Stock Span Problem Using Stack in DSA Javascript - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the Stock Span Problem?

The Stock Span Problem finds, for each day, how many consecutive days had stock prices less than or equal to the current day's price.

intermediate

Why do we use a stack to solve the Stock Span Problem?

A stack helps keep track of previous days with higher stock prices efficiently, allowing us to find spans in O(n) time by popping smaller or equal prices until a higher price is found.

intermediate

What does each element in the stack represent in the Stock Span Problem?

Each element in the stack stores the index of a day with a stock price higher than the current day's price, helping to calculate the span.

intermediate

How is the span for a day calculated using the stack?

Span = current day index - index of last higher price day (top of stack) if stack not empty; otherwise, span = current day index + 1.

intermediate

What is the time complexity of the Stock Span Problem solution using a stack?

The time complexity is O(n) because each element is pushed and popped at most once from the stack.

What does the Stock Span Problem calculate for each day?

A Total sum of stock prices till current day

B Number of consecutive days with stock price less than or equal to current day

C Minimum stock price till current day

D Maximum stock price till current day

The problem finds how many consecutive days had prices less than or equal to the current day's price.

What data structure is best suited to solve the Stock Span Problem efficiently?

A Stack

B Queue

C Array

D Linked List

A stack helps track previous higher prices and calculate spans in O(n) time.

When calculating span, if the stack is empty, what is the span for the current day?

A 1

B 0

C Current day index + 1

D Current day index

If no previous higher price exists, span is all days till current day, which is index + 1.

What happens to stack elements when a new day's price is higher than the top of the stack's price?

A Ignore the new price

B Push new price without popping

C Clear the stack completely

D Pop elements until top has higher price or stack is empty

We pop smaller or equal prices to find the last higher price for span calculation.

What is the overall time complexity of the stack-based Stock Span solution?

A O(n)

B O(n^2)

C O(log n)

D O(1)

Each element is pushed and popped at most once, making the solution linear time.

Explain how a stack helps solve the Stock Span Problem efficiently.

Think about how you find the last day with a higher price before the current day.

Describe the step-by-step process to calculate the span for each day using a stack.

Imagine checking previous days one by one but using a stack to skip unnecessary checks.

Practice

1. What does the Stock Span Problem calculate for each day in a list of stock prices?

easy

A. The number of consecutive days before the current day with a price less than or equal to the current day's price

B. The maximum stock price in the entire list

C. The minimum stock price in the entire list

D. The difference between the current day's price and the previous day's price

Solution

1. Step 1: Understand the problem definition

   The Stock Span Problem finds how many consecutive days before today had prices less than or equal to today's price.

2. Step 2: Clarify what is calculated for each day

   For each day, it counts days backward until a higher price is found or start is reached.

3. Final Answer:

   The number of consecutive days with price less or equal to current day -> Option A

4. Quick Check:

   Span counts consecutive lower/equal prices before today [OK]

Hint: Span counts days with prices ≤ current day price [OK]

Common Mistakes:

• Confusing span with max or min price
• Thinking span is price difference
• Ignoring consecutive days condition

2. Which of the following JavaScript code snippets correctly initializes an empty stack for solving the Stock Span Problem?

easy

A. const stack = 0;

B. const stack = {};

C. const stack = [];

D. const stack = null;

Solution

1. Step 1: Identify the correct data structure for stack

   In JavaScript, a stack is usually implemented as an array to use push and pop methods.

2. Step 2: Check initialization syntax

   An empty array is initialized with [] which is correct for a stack.

