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DSA Javascriptprogramming~30 mins

KMP Pattern Matching Algorithm in DSA Javascript - Build from Scratch

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KMP Pattern Matching Algorithm
📖 Scenario: You are building a simple text search tool that finds if a small pattern exists inside a larger text efficiently. This is useful in searching documents, DNA sequences, or logs.
🎯 Goal: Build the KMP (Knuth-Morris-Pratt) pattern matching algorithm step-by-step in JavaScript to find the first occurrence of a pattern in a text.
📋 What You'll Learn
Create an array called lps to store longest prefix suffix values
Create a function computeLPSArray to fill the lps array for the pattern
Create a function KMPSearch that uses lps to find the pattern in the text
Print the index of the first match or -1 if not found
💡 Why This Matters
🌍 Real World
Text search is used in editors, search engines, DNA sequence analysis, and log scanning to quickly find patterns.
💼 Career
Understanding KMP algorithm helps in software development roles involving string processing, data analysis, and algorithm optimization.
Progress0 / 4 steps
1
Create the text and pattern variables
Create two string variables called text and pattern with values 'ABABDABACDABABCABAB' and 'ABABCABAB' respectively.
DSA Javascript
Hint

Use const to declare text and pattern with the exact strings given.

2
Create the lps array and computeLPSArray function
Create an array called lps with length equal to pattern.length filled with zeros. Then create a function called computeLPSArray that takes pattern and lps as parameters and fills lps with longest prefix suffix values using the KMP preprocessing logic.
DSA Javascript
Hint

Initialize lps with zeros. Use a while loop and two pointers i and length to fill lps according to KMP rules.

3
Create the KMPSearch function using lps
Create a function called KMPSearch that takes pattern and text as parameters. Inside it, create an array lps and call computeLPSArray(pattern, lps). Then use two indexes i for text and j for pattern to find the first occurrence of pattern in text using the KMP algorithm. Return the index of the first match or -1 if not found.
DSA Javascript
Hint

Use two pointers i and j to scan text and pattern. Use lps to skip characters when mismatch happens.

4
Print the index of the first pattern match in the text
Call the function KMPSearch with pattern and text and print the returned index using console.log.
DSA Javascript
Hint

Call KMPSearch(pattern, text) and print the result with console.log.

Practice

(1/5)
1. What is the main purpose of the KMP (Knuth-Morris-Pratt) pattern matching algorithm?
easy
A. To sort an array of numbers in ascending order
B. To find occurrences of a pattern string within a text efficiently
C. To reverse a string in linear time
D. To calculate the factorial of a number recursively

Solution

  1. Step 1: Understand the problem KMP solves

    KMP is designed to find all occurrences of a pattern inside a text without rechecking characters unnecessarily.
  2. Step 2: Compare with other options

    Sorting, reversing strings, and factorial calculation are unrelated to pattern searching.
  3. Final Answer:

    To find occurrences of a pattern string within a text efficiently -> Option B
  4. Quick Check:

    KMP = Pattern searching [OK]
Hint: KMP is about searching patterns fast in text [OK]
Common Mistakes:
  • Confusing KMP with sorting algorithms
  • Thinking KMP reverses strings
  • Assuming KMP calculates factorials
2. Which of the following is the correct way to initialize the prefix array (lps) in the KMP algorithm in JavaScript?
easy
A. const lps = new Array(pattern.length).fill(null);
B. const lps = Array(pattern.length);
C. const lps = []; lps.length = pattern.length;
D. const lps = new Array(pattern.length).fill(0);

Solution

  1. Step 1: Understand prefix array initialization

    The prefix array (lps) must be initialized with zeros to store lengths of longest prefix suffix.
  2. Step 2: Check each option

    const lps = new Array(pattern.length).fill(0); correctly creates an array of the pattern's length filled with zeros. const lps = Array(pattern.length); creates an array but leaves elements undefined. const lps = []; lps.length = pattern.length; sets length but elements are undefined. const lps = new Array(pattern.length).fill(null); fills with null, which is incorrect.
  3. Final Answer:

    const lps = new Array(pattern.length).fill(0); -> Option D
  4. Quick Check:

