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DSA Javascriptprogramming~10 mins

Generate All Subsets Powerset in DSA Javascript - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the result array for storing subsets.

DSA Javascript
function subsets(nums) {
  const result = [1];
  return result;
}
Drag options to blanks, or click blank then click option'
A[]
B{}
Cnull
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using {} which creates an object instead of an array.
Using null or 0 which are not containers.
2fill in blank
medium

Complete the code to start the recursive helper function call with initial parameters.

DSA Javascript
function subsets(nums) {
  const result = [];
  function backtrack(start, path) {
    result.push([...path]);
    for (let i = start; i < nums.length; i++) {
      path.push(nums[i]);
      backtrack([1], path);
      path.pop();
    }
  }
  backtrack(0, []);
  return result;
}
Drag options to blanks, or click blank then click option'
A0
Bi + 1
Cstart + 1
Dnums.length
Attempts:
3 left
💡 Hint
Common Mistakes
Passing start + 1 which does not move forward correctly.
Passing 0 which causes infinite recursion.
3fill in blank
hard

Fix the error in the recursive function to correctly copy the current path before pushing.

DSA Javascript
function subsets(nums) {
  const result = [];
  function backtrack(start, path) {
    result.push([1]);
    for (let i = start; i < nums.length; i++) {
      path.push(nums[i]);
      backtrack(i + 1, path);
      path.pop();
    }
  }
  backtrack(0, []);
  return result;
}
Drag options to blanks, or click blank then click option'
Apath.concat()
Bpath
Cpath.slice()
D[...path]
Attempts:
3 left
💡 Hint
Common Mistakes
Pushing path directly stores a reference, causing all subsets to be the same.
Using path.concat() without arguments returns the same array.
4fill in blank
hard

Fill both blanks to create a function that generates all subsets using iteration.

DSA Javascript
function subsets(nums) {
  let result = [[]];
  for (const num of nums) {
    const newSubsets = result[1](subset => [...subset, num]);
    result = result[2]newSubsets;
  }
  return result;
}
Drag options to blanks, or click blank then click option'
A.map
B.filter
C.reduce
D.forEach
E.concat
Attempts:
3 left
💡 Hint
Common Mistakes
Using filter which only selects elements, not transforms.
Using reduce which is more complex here.
Using forEach which returns undefined.
5fill in blank
hard

Fill all three blanks to create a recursive function that generates subsets with backtracking.

DSA Javascript
function subsets(nums) {
  const result = [];
  function backtrack([1], [2]) {
    result.push([...path]);
    for (let i = start; i < nums.length; i++) {
      path.push(nums[i]);
      backtrack(i + 1, [3]);
      path.pop();
    }
  }
  backtrack(0, []);
  return result;
}
Drag options to blanks, or click blank then click option'
Astart
Bpath
Cnums
Dresult
Attempts:
3 left
💡 Hint
Common Mistakes
Using nums or result as parameters which are not needed.
Not passing path in recursive call causing errors.

Practice

(1/5)
1. What does the term powerset mean in the context of sets?
easy
A. The set itself without any subsets
B. All possible subsets of a set including the empty set
C. Only the subsets with exactly two elements
D. Subsets that contain only odd numbers

Solution

  1. Step 1: Understand the definition of powerset

    The powerset of a set is the collection of all subsets of that set, including the empty set and the set itself.
  2. Step 2: Compare options with the definition

    All possible subsets of a set including the empty set correctly describes the powerset as all possible subsets including the empty set. Other options describe only parts or incorrect subsets.
  3. Final Answer:

    All possible subsets of a set including the empty set -> Option B
  4. Quick Check:

    powerset = all subsets [OK]
Hint: Powerset means every subset, even empty one [OK]
Common Mistakes:
  • Thinking powerset excludes empty set
  • Confusing powerset with subsets of fixed size
  • Assuming powerset is just the original set
2. Which of the following JavaScript function signatures correctly represents a function to generate all subsets of an array arr?
easy
A. function generateSubsets(arr, subsets) { ... }
B. function generateSubsets(arr[]) { ... }
C. function generateSubsets() { ... }
D. function generateSubsets(arr) { ... }

