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DSA Javascriptprogramming~20 mins

Buy and Sell Stocks All Variants in DSA Javascript - Practice Problems & Challenges

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Challenge - 5 Problems
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❓ Predict Output
intermediate
2:00remaining
Maximum Profit with One Transaction
What is the output of the following code that calculates the maximum profit from one buy-sell transaction?
DSA Javascript
function maxProfit(prices) {
  let minPrice = Infinity;
  let maxProfit = 0;
  for (const price of prices) {
    if (price < minPrice) minPrice = price;
    else if (price - minPrice > maxProfit) maxProfit = price - minPrice;
  }
  return maxProfit;
}

console.log(maxProfit([7,1,5,3,6,4]));
A6
B5
C4
D7
Attempts:
2 left
💡 Hint
Track the lowest price and calculate profit by subtracting it from current price.
❓ Predict Output
intermediate
2:00remaining
Maximum Profit with Unlimited Transactions
What is the output of this code that calculates the maximum profit with unlimited buy-sell transactions?
DSA Javascript
function maxProfit(prices) {
  let profit = 0;
  for (let i = 1; i < prices.length; i++) {
    if (prices[i] > prices[i - 1]) {
      profit += prices[i] - prices[i - 1];
    }
  }
  return profit;
}

console.log(maxProfit([7,1,5,3,6,4]));
A6
B8
C5
D7
Attempts:
2 left
💡 Hint
Add all positive differences between consecutive days.
❓ Predict Output
advanced
2:00remaining
Maximum Profit with Cooldown Period
What is the output of this code that calculates maximum profit with a cooldown period after selling?
DSA Javascript
function maxProfit(prices) {
  if (prices.length === 0) return 0;
  let sell = 0, prev_sell = 0, buy = -Infinity;
  for (const price of prices) {
    let prev_buy = buy;
    buy = Math.max(prev_sell - price, buy);
    prev_sell = sell;
    sell = Math.max(prev_buy + price, sell);
  }
  return sell;
}

console.log(maxProfit([1,2,3,0,2]));
A3
B4
C5
D2
Attempts:
2 left
💡 Hint
Use variables to track buy and sell states considering cooldown.
❓ Predict Output
advanced
2:00remaining
Maximum Profit with Transaction Fee
What is the output of this code that calculates maximum profit with a transaction fee for each sell?
DSA Javascript
function maxProfit(prices, fee) {
  let cash = 0, hold = -prices[0];
  for (let i = 1; i < prices.length; i++) {
    cash = Math.max(cash, hold + prices[i] - fee);
    hold = Math.max(hold, cash - prices[i]);
  }
  return cash;
}

console.log(maxProfit([1,3,2,8,4,9], 2));
A7
B6
C8
D5
Attempts:
2 left
💡 Hint
Track cash and hold states, subtract fee on sell.
🧠 Conceptual
expert
3:00remaining
Understanding State Transitions in Stock Trading with Cooldown and Fee
Which option correctly describes the state transitions in a dynamic programming solution for stock trading with both cooldown and transaction fee?
ABuy state depends on previous sell state minus price; sell state depends on previous buy state plus price minus fee; cooldown is implicit by delaying buy after sell.
BBuy state depends on current sell state plus price; sell state depends on previous buy state minus price plus fee; cooldown is explicit by skipping days.
CBuy and sell states are independent; cooldown is handled by subtracting fee from buy state only.
DSell state depends on previous sell state minus fee; buy state depends on previous buy state plus price; cooldown is ignored.
Attempts:
2 left
💡 Hint
Think about how buy and sell states update and how cooldown delays buying after selling.

Practice

(1/5)
1. What is the main goal when solving the Buy and Sell Stocks problem variants?
easy
A. Maximize the profit by choosing the best days to buy and sell stocks
B. Minimize the number of transactions regardless of profit
C. Find the day with the highest stock price only
D. Calculate the average stock price over all days

Solution

  1. Step 1: Understand the problem goal

    The problem asks to find the best days to buy and sell stocks to get the highest profit.
  2. Step 2: Identify the objective

    Maximizing profit means buying low and selling high at the right times.
  3. Final Answer:

    Maximize the profit by choosing the best days to buy and sell stocks -> Option A
  4. Quick Check:

