What if you could solve a tricky puzzle by smartly undoing mistakes instead of guessing blindly?
Why N Queens Problem in DSA Javascript?
Imagine you have a chessboard and you want to place queens so that none can attack each other. You try to do this by guessing positions one by one, checking if they attack each other manually.
Manually checking every possible position is slow and confusing. You might miss some attacks or spend hours trying different arrangements without a clear method.
The N Queens Problem uses a smart way to place queens one by one, backtracking when a conflict happens. This method quickly finds all safe arrangements without guessing blindly.
for (let i = 0; i < boardSize; i++) { for (let j = 0; j < boardSize; j++) { if (noAttack(i, j)) placeQueen(i, j); } }
function solveNQueens(row) {
if (row === boardSize) saveSolution();
else {
for (let col = 0; col < boardSize; col++) {
if (isSafe(row, col)) {
placeQueen(row, col);
solveNQueens(row + 1);
removeQueen(row, col);
}
}
}
}This approach lets you find all safe ways to place queens on the board efficiently, even for large sizes.
Scheduling tasks so none overlap in time or resources is like placing queens safely on a board.
Manual guessing is slow and error-prone.
Backtracking tries positions step-by-step and undoes wrong choices.
This method finds all safe queen placements efficiently.
Practice
N Queens Problem in chess?Solution
Step 1: Understand the problem objective
The N Queens Problem requires placing queens so that none can attack another. Queens attack horizontally, vertically, and diagonally.Step 2: Analyze the options
Only Place N queens on an NxN board so no two queens attack each other correctly states the goal: no two queens attack each other on an NxN board.Final Answer:
Place N queens on an NxN board so no two queens attack each other -> Option AQuick Check:
Goal = safe queen placement [OK]
- Thinking queens can share rows or columns
- Ignoring diagonal attacks
- Confusing attack with placement
Solution
Step 1: Understand recursive approach parameters
Typically, the recursive function takes the board state and the current row to place a queen.Step 2: Check options for correct parameters
function solveNQueens(board, row) {} usesboardandrow, which fits the common recursive pattern.Final Answer:
function solveNQueens(board, row) {} -> Option AQuick Check:
Recursive function = board + current row [OK]
- Using column instead of row for recursion
- Missing board parameter
- Using only one parameter
n = 4?
function isSafe(board, row, col) {
for (let i = 0; i < row; i++) {
if (board[i] === col || Math.abs(board[i] - col) === row - i) return false;
}
return true;
}
function solveNQueens(n) {
const board = Array(n).fill(-1);
const results = [];
function backtrack(row) {
if (row === n) {
results.push(board.slice());
return;
}
for (let col = 0; col < n; col++) {
if (isSafe(board, row, col)) {
board[row] = col;
backtrack(row + 1);
board[row] = -1;
}
}
}
backtrack(0);
return results.length;
}
console.log(solveNQueens(4));Solution
Step 1: Understand the code logic
The code uses backtracking to find all valid placements of 4 queens on a 4x4 board. It counts solutions by pushing valid boards to results.Step 2: Recall known N Queens results
For n=4, the number of valid solutions is 2, which matches the returned results length.Final Answer:
2 -> Option DQuick Check:
4 Queens solutions = 2 [OK]
- Assuming 4 queens have more than 2 solutions
- Confusing board representation with count
- Misreading the backtracking logic
function isSafe(board, row, col) {
for (let i = 0; i < row; i++) {
if (board[i] === col || Math.abs(board[i] - col) === row + i) return false;
}
return true;
}Solution
Step 1: Analyze the diagonal attack condition
The diagonal attack is checked by comparing absolute difference of columns to difference of rows. It should berow - i, notrow + i.Step 2: Identify the incorrect expression
The code usesrow + i, which is wrong and causes incorrect safety checks.Final Answer:
The diagonal check uses 'row + i' instead of 'row - i' -> Option CQuick Check:
Diagonal check = row - i [OK]
- Using addition instead of subtraction for diagonal check
- Looping one extra iteration
- Returning true too early
Solution
Step 1: Recall known solution counts for N Queens
For n=5, the known number of distinct solutions is 10.Step 2: Understand why solution count increases
With larger boards, more safe placements exist because queens can be spread out more easily without attacking each other.Final Answer:
10 solutions because more rows allow more queen placements without conflict -> Option BQuick Check:
5 Queens solutions = 10 [OK]
- Assuming no solutions for 5x5
- Confusing unique rows with total solutions
- Underestimating solution count
Ready to prove it?
Pass the test and this pattern moves unknown
