It is the largest sum of node values on any path in the tree. The path can start and end at any nodes, and must follow parent-child connections.
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intermediate
Why do we use Dynamic Programming (DP) on trees for Maximum Path Sum?
Because we can break the problem into smaller subproblems: the maximum path sum starting from each child. We store results to avoid repeated work and combine them to find the global maximum.
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intermediate
In DP on trees for Maximum Path Sum, what does the 'return value' of the recursive function usually represent?
It represents the maximum path sum starting from the current node and extending down to one of its children or just the node itself.
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intermediate
How do we handle negative node values in Maximum Path Sum on trees?
We compare the node value alone with sums including children and choose the maximum. This way, we avoid paths that reduce the sum by including negative values.
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beginner
What is the role of a global variable in the DP on Trees Maximum Path Sum algorithm?
It keeps track of the overall maximum path sum found so far while the recursion explores all nodes.
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What does the maximum path sum in a tree represent?
AThe largest sum of node values on any path in the tree
BThe sum of all node values in the tree
CThe longest path length in the tree
DThe smallest node value in the tree
✗ Incorrect
The maximum path sum is the largest sum of node values on any path, not necessarily covering all nodes.
In DP on trees, what does the recursive function usually return?
ATotal number of nodes in the tree
BMaximum path sum starting from the current node downwards
CMinimum node value in the subtree
DHeight of the tree
✗ Incorrect
The recursive function returns the maximum path sum starting at the current node and going down to one child or just the node itself.
How do we handle negative values in nodes when calculating maximum path sum?
AReplace negative values with zero
BAlways include all nodes regardless of value
CIgnore negative values and only consider positive sums
DCompare node value alone with sums including children and choose the maximum
✗ Incorrect
We choose the maximum between the node alone and sums including children to avoid reducing the total sum.
Why do we keep a global variable in the DP on Trees Maximum Path Sum algorithm?
ATo store the height of the tree
BTo count the number of nodes visited
CTo store the overall maximum path sum found so far
DTo keep track of the minimum path sum
✗ Incorrect
The global variable tracks the highest path sum found anywhere in the tree during recursion.
Which of these paths is valid when calculating maximum path sum in a tree?
AA path following parent-child connections
BA path that jumps between unrelated nodes
CA path that includes cycles
DA path that skips nodes
✗ Incorrect
Paths must follow parent-child connections without skipping or jumping between unrelated nodes.
Explain how dynamic programming helps find the maximum path sum in a tree.
Think about how you solve smaller parts and combine them.
You got /5 concepts.
Describe how to handle negative node values when computing maximum path sum on trees.
Consider when it is better to take just the node itself.
You got /4 concepts.
Practice
(1/5)
1. What does the "maximum path sum" in a binary tree represent? Maximum path sum means:
easy
A. The largest sum of node values along any path in the tree
B. The number of nodes in the longest path
C. The smallest sum of node values along any path
D. The sum of all node values in the tree
Solution
Step 1: Understand the path definition
A path in a tree is any sequence of nodes connected by edges, not necessarily starting at the root.
Step 2: Define maximum path sum meaning
The maximum path sum is the highest total value you get by adding node values along any such path.
Final Answer:
The largest sum of node values along any path in the tree -> Option A
Quick Check:
Maximum path sum = largest node value sum [OK]
Hint: Maximum path sum is about node values, not count or minimum [OK]
Common Mistakes:
Confusing path length with sum
Thinking path must start at root
Choosing sum of all nodes instead of max path
2. Which of the following is the correct base case for a recursive function computing maximum path sum in a binary tree node?
function maxPathSum(node) {
if (___) return 0;
// rest of code
}
easy
A. node.value === 0
B. node.left === null && node.right === null
C. node === null
D. node === undefined
Solution
Step 1: Identify when recursion should stop
When the node is empty (null), there is no path, so return 0.
Step 2: Check options for base case
Only checking if node is null correctly handles leaf children and empty trees.
Final Answer:
node === null -> Option C
Quick Check:
Base case: node null means no path [OK]
Hint: Base case is node === null to stop recursion [OK]
Common Mistakes:
Using node.value === 0 which is incorrect
Checking both children null instead of node null
Using node === undefined which is less common
3. What is the output of the following code snippet?
class TreeNode {
constructor(val, left = null, right = null) {
this.val = val;
this.left = left;
this.right = right;
}
}
function maxPathSum(root) {
let maxSum = -Infinity;
function dfs(node) {
if (node === null) return 0;
let left = Math.max(dfs(node.left), 0);
let right = Math.max(dfs(node.right), 0);
maxSum = Math.max(maxSum, node.val + left + right);
return node.val + Math.max(left, right);
}
dfs(root);
return maxSum;
}
const tree = new TreeNode(1, new TreeNode(2), new TreeNode(3));
console.log(maxPathSum(tree));
medium
A. 6
B. 5
C. 3
D. 1
Solution
Step 1: Calculate max path sums for each node
For leaf nodes 2 and 3, max path sum is their value (2 and 3). For root 1, left=2, right=3, sum=1+2+3=6.
Step 2: Update maxSum and return correct values
maxSum updates to 6 at root. Return values propagate correctly.
Final Answer:
6 -> Option A
Quick Check:
Sum of 1+2+3 = 6 [OK]
Hint: Add node + max left + max right, ignore negatives [OK]
Common Mistakes:
Forgetting to ignore negative sums
Returning node.val + left + right instead of max(left, right)
Confusing maxSum update with return value
4. Find the bug in this code for maximum path sum in a binary tree:
function maxPathSum(root) {
let maxSum = -Infinity;
function dfs(node) {
if (!node) return 0;
let left = dfs(node.left);
let right = dfs(node.right);
maxSum = Math.max(maxSum, node.val + left + right);
return node.val + Math.max(left, right);
}
dfs(root);
return maxSum;
}
medium
A. It returns maxSum before dfs call
B. It does not ignore negative sums from children
C. It uses wrong base case condition
D. It adds node.val twice in maxSum
Solution
Step 1: Check handling of negative child sums
The code uses left = dfs(node.left) directly without ignoring negatives, which can reduce maxSum incorrectly.
Step 2: Correct approach to ignore negatives
Should use left = Math.max(dfs(node.left), 0) and similarly for right to avoid negative paths.
Final Answer:
It does not ignore negative sums from children -> Option B
Quick Check:
Ignore negatives to maximize path sum [OK]
Hint: Use Math.max(childSum, 0) to skip negative paths [OK]
Common Mistakes:
Not ignoring negative sums
Returning before dfs call
Wrong base case check
5. Given a binary tree where nodes can have negative values, how would you modify the maximum path sum algorithm to handle the case where all node values are negative? Choose the best approach:
hard
A. Initialize maxSum to 0 and ignore negative sums
B. Only consider paths starting at the root
C. Return 0 if all nodes are negative
D. Initialize maxSum to -Infinity and allow paths with negative sums
Solution
Step 1: Understand negative values impact
If all nodes are negative, ignoring negative sums by replacing with 0 would incorrectly return 0 instead of the max negative value.
Step 2: Use -Infinity initialization and allow negative sums
Initialize maxSum to -Infinity and do not ignore negative sums completely, so the max negative node is chosen.
Final Answer:
Initialize maxSum to -Infinity and allow paths with negative sums -> Option D
Quick Check:
Allow negative sums to handle all-negative nodes [OK]
Hint: Use -Infinity start and allow negatives for all-negative trees [OK]
Common Mistakes:
Ignoring negatives leads to wrong zero result
Returning 0 when no positive path exists
Restricting paths to root only
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