What if you could remove the last item instantly without searching through everything?
Why Pop Using Linked List Node in DSA Javascript?
Imagine you have a stack of books on your desk. You want to remove the top book, but you have to look through all the books one by one to find it because they are not organized well.
Manually searching through the books is slow and tiring. You might accidentally remove the wrong book or drop some. It's easy to make mistakes and waste time.
Using a linked list with a pop operation lets you quickly remove the top item without searching. It keeps track of the top book, so you just take it off easily and safely.
let books = ['book1', 'book2', 'book3']; // To remove top book, find last element manually let topBook = books[books.length - 1]; books.length = books.length - 1;
class Node { constructor(value) { this.value = value; this.next = null; } } class Stack { constructor() { this.top = null; } pop() { if (!this.top) return null; let popped = this.top.value; this.top = this.top.next; return popped; } }
This lets you remove the last added item instantly, making your program faster and safer.
When you undo typing in a text editor, it quickly removes the last action using a pop operation on a linked list stack.
Manual removal is slow and error-prone.
Pop operation removes the top node quickly.
Linked list tracks the top for instant access.
Practice
pop() operation do in a linked list implemented using nodes?Solution
Step 1: Understand pop operation in linked list
The pop operation removes the last node from the linked list and returns its value.Step 2: Differentiate from other operations
Adding a node is push, removing first node is shift, and peeking returns value without removal.Final Answer:
Removes the last node and returns its value -> Option DQuick Check:
pop() removes last node = B [OK]
- Confusing pop with push (adding nodes)
- Thinking pop removes the first node
- Assuming pop only returns value without removal
Solution
Step 1: Identify standard method name
In JavaScript linked list implementations,pop()is the standard method to remove the last node.Step 2: Check other options
Other method names likepopNode(),removeLast(), ordeleteTail()are not standard or common.Final Answer:
list.pop() -> Option CQuick Check:
pop() removes last node syntax = D [OK]
- Using non-standard method names
- Confusing pop() with other removal methods
- Assuming popNode() is built-in
class Node {
constructor(value) {
this.value = value;
this.next = null;
}
}
class LinkedList {
constructor() {
this.head = null;
}
push(value) {
const newNode = new Node(value);
if (!this.head) {
this.head = newNode;
return;
}
let current = this.head;
while (current.next) {
current = current.next;
}
current.next = newNode;
}
pop() {
if (!this.head) return null;
if (!this.head.next) {
const val = this.head.value;
this.head = null;
return val;
}
let current = this.head;
while (current.next.next) {
current = current.next;
}
const val = current.next.value;
current.next = null;
return val;
}
}
const list = new LinkedList();
list.push(10);
list.push(20);
list.push(30);
const poppedValue = list.pop();
console.log(poppedValue);What will be printed?
Solution
Step 1: Trace push operations
Nodes added in order: 10 -> 20 -> 30Step 2: Trace pop operation
Pop removes last node (30) and returns its value.Final Answer:
30 -> Option AQuick Check:
Last node value popped = 30 [OK]
- Confusing pop with removing first node
- Expecting 20 instead of 30
- Assuming pop returns null if list not empty
pop() method for a singly linked list has a bug. What is the error?pop() {
if (!this.head) return null;
let current = this.head;
while (current.next) {
current = current.next;
}
const val = current.value;
current = null;
return val;
}Solution
Step 1: Analyze traversal to last node
The code moves current to last node correctly but does not track previous node.Step 2: Check removal logic
Setting current = null only changes local variable, does not remove last node from list.Step 3: Identify missing update
Previous node's next should be set to null to remove last node.Final Answer:
It does not update the previous node's next to null -> Option AQuick Check:
Missing previous.next = null causes bug = A [OK]
- Not tracking previous node during traversal
- Setting current = null does not remove node
- Ignoring empty list check
You perform two pop operations in a row. What is the state of the linked list after these operations?
Solution
Step 1: Initial list nodes
List is 5 -> 15 -> 25 -> 35 -> null.Step 2: First pop removes last node
Pop removes 35, list becomes 5 -> 15 -> 25 -> null.Step 3: Second pop removes new last node
Pop removes 25, list becomes 5 -> 15 -> null.Final Answer:
5 -> 15 -> null -> Option BQuick Check:
Two pops remove last two nodes = A [OK]
- Removing nodes from the front instead of end
- Removing only one node after two pops
- Assuming list becomes empty after two pops
Ready to prove it?
Pass the test and this pattern moves unknown
