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DSA Javascriptprogramming~5 mins

Generate All Combinations Sum K in DSA Javascript - Time & Space Complexity

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Time Complexity: Generate All Combinations Sum K
O(2^n * k)
Understanding Time Complexity

We want to understand how the time needed to find all combinations that add up to a target grows as the input size changes.

How does the number of combinations affect the work done?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


function combinationSumK(nums, target) {
  const result = [];
  function backtrack(start, path, sum) {
    if (sum === target) {
      result.push([...path]);
      return;
    }
    if (sum > target) return;
    for (let i = start; i < nums.length; i++) {
      path.push(nums[i]);
      backtrack(i + 1, path, sum + nums[i]);
      path.pop();
    }
  }
  backtrack(0, [], 0);
  return result;
}
    

This code finds all unique combinations of numbers that add up to the target sum.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: Recursive calls exploring combinations by looping through remaining numbers.
  • How many times: Potentially explores all subsets of the input array, which can be up to 2n combinations.
How Execution Grows With Input

As the input size grows, the number of possible combinations grows very fast because each number can be either included or excluded.

Input Size (n)Approx. Operations
10About 1,000 combinations explored
20About 1,000,000 combinations explored
30About 1,000,000,000 combinations explored

Pattern observation: The work grows exponentially as input size increases, doubling roughly with each added element.

Final Time Complexity

Time Complexity: O(2n * k)

This means the time grows exponentially with the number of input elements, multiplied by the average length of each combination.

Common Mistake

[X] Wrong: "The time complexity is just O(n) because we loop through the array once."

[OK] Correct: The code explores many combinations recursively, not just a single pass, so the work grows exponentially, not linearly.

Interview Connect

Understanding this exponential growth helps you explain why some problems need careful pruning or different approaches, a skill valued in interviews.

Self-Check

"What if we allowed numbers to be reused unlimited times? How would the time complexity change?"

Practice

(1/5)
1. What does the problem "Generate All Combinations Sum K" ask you to find?
easy
A. All unique combinations of numbers that add up to K
B. The largest number less than K
C. The count of numbers greater than K
D. The product of all numbers up to K

Solution

  1. Step 1: Understand the problem goal

    The problem asks to find all unique sets of numbers that sum exactly to K.
  2. Step 2: Clarify what combinations mean

    Combinations mean groups of numbers without regard to order, all adding to K.
  3. Final Answer:

    All unique combinations of numbers that add up to K -> Option A
  4. Quick Check:

    Combinations sum to K = All unique combinations of numbers that add up to K [OK]
Hint: Focus on sums equal to K, not counts or products [OK]
Common Mistakes:
  • Confusing combinations with permutations
  • Looking for counts instead of actual combinations
  • Trying to find products instead of sums
2. Which of the following is the correct way to start a recursive function in JavaScript to generate combinations summing to K?
easy
A. function findCombos() { return; }
B. function findCombos(nums, target) { return nums + target; }
C. function findCombos(nums, target, start, path, result) { ... }
D. function findCombos(nums) { console.log(target); }

Solution

  1. Step 1: Identify correct recursive function signature

    The function needs parameters for numbers, target sum, start index, current path, and result storage.
  2. Step 2: Check options for these parameters

    Only function findCombos(nums, target, start, path, result) { ... } includes all necessary parameters for recursion and backtracking.
  3. Final Answer:

    function findCombos(nums, target, start, path, result) { ... } -> Option C
  4. Quick Check:

    Recursive function with all params = function findCombos(nums, target, start, path, result) { ... } [OK]
Hint: Include start index and path for backtracking recursion [OK]
Common Mistakes:
  • Missing parameters needed for recursion
  • Returning wrong values instead of building combinations
  • Not including start index to avoid duplicates
3. What is the output of the following code snippet?
function combinationSum(nums, target) {
  const result = [];
  function backtrack(start, path, sum) {
    if (sum === target) {
      result.push([...path]);
      return;
    }
    if (sum > target) return;
    for (let i = start; i < nums.length; i++) {
      path.push(nums[i]);
      backtrack(i + 1, path, sum + nums[i]);
      path.pop();
    }
  }
  backtrack(0, [], 0);
  return result;
}

console.log(combinationSum([2,3,6,7], 7));
medium
A. [[7]]
B. [[2,3,6,7]]
C. [[2,3,7]]
D. [[2,2,3]]

Solution

  1. Step 1: Understand the code logic

    The function finds combinations of numbers from the array that sum to 7 without reuse (i + 1).
  2. Step 2: Trace the combinations

    Only 7 alone sums to 7; others like 2+3=5, 2+3+6=11 exceed or don't match target.
  3. Final Answer:

    [[7]] -> Option A
  4. Quick Check:

    Only [7] sums to 7 without repeats = [[7]] [OK]
Hint: Check sum and index increment to avoid reuse [OK]
Common Mistakes:
  • Assuming numbers can be reused multiple times
  • Including combinations that exceed target
  • Not copying path array before pushing
4. Identify the bug in this code snippet for generating combinations summing to K:
function findCombos(nums, target) {
  const result = [];
  function backtrack(start, path, sum) {
    if (sum === target) {
      result.push(path);
      return;
    }
    if (sum > target) return;
    for (let i = start; i < nums.length; i++) {
      path.push(nums[i]);
      backtrack(i + 1, path, sum + nums[i]);
      path.pop();
    }
  }
  backtrack(0, [], 0);
  return result;
}
medium
A. The base case sum === target is missing
B. The path array is pushed directly without copying, causing reference issues
C. The loop should start from 0 instead of start
D. The function does not return any result

Solution

  1. Step 1: Check how results are stored

    The code pushes 'path' directly, which is a reference and will change later.
  2. Step 2: Identify correct way to store combinations

    Must push a copy of path (e.g., [...path]) to save current state.
  3. Final Answer:

    The path array is pushed directly without copying, causing reference issues -> Option B
  4. Quick Check:

    Push copy of path, not reference = The path array is pushed directly without copying, causing reference issues [OK]
Hint: Always push a copy of path array to result [OK]
Common Mistakes:
  • Pushing path reference instead of copy
  • Incorrect loop start index causing duplicates
  • Missing base case for sum equal to target
5. Given the array [1, 2, 3, 4] and target sum 5, which of the following is the correct set of all unique combinations that sum to 5, assuming numbers can be used only once?
hard
A. [[1,2,2]]
B. [[1,1,3],[2,3]]
C. [[5]]
D. [[1,4],[2,3]]

Solution

  1. Step 1: List all combinations without reuse that sum to 5

    Possible pairs: 1+4=5, 2+3=5; triples or singles don't sum to 5 without reuse.
  2. Step 2: Verify options against these combinations

    [[1,4],[2,3]] matches these pairs exactly; others include duplicates or invalid sums.
  3. Final Answer:

    [[1,4],[2,3]] -> Option D
  4. Quick Check:

    Unique pairs summing to 5 = [[1,4],[2,3]] [OK]
Hint: Sum pairs without reuse to find valid combos [OK]
Common Mistakes:
  • Including repeated numbers when only single use allowed
  • Assuming single number 5 exists in array
  • Counting invalid sums or duplicates
Recommended

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10 questions~5 mineasy hard