    Prefix array = zeros [OK]
Hint: Prefix array must start with zeros for correct matching [OK]
Common Mistakes:
  • Leaving prefix array elements undefined
  • Filling prefix array with null instead of zero
  • Not initializing prefix array length
3. What will be the output of the following JavaScript code snippet using KMP to find pattern 'ABABC' in text 'ABABABCABABCBC'?
function KMPSearch(pattern, text) {
  const lps = computeLPSArray(pattern);
  let i = 0, j = 0;
  const result = [];
  while (i < text.length) {
    if (pattern[j] === text[i]) {
      i++; j++;
      if (j === pattern.length) {
        result.push(i - j);
        j = lps[j - 1];
      }
    } else if (j !== 0) {
      j = lps[j - 1];
    } else {
      i++;
    }
  }
  return result;
}

function computeLPSArray(pattern) {
  const lps = new Array(pattern.length).fill(0);
  let length = 0, i = 1;
  while (i < pattern.length) {
    if (pattern[i] === pattern[length]) {
      length++;
      lps[i] = length;
      i++;
    } else if (length !== 0) {
      length = lps[length - 1];
    } else {
      lps[i] = 0;
      i++;
    }
  }
  return lps;
}

console.log(KMPSearch('ABABC', 'ABABABCABABCBC'));
medium
A. [1, 6]
B. [0, 5]
C. [2, 7]
D. [3, 8]

Solution

  1. Step 1: Compute LPS array for pattern 'ABABC'

    LPS array is [0, 0, 1, 2, 0]. This helps skip characters on mismatch.
  2. Step 2: Trace pattern matches in text 'ABABABCABABCBC'

    Pattern matches start at index 2 and again at index 7 in the text.
  3. Final Answer:

    [2, 7] -> Option C
  4. Quick Check:

    Match indices = [2, 7] [OK]
Hint: Use LPS to jump and find pattern start indices [OK]
Common Mistakes:
  • Incorrect LPS array calculation
  • Off-by-one errors in indices
  • Confusing pattern length with text length
4. Identify the bug in this KMP prefix array computation code snippet:
function computeLPSArray(pattern) {
  const lps = new Array(pattern.length).fill(0);
  let length = 0;
  let i = 0;
  while (i < pattern.length) {
    if (pattern[i] === pattern[length]) {
      length++;
      lps[i] = length;
      i++;
    } else if (length !== 0) {
      length = lps[length - 1];
    } else {
      lps[i] = 0;
      i++;
    }
  }
  return lps;
}
medium
A. The loop should start with i = 1, not i = 0
B. The length variable should be initialized to 1
C. The lps array should be filled with -1 instead of 0
D. The condition pattern[i] === pattern[length] should be reversed

Solution

  1. Step 1: Check loop initialization

    The prefix array computation starts from index 1 because index 0 always has lps value 0.
  2. Step 2: Identify impact of starting at i=0

    Starting at i=0 causes comparing pattern[0] with pattern[0] unnecessarily and overwrites lps[0], which should remain 0.
  3. Final Answer:

    The loop should start with i = 1, not i = 0 -> Option A
  4. Quick Check:

    Start loop at 1 for prefix array [OK]
Hint: Prefix array loop always starts at 1 [OK]
Common Mistakes:
  • Starting loop at 0
  • Initializing length incorrectly
  • Filling lps with wrong values
5. Given a large text and a pattern, how can you modify the KMP algorithm to count overlapping occurrences of the pattern in the text? For example, pattern 'AAA' in text 'AAAAA' occurs 3 times (positions 0,1,2). Which change is correct?
hard
A. After a match, set j = lps[j - 1] instead of resetting j to 0
B. After a match, increment i by pattern length to skip matched part
C. After a match, reset both i and j to 0 to restart search
D. After a match, increment j by 1 to continue matching

Solution

  1. Step 1: Understand overlapping matches

    Overlapping matches require continuing search from the longest proper prefix which is also suffix, not restarting.
  2. Step 2: Apply correct jump after match

    Setting j = lps[j - 1] after a match allows the algorithm to find overlapping occurrences without missing any.
  3. Final Answer:

    After a match, set j = lps[j - 1] instead of resetting j to 0 -> Option A
  4. Quick Check:

    Use lps jump to count overlaps [OK]
Hint: Use lps jump after match to find overlaps [OK]
Common Mistakes:
  • Resetting j to 0 after match
  • Skipping characters by incrementing i too much
  • Not handling overlaps correctly
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10 questions~5 mineasy hard