3. Final Answer:

   const stack = []; -> Option C

4. Quick Check:

   Stack uses array [] in JavaScript [OK]

Hint: Use array [] to create stack in JavaScript [OK]

Common Mistakes:

• Using object {} instead of array
• Assigning null or number instead of array
• Forgetting to initialize stack before use

3. What is the output of the stock span array for the prices [100, 80, 60, 70, 60, 75, 85] using the Stock Span Problem algorithm?

medium

A. [7, 6, 5, 4, 3, 2, 1]

B. [1, 2, 3, 4, 5, 6, 7]

C. [1, 1, 1, 1, 1, 1, 1]

D. [1, 1, 1, 2, 1, 4, 6]

Solution

1. Step 1: Calculate span for each price

   Day 0: 100 -> span=1 (no previous days)
   Day 1: 80 < 100 -> span=1
   Day 2: 60 < 80 -> span=1
   Day 3: 70 > 60 -> span=2 (includes day 2)
   Day 4: 60 < 70 -> span=1
   Day 5: 75 > 60, 70, 60 -> span=4 (days 4,3,2,1)
   Day 6: 85 > 75, 70, 60, 80 -> span=6 (days 5,3,2,1,0)

2. Step 2: Write the span array

   The spans are [1, 1, 1, 2, 1, 4, 6].

3. Final Answer:

   [1, 1, 1, 2, 1, 4, 6] -> Option D

4. Quick Check:

   Span array matches calculated values [OK]

Hint: Count consecutive previous days with price ≤ current [OK]

Common Mistakes:

• Counting all previous days instead of consecutive
• Mixing up greater and less conditions
• Incorrectly including days with higher prices

4. Identify the error in the following JavaScript code snippet for the Stock Span Problem:

function calculateSpan(prices) {
  const stack = [];
  const span = [];
  for (let i = 0; i < prices.length; i++) {
    while (stack.length > 0 && prices[stack[stack.length - 1]] <= prices[i]) {
      stack.pop();
    }
    span[i] = stack.length === 0 ? i + 1 : i - stack[stack.length - 1];
    stack.push(i);
  }
  return span;
}

medium

A. The span calculation formula is incorrect; it should be i + stack[stack.length - 1]

B. There is no error; the code correctly calculates the stock span

C. The stack should store prices, not indices

D. The comparison operator in while loop should be <= instead of <

Solution

1. Step 1: Analyze the while loop condition

   The loop pops indices while the price at top index is less than or equal to current price, which is correct for span calculation.

2. Step 2: Check span calculation formula

   If stack is empty, span is i+1 (all previous days), else difference between current index and top index in stack, which is correct.

3. Step 3: Verify stack usage

   Stack stores indices, which is standard to access prices array correctly.

4. Final Answer:

   There is no error; the code correctly calculates the stock span -> Option B

5. Quick Check:

   Code matches standard stock span algorithm [OK]

Hint: Stack stores indices; span formula uses index difference [OK]

Common Mistakes:

• Changing < to <= breaks correct span logic
• Storing prices instead of indices causes wrong indexing
• Incorrect span formula leads to wrong results

5. Given the stock prices array [10, 4, 5, 90, 120, 80], how would the Stock Span Problem algorithm change if we want to find the span of days with prices strictly less than the current day's price (not less than or equal)? What is the resulting span array?

hard

A. [1, 1, 2, 4, 5, 1]

B. [1, 1, 2, 3, 4, 1]

C. [1, 1, 1, 4, 5, 1]

D. [1, 2, 3, 4, 5, 6]

Solution

1. Step 1: Understand the strict less than condition

   Change the comparison in the algorithm from ≤ to <, so only days with price strictly less count towards span.

2. Step 2: Calculate spans with strict less than

   Day 0: 10 -> span=1
   Day 1: 4 < 10 -> span=1
   Day 2: 5 > 4 -> span=2 (days 1 and 2)
   Day 3: 90 > 5,4,10 -> span=4 (days 0,1,2,3)
   Day 4: 120 > 90 -> span=5 (days 0 to 4)
   Day 5: 80 < 120 -> span=1

3. Final Answer:

   [1, 1, 2, 4, 5, 1] -> Option A

4. Quick Check:

   Strict less than span matches [1,1,2,4,5,1] [OK]

Hint: Use < instead of ≤ in comparison for strict span [OK]

Common Mistakes:

• Not changing comparison operator correctly
• Counting equal prices in span incorrectly
• Miscounting consecutive days with strict condition