    Goal = Maximize profit [OK]
Hint: Focus on profit maximization, not just prices or counts [OK]
Common Mistakes:
  • Thinking the goal is to minimize transactions
  • Only looking for highest price day
  • Calculating average price instead of profit
2. Which of the following is the correct syntax to initialize a variable maxProfit to 0 in JavaScript?
easy
A. var maxProfit == 0;
B. let maxProfit = 0;
C. maxProfit := 0;
D. int maxProfit = 0;

Solution

  1. Step 1: Identify correct JavaScript variable declaration

    JavaScript uses let or const for variable declaration and single equals = for assignment.
  2. Step 2: Check each option

    let maxProfit = 0; uses let maxProfit = 0; which is correct syntax.
  3. Final Answer:

    let maxProfit = 0; -> Option B
  4. Quick Check:

    Variable declaration with let and = assignment [OK]
Hint: Use let or const with single = for assignment in JavaScript [OK]
Common Mistakes:
  • Using double equals == for assignment
  • Using := which is not JavaScript syntax
  • Using int which is not a JavaScript keyword
3. What will be the output of the following code snippet?
const prices = [7,1,5,3,6,4];
let minPrice = Infinity;
let maxProfit = 0;
for (let price of prices) {
  if (price < minPrice) minPrice = price;
  else if (price - minPrice > maxProfit) maxProfit = price - minPrice;
}
console.log(maxProfit);
medium
A. 7
B. 6
C. 4
D. 5

Solution

  1. Step 1: Track minimum price and maximum profit

    Iterate prices: minPrice updates to 7, then 1; maxProfit updates when price - minPrice is larger.
  2. Step 2: Calculate maxProfit step-by-step

    Prices: 7 (minPrice=7), 1 (minPrice=1), 5 (profit=4), 3 (profit=2), 6 (profit=5), 4 (profit=3). Max profit is 5.
  3. Final Answer:

    5 -> Option D
  4. Quick Check:

    Max profit = 5 [OK]
Hint: Track min price and update max profit on the fly [OK]
Common Mistakes:
  • Confusing minPrice update logic
  • Calculating profit incorrectly
  • Using max price instead of max profit
4. The following code is intended to find the maximum profit from one transaction but has a bug. What is the bug?
function maxProfit(prices) {
  let minPrice = 0;
  let maxProfit = 0;
  for (let price of prices) {
    if (price < minPrice) minPrice = price;
    else if (price - minPrice > maxProfit) maxProfit = price - minPrice;
  }
  return maxProfit;
}
medium
A. minPrice should be initialized to Infinity, not 0
B. maxProfit should be initialized to -Infinity
C. The for loop should use index instead of for-of
D. The return statement is missing

Solution

  1. Step 1: Check initialization of minPrice

    minPrice is set to 0, but prices can be greater than 0, so minPrice never updates correctly if all prices are above 0.
  2. Step 2: Correct initialization

    minPrice should start at Infinity to ensure it updates to the first price correctly.
  3. Final Answer:

    minPrice should be initialized to Infinity, not 0 -> Option A
  4. Quick Check:

    minPrice init = Infinity [OK]
Hint: Initialize minPrice to Infinity to track minimum correctly [OK]
Common Mistakes:
  • Initializing minPrice to 0 causes wrong min tracking
  • Thinking maxProfit needs -Infinity initialization
  • Confusing loop types for this problem
5. Given the prices array [3,3,5,0,0,3,1,4], what is the maximum profit with at most two transactions?
hard
A. 5
B. 6
C. 7
D. 4

Solution

  1. Step 1: Understand two transactions limit

    We can buy and sell twice to maximize profit, but transactions cannot overlap.
  2. Step 2: Calculate profits for two transactions

    First transaction: buy at 3, sell at 5 (profit 2). Second transaction: buy at 0, sell at 4 (profit 5). Total profit = 2 + 5 = 7.
  3. Final Answer:

    7 -> Option C
  4. Quick Check:

    Two transactions profit = 7 [OK]
Hint: Split array, find max profit in two parts, sum them [OK]
Common Mistakes:
  • Trying to do more than two transactions
  • Adding profits from overlapping transactions
  • Missing the best buy/sell days for each transaction
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10 questions~5 mineasy hard