Reverse a Doubly Linked List in DSA Javascript - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a doubly linked list?

A doubly linked list is a chain of nodes where each node has three parts: data, a pointer to the next node, and a pointer to the previous node. This allows moving forward and backward through the list.

beginner

What does reversing a doubly linked list mean?

Reversing a doubly linked list means changing the direction of the list so that the last node becomes the first, and the first becomes the last, by swapping the next and previous pointers of each node.

intermediate

In reversing a doubly linked list, what pointers do we swap in each node?

We swap the 'next' pointer with the 'previous' pointer in each node. This changes the direction of the links between nodes.

intermediate

Why do we need to update the head pointer after reversing a doubly linked list?

Because after reversing, the original tail becomes the new head. We must update the head pointer to point to this new first node to correctly represent the reversed list.

beginner

What is the time complexity of reversing a doubly linked list?

The time complexity is O(n), where n is the number of nodes, because we visit each node once to swap its pointers.

What pointers are swapped in each node when reversing a doubly linked list?

A Next and previous pointers

B Data and next pointers

C Only next pointers

D Only previous pointers

Reversing a doubly linked list requires swapping both next and previous pointers in each node.

After reversing a doubly linked list, what should the head pointer point to?

A Original tail node

B Null

C Original head node

D Middle node

The original tail becomes the new head after reversing the list.

What is the time complexity of reversing a doubly linked list with n nodes?

A O(1)

B O(n^2)

C O(log n)

D O(n)

Each node is visited once to swap pointers, so the time complexity is O(n).

Which of these is NOT a part of a doubly linked list node?

A Next pointer

B Random pointer

C Previous pointer

D Data

A standard doubly linked list node has data, next, and previous pointers. Random pointer is not standard.

What happens if you forget to update the head pointer after reversing a doubly linked list?

A The list will be empty

B The list will still be reversed but head points to old first node

C The list will be reversed but head points to old first node, causing incorrect traversal

D The list will be reversed but head points to old tail node

If head is not updated, it points to the old first node which is now the last, causing incorrect traversal.

Explain step-by-step how to reverse a doubly linked list.

Think about swapping pointers and updating head.

Why is reversing a doubly linked list easier than reversing a singly linked list?

Consider the presence of two pointers per node.

Practice

1. What does reversing a doubly linked list mean?

easy

A. Adding a new node at the end

B. Deleting all nodes from the list

C. Sorting the nodes in ascending order

D. Swapping the next and previous pointers of each node

Solution

1. Step 1: Understand doubly linked list structure

   Each node has two pointers: one to the next node and one to the previous node.

2. Step 2: Reverse means swapping pointers

   Reversing means changing each node's next pointer to previous and previous pointer to next.

3. Final Answer:

   Swapping the next and previous pointers of each node -> Option D

4. Quick Check:

   Reverse = swap next and prev pointers [OK]

Hint: Reverse means swap next and prev pointers [OK]

Common Mistakes:

• Thinking reverse means deleting nodes
• Confusing reverse with sorting
• Adding nodes instead of reversing pointers

2. Which of the following is the correct way to swap the next and prev pointers of a node in JavaScript?

easy

A. node.prev = node.next; node.next = node.prev;

B. node.next = node.prev; node.prev = node.next;

C. let temp = node.next; node.next = node.prev; node.prev = temp;

D. node.next = node.next; node.prev = node.prev;

Solution

1. Step 1: Use a temporary variable to hold one pointer

   Store node.next in temp to avoid losing its value.

2. Step 2: Swap pointers correctly

   Assign node.next = node.prev, then node.prev = temp to complete swap.

3. Final Answer:

   let temp = node.next; node.next = node.prev; node.prev = temp; -> Option C

4. Quick Check:

   Swap with temp variable = correct [OK]

Hint: Use temp variable to swap pointers safely [OK]

Common Mistakes:

• Swapping without temp loses pointer data
• Assigning both pointers to same value
• Not swapping pointers at all

3. What will be the output list after reversing this doubly linked list?

Head -> 1 <-> 2 <-> 3 <-> null

After reversal, what is the new head node's value?

medium

A. 3

B. 1

C. 2

D. null

Solution

1. Step 1: Original list order

   List is 1 <-> 2 <-> 3, head points to 1.

2. Step 2: Reverse swaps pointers, so last node becomes head

   After reversal, 3 becomes the new head, pointing backward to 2 and forward to null.

3. Final Answer:

   3 -> Option A

4. Quick Check:

   New head after reverse = last node = 3 [OK]

Hint: New head after reverse is original tail [OK]

Common Mistakes:

• Assuming head stays same after reverse
• Confusing node values order
• Thinking null becomes head

4. Identify the bug in this reverse function for a doubly linked list:

function reverse(head) {
  let current = head;
  while (current != null) {
    let temp = current.next;
    current.next = current.prev;
    current.prev = temp;
    current = current.next;
  }
  return head;
}

medium

A. The function does not update the head to the new first node

B. Swapping next and prev pointers is done incorrectly

C. The loop condition should be current.next != null

D. The function should return null instead of head

Solution

1. Step 1: Check pointer swapping

   Swapping next and prev pointers is done correctly using temp variable.

2. Step 2: Check head update after reversal

   Function returns original head, but after reversal head should be last node visited, so head is not updated.

3. Final Answer:

   The function does not update the head to the new first node -> Option A

4. Quick Check:

   Head must update to new first node [OK]

Hint: Update head to last processed node after loop [OK]

Common Mistakes:

• Not updating head after reversal
• Incorrect loop condition causing infinite loop
• Returning wrong node at end

5. Given a doubly linked list with nodes:

Head -> 10 <-> 20 <-> 30 <-> 40 <-> null

After reversing the list, what is the correct sequence of nodes starting from the new head?

hard

A. 10 <-> 20 <-> 30 <-> 40 <-> null

B. 40 <-> 30 <-> 20 <-> 10 <-> null

C. 40 <-> 20 <-> 30 <-> 10 <-> null

D. null <-> 40 <-> 30 <-> 20 <-> 10

Solution

1. Step 1: Original list order

   Nodes are linked as 10 <-> 20 <-> 30 <-> 40, head at 10.

2. Step 2: Reverse swaps pointers and changes head to last node

   After reversal, head is 40, and nodes link backward as 40 <-> 30 <-> 20 <-> 10.

3. Final Answer:

   40 <-> 30 <-> 20 <-> 10 <-> null -> Option B

4. Quick Check:

   Reverse list order = original tail to head [OK]

Hint: Reversed list order is original list backwards [OK]

Common Mistakes:

• Not reversing the order correctly
• Mixing node values in wrong order
• Confusing null placement in list