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DSA Javascriptprogramming~5 mins

Majority Element Moore's Voting Algorithm in DSA Javascript - Time & Space Complexity

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Time Complexity: Majority Element Moore's Voting Algorithm
O(n)
Understanding Time Complexity

We want to understand how fast Moore's Voting Algorithm finds the majority element in a list.

How does the time needed grow as the list gets bigger?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


function majorityElement(nums) {
  let count = 0;
  let candidate = null;
  for (const num of nums) {
    if (count === 0) {
      candidate = num;
    }
    count += (num === candidate) ? 1 : -1;
  }
  return candidate;
}
    

This code finds the majority element by tracking a candidate and adjusting a count as it scans the list once.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: One loop that goes through each number in the list exactly once.
  • How many times: The loop runs once for every element in the list (n times).
How Execution Grows With Input

As the list grows, the number of steps grows directly with it.

Input Size (n)Approx. Operations
10About 10 steps
100About 100 steps
1000About 1000 steps

Pattern observation: The steps increase in a straight line as the list gets bigger.

Final Time Complexity

Time Complexity: O(n)

This means the time to find the majority element grows directly with the size of the list.

Common Mistake

[X] Wrong: "The algorithm checks every pair of elements, so it must be O(n²)."

[OK] Correct: The algorithm only scans the list once, updating counts without nested loops, so it runs in linear time.

Interview Connect

Knowing this algorithm's time complexity helps you explain efficient solutions clearly and confidently in interviews.

Self-Check

"What if we added a second loop to verify the candidate's count? How would the time complexity change?"

Practice

(1/5)
1. What is the main purpose of Moore's Voting Algorithm in arrays?
easy
A. To find the element that appears more than half the time
B. To sort the array in ascending order
C. To find the smallest element in the array
D. To reverse the array elements

Solution

  1. Step 1: Understand the problem Moore's Voting Algorithm solves

    It is designed to find the majority element, which is the element that appears more than half the times in the array.
  2. Step 2: Compare with other options

    Sorting, finding smallest, or reversing are unrelated to majority element detection.
  3. Final Answer:

    To find the element that appears more than half the time -> Option A
  4. Quick Check:

    Majority element = element appearing > n/2 times [OK]
Hint: Majority element appears more than half the array length [OK]
Common Mistakes:
  • Confusing majority element with most frequent element
  • Thinking it sorts the array
  • Assuming it finds smallest or largest element
2. Which of the following is the correct initialization step in Moore's Voting Algorithm in JavaScript?
easy
A. let count = 1, candidate = 0;
B. let count = 0, candidate = null;
C. let candidate = 0, count = null;
D. let count = null, candidate = 1;

Solution

  1. Step 1: Identify correct variable initialization

    Moore's Voting Algorithm starts with count = 0 and candidate = null (or undefined) to indicate no candidate chosen yet.
  2. Step 2: Check other options for correctness

    Options A, C, and D initialize count or candidate incorrectly, which can cause logic errors.
  3. Final Answer:

    let count = 0, candidate = null; -> Option B
  4. Quick Check:

    Initialize count=0 and candidate=null [OK]
Hint: Start count at 0 and candidate as null before loop [OK]
Common Mistakes:
  • Starting count at 1 instead of 0
  • Assigning candidate a number before selection
  • Swapping count and candidate initialization
3. What will be the output of the following JavaScript code?
function majorityElement(nums) {
  let count = 0, candidate = null;
  for (const num of nums) {
    if (count === 0) candidate = num;
    count += (num === candidate) ? 1 : -1;
  }
  return candidate;
}
console.log(majorityElement([2,2,1,1,1,2,2]));
medium
A. Error
B. 1
C. null
D. 2

Solution

  1. Step 1: Trace the loop and candidate updates

    Initial count=0, candidate=null. Iteration updates candidate and count as follows:
    - num=2: count=0, candidate=2, count=1
    - num=2: count=1, same candidate, count=2
    - num=1: count=2, different candidate, count=1
    - num=1: count=1, different candidate, count=0
    - num=1: count=0, candidate=1, count=1
    - num=2: count=1, different candidate, count=0
    - num=2: count=0, candidate=2, count=1
  2. Step 2: Final candidate after loop

    The candidate is 2 after the loop ends, which is the majority element.
  3. Final Answer:

    2 -> Option D
  4. Quick Check:

    Majority element found = 2 [OK]
Hint: Track count changes; candidate updates when count hits zero [OK]
Common Mistakes:
  • Assuming candidate never changes
  • Confusing count increments and decrements
  • Returning count instead of candidate
4. Identify the bug in this Moore's Voting Algorithm implementation:
function majorityElement(nums) {
  let count = 1, candidate = nums[0];
  for (let i = 1; i < nums.length; i++) {
    if (nums[i] === candidate) {
      count++;
    } else {
      count--;
      if (count === 0) {
        candidate = nums[i];
        count = 1;
      }
    }
  }
  return candidate;
}
medium
A. Initialization of count should be 0, not 1
B. Candidate should be initialized to null, not nums[0]
C. No bug, code is correct
D. Loop should start from i = 0, not i = 1

Solution

  1. Step 1: Analyze initialization and loop

    Starting count at 1 and candidate as nums[0] is a valid approach. Loop starts at i=1 to compare remaining elements.
  2. Step 2: Check logic inside loop

    Count increments if current equals candidate, else decrements. When count hits zero, candidate updates and count resets to 1. This matches Moore's Voting Algorithm logic.
  3. Final Answer:

    No bug, code is correct -> Option C
  4. Quick Check:

    Initialization and loop logic correct [OK]
Hint: Starting count=1 with first element candidate is valid [OK]
Common Mistakes:
  • Thinking count must start at 0
  • Assuming candidate must be null initially
  • Starting loop at wrong index
5. Given an array where no element appears more than half the time, what will Moore's Voting Algorithm return?
Example: [1, 2, 3, 4]
hard
A. An incorrect majority element
B. null or undefined (no majority element)
C. The first element of the array
D. The element with the highest frequency

Solution

  1. Step 1: Understand Moore's Voting Algorithm assumption

    The algorithm assumes a majority element exists (appears more than half the time). If none exists, it still returns a candidate but it may not be a true majority.
  2. Step 2: Analyze example array [1, 2, 3, 4]

    No element appears more than 2 times (half of 4). The algorithm will return a candidate but it is not a valid majority element.
  3. Final Answer:

    An incorrect majority element -> Option A
  4. Quick Check:

    No majority means algorithm returns wrong candidate [OK]
Hint: Algorithm assumes majority exists; else result may be wrong [OK]
Common Mistakes:
  • Assuming algorithm returns null if no majority
  • Thinking it returns highest frequency element always
  • Believing it returns first element by default
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