stops the recursion to prevent infinite calls
Attempts:
2 left
💡 Hint
Think about what happens if the function never stops calling itself.

Practice

(1/5)
1. What is the purpose of the base case in a recursive function?
easy
A. To call the function again with a smaller input
B. To increase the input size for the next call
C. To stop the recursion and prevent infinite calls
D. To print the result of the recursion

Solution

  1. Step 1: Understand what recursion does

    Recursion calls the same function repeatedly with smaller inputs.
  2. Step 2: Identify the role of the base case

    The base case stops the recursion by providing a condition where no further calls happen.
  3. Final Answer:

    To stop the recursion and prevent infinite calls -> Option C
  4. Quick Check:

    Base case = stop recursion [OK]
Hint: Base case stops recursion to avoid infinite loops [OK]
Common Mistakes:
  • Confusing base case with recursive case
  • Thinking base case calls recursion again
  • Ignoring base case leads to infinite recursion
2. Which of the following is the correct syntax for a base case in this recursive function to calculate factorial?
function factorial(n) {
  if (___) {
    return 1;
  }
  return n * factorial(n - 1);
}
easy
A. n > 0
B. n === 0
C. n === 1
D. n < 0

Solution

  1. Step 1: Recall factorial base case

    Factorial of 0 is 1, so base case is when n equals 0.
  2. Step 2: Match condition to code

    The condition n === 0 correctly stops recursion and returns 1.
  3. Final Answer:

    n === 0 -> Option B
  4. Quick Check:

    Base case for factorial = n === 0 [OK]
Hint: Factorial base case is n equals zero [OK]
Common Mistakes:
  • Using n > 0 as base case causes infinite recursion
  • Using n < 0 which is invalid for factorial
  • Using n === 1 misses factorial(0) base case
3. What will be the output of this recursive function call?
function sumTo(n) {
  if (n === 0) {
    return 0;
  }
  return n + sumTo(n - 1);
}
console.log(sumTo(3));
medium
A. 6
B. 3
C. 0
D. Error

Solution

  1. Step 1: Trace recursive calls

    sumTo(3) calls 3 + sumTo(2), sumTo(2) calls 2 + sumTo(1), sumTo(1) calls 1 + sumTo(0), sumTo(0) returns 0.
  2. Step 2: Calculate total sum

    sumTo(3) = 3 + 2 + 1 + 0 = 6.
  3. Final Answer:

    6 -> Option A
  4. Quick Check:

    3+2+1+0 = 6 [OK]
Hint: Sum from n down to 0 adds all numbers [OK]
Common Mistakes:
  • Forgetting to add current n before recursive call
  • Confusing base case return value
  • Assuming output is just n instead of sum
4. Find the error in this recursive function to compute the nth Fibonacci number:
function fib(n) {
  if (n === 0) return 0;
  if (n === 1) return 1;
  return fib(n - 1) + fib(n - 2);
}
console.log(fib(-1));
medium
A. Missing base case for negative n causing infinite recursion
B. Incorrect base case values for fib(0) and fib(1)
C. Wrong recursive calls should be fib(n + 1) and fib(n + 2)
D. No error, output is correct

Solution

  1. Step 1: Analyze base cases and input

    Base cases cover n=0 and n=1, but input is n=-1 which is not handled.
  2. Step 2: Understand recursion with negative input

    Calling fib(-1) leads to fib(-2) and fib(-3) calls infinitely, no stop condition.
  3. Final Answer:

    Missing base case for negative n causing infinite recursion -> Option A
  4. Quick Check:

    Negative input needs base case [OK]
Hint: Check base cases cover all input ranges [OK]
Common Mistakes:
  • Ignoring negative inputs in recursion
  • Assuming fib(-1) is valid without base case
  • Changing recursive calls incorrectly
5. You want to write a recursive function to reverse a string. Which base case and recursive case correctly achieve this?
function reverse(str) {
  if (___) {
    return ___;
  }
  return reverse(___) + str[0];
}
hard
A. str.length === 0 / str / str.slice(1)
B. str.length === 1 / str / str.slice(0, -1)
C. str === null / null / str.slice(1)
D. str === '' / str[0] / str.slice(1)

Solution

  1. Step 1: Identify base case for empty string

    When string is empty (''), return the empty string to stop recursion.
  2. Step 2: Define recursive call correctly

    Call reverse on substring from index 1 to end, then add first character at the end.
  3. Final Answer:

    str === '' / str / str.slice(1) -> Option D
  4. Quick Check:

    Empty string base case and slice(1) recursive call [OK]
Hint: Base case empty string, recursive call slice(1) [OK]
Common Mistakes:
  • Using null instead of empty string as base case
  • Returning wrong substring in recursive call
  • Incorrect base case condition
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