Solution

  1. Step 1: Check valid JavaScript function syntax

    function generateSubsets(arr) { ... } uses correct syntax with one parameter named arr. function generateSubsets(arr[]) { ... } uses invalid syntax with arr[]. function generateSubsets() { ... } has no parameters, which is incomplete for this task. function generateSubsets(arr, subsets) { ... } has two parameters which might be valid but is not the standard signature for generating subsets.
  2. Step 2: Choose the most appropriate signature

    function generateSubsets(arr) { ... } is the standard and correct way to define a function that takes an array to generate subsets.
  3. Final Answer:

    function generateSubsets(arr) { ... } -> Option D
  4. Quick Check:

    Correct function syntax = function generateSubsets(arr) { ... } [OK]
Hint: Function parameters must be valid identifiers without brackets [OK]
Common Mistakes:
  • Using array syntax in parameter list (arr[])
  • Omitting required parameters
  • Adding unnecessary parameters without explanation
3. What is the output of the following JavaScript code?
function subsets(nums) {
  let result = [[]];
  for (const num of nums) {
    const newSubsets = [];
    for (const subset of result) {
      newSubsets.push([...subset, num]);
    }
    result.push(...newSubsets);
  }
  return result;
}

console.log(subsets([1, 2]));
medium
A. [[], [1], [2], [1, 2]]
B. [[], [1], [1, 2]]
C. [[1], [2], [1, 2]]
D. [[], [2], [1, 2]]

Solution

  1. Step 1: Trace the initial result and loop

    Initially, result = [[]]. For num=1, newSubsets = [[1]], result becomes [[], [1]]. For num=2, newSubsets = [[2], [1, 2]], result becomes [[], [1], [2], [1, 2]].
  2. Step 2: Confirm final output

    The function returns [[], [1], [2], [1, 2]] which matches [[], [1], [2], [1, 2]] exactly.
  3. Final Answer:

    [[], [1], [2], [1, 2]] -> Option A
  4. Quick Check:

    All subsets of [1,2] = [[], [1], [2], [1, 2]] [OK]
Hint: Each new number doubles subsets by adding to existing ones [OK]
Common Mistakes:
  • Missing empty subset in output
  • Not adding new subsets correctly
  • Confusing order of subsets
4. Identify the error in this JavaScript code that tries to generate all subsets of nums:
function getSubsets(nums) {
  let result = [];
  for (let num of nums) {
    let newSubsets = [];
    for (let subset of result) {
      newSubsets.push(subset.concat(num));
    }
    result = result.concat(newSubsets);
  }
  return result;
}

console.log(getSubsets([1, 2]));
medium
A. The initial result should contain the empty subset [[]]
B. Using concat instead of push causes error
C. The inner loop should iterate over nums, not result
D. Missing return statement

Solution

  1. Step 1: Check initial value of result

    The code initializes result as an empty array []. It should start with [[]] to include the empty subset, otherwise no subsets are generated.
  2. Step 2: Understand impact of initial value

    Without the empty subset, the inner loop never runs on first iteration, so no subsets are created. Adding [[]] fixes this.
  3. Final Answer:

    The initial result should contain the empty subset [[]] -> Option A
  4. Quick Check:

    Start with [[]] to generate subsets [OK]
Hint: Always start subsets with empty set [[]] [OK]
Common Mistakes:
  • Starting with empty array instead of [[]]
  • Confusing concat and push usage
  • Looping over wrong array
5. Given an array nums = [1, 2, 2], which code modification correctly generates all unique subsets (no duplicates) using the powerset approach?
hard
A. Remove duplicates from nums before generating subsets
B. Use a Set to store subsets as strings to avoid duplicates
C. Sort nums first, then skip adding duplicate subsets during generation
D. Generate all subsets normally without any change

Solution

  1. Step 1: Understand the problem with duplicates

    Array [1, 2, 2] has duplicates. Generating subsets normally will create duplicate subsets like [2] twice.
  2. Step 2: Apply sorting and skipping duplicates

    Sorting nums makes duplicates adjacent. During subset generation, skip adding subsets that duplicate previous ones to avoid duplicates in result.
  3. Final Answer:

    Sort nums first, then skip adding duplicate subsets during generation -> Option C
  4. Quick Check:

    Sort and skip duplicates to get unique subsets [OK]
Hint: Sort array and skip duplicates while generating subsets [OK]
Common Mistakes:
  • Ignoring duplicates causing repeated subsets
  • Removing duplicates from input changes problem
  • Using Set of strings can be inefficient or incorrect
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