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DSA Javascriptprogramming~10 mins

Doubly Linked List Structure and Node Design in DSA Javascript - Execution Trace

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Concept Flow - Doubly Linked List Structure and Node Design
Create new node
↓
Set node.data, node.prev, node.next
↓
If list empty?
Yes→head = node, tail = node
No↓
Link new node with tail
↓
Update tail to new node
↓
Done
Shows how a new node is created and linked in a doubly linked list, updating pointers for both previous and next nodes.
Execution Sample
DSA Javascript
class Node {
  constructor(data) {
    this.data = data;
    this.prev = null;
    this.next = null;
  }
}
Defines a doubly linked list node with data and two pointers: prev and next.
Execution Table
StepOperationNodes in ListPointer ChangesVisual State
1Create node with data=10Nonenode.prev=null, node.next=nullnull <- [10] -> null
2List empty? YesNonehead=node, tail=node[10]
3Create node with data=20[10]node.prev=null, node.next=null[10]
4List empty? No[10]tail.next=node, node.prev=tail[10] <-> [20]
5Update tail to new node[10] <-> [20]tail=node[10] <-> [20]
6Create node with data=30[10] <-> [20]node.prev=null, node.next=null[10] <-> [20]
7List empty? No[10] <-> [20]tail.next=node, node.prev=tail[10] <-> [20] <-> [30]
8Update tail to new node[10] <-> [20] <-> [30]tail=node[10] <-> [20] <-> [30]
9End of insertion[10] <-> [20] <-> [30]No changes[10] <-> [20] <-> [30]
💡 All nodes inserted, list updated with correct prev and next pointers.
Variable Tracker
VariableStartAfter Step 1After Step 3After Step 6Final
headnull[10][10][10][10]
tailnull[10][10][20][30]
nodenull[10][20][30]null
Key Moments - 3 Insights
Why do we set node.prev to tail before updating tail?
Because the new node must point back to the current tail before tail moves to the new node, as shown in steps 4 and 7 in the execution_table.
What happens if the list is empty when inserting the first node?
The head and tail both point to the new node, making it the only node in the list, as shown in step 2.
Why do we set node.next to null when creating a new node?
Because the new node is added at the end, so it has no next node yet, as shown in steps 1, 3, and 6.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table at step 4, what pointer changes happen?
Anew node.prev and new node.next both point to null
Btail.next points to new node, new node.prev points to tail
Chead points to new node, new node.next points to head
Dtail is set to null
💡 Hint
Check the 'Pointer Changes' column at step 4 in the execution_table.
At which step does the tail pointer update to the new node for the second time?
AStep 8
BStep 5
CStep 7
DStep 9
💡 Hint
Look at the 'Pointer Changes' column for tail updates in the execution_table.
If the list was empty, what would be the visual state after inserting the first node?
A[10] <-> [20] <-> [30]
B[10] <-> [20]
Cnull <- [10] -> null
Dnull
💡 Hint
Refer to step 1 and 2 visual states in the execution_table.
Concept Snapshot
Doubly Linked List Node:
- Has data, prev, next pointers
- prev points to previous node or null
- next points to next node or null
Insertion:
- Create node with data
- If empty, head and tail = node
- Else, link node.prev to tail, tail.next to node
- Update tail to new node
Full Transcript
This visual trace shows how a doubly linked list node is created and inserted at the end of the list. Each node has three parts: data, prev pointer, and next pointer. When the list is empty, the new node becomes both head and tail. For subsequent insertions, the new node's prev pointer links to the current tail, and the current tail's next pointer links to the new node. Then the tail pointer updates to the new node. The visual states show the list growing step by step with arrows indicating prev and next links.

Practice

(1/5)
1. What is the main difference between a doubly linked list node and a singly linked list node?
easy
A. A doubly linked list node does not store any data.
B. A doubly linked list node stores data in a different format.
C. A doubly linked list node can only point to the next node.
D. A doubly linked list node has pointers to both the next and previous nodes.

Solution

  1. Step 1: Understand node pointers in singly linked list

    A singly linked list node has only one pointer to the next node.
  2. Step 2: Understand node pointers in doubly linked list

    A doubly linked list node has two pointers: one to the next node and one to the previous node.
  3. Final Answer:

    A doubly linked list node has pointers to both the next and previous nodes. -> Option D
  4. Quick Check:

    Doubly linked list nodes have two pointers [OK]
Hint: Remember: doubly means two pointers, singly means one [OK]
Common Mistakes:
  • Thinking doubly linked list nodes store data differently
  • Confusing the number of pointers in singly vs doubly linked nodes
  • Assuming doubly linked nodes do not store data
2. Which of the following is the correct way to define a doubly linked list node class in JavaScript?
easy
A. class Node { constructor(data) { this.data = data; this.next = null; } }
B. class Node { constructor(data) { this.data = data; this.next = null; this.prev = null; } }
C. class Node { constructor(data) { this.data = data; this.prev = null; } }
D. class Node { constructor(data) { this.next = null; this.prev = null; } }

Solution

  1. Step 1: Check for data property in constructor

    The node must store data, so constructor should assign this.data = data.
  2. Step 2: Check for both next and prev pointers

    A doubly linked list node must have this.next and this.prev initialized to null.
  3. Final Answer:

    class Node { constructor(data) { this.data = data; this.next = null; this.prev = null; } } -> Option B
  4. Quick Check:

    Doubly linked list node has data, next, and prev [OK]
Hint: Doubly linked nodes always have next and prev pointers [OK]
Common Mistakes:
  • Omitting the prev pointer
  • Not initializing next or prev to null
  • Forgetting to assign data in constructor
3. Given the following code, what will be the output after inserting nodes 10 and 20 into an empty doubly linked list?
class Node {
  constructor(data) {
    this.data = data;
    this.next = null;
    this.prev = null;
  }
}

class DoublyLinkedList {
  constructor() {
    this.head = null;
  }
  insert(data) {
    const newNode = new Node(data);
    if (!this.head) {
      this.head = newNode;
      return;
    }
    let current = this.head;
    while (current.next) {
      current = current.next;
    }
    current.next = newNode;
    newNode.prev = current;
  }
  print() {
    let current = this.head;
    let result = '';
    while (current) {
      result += current.data + ' <-> ';
      current = current.next;
    }
    result += 'null';
    console.log(result);
  }
}

const list = new DoublyLinkedList();
list.insert(10);
list.insert(20);
list.print();
medium
A. 10 <-> 20 <-> null
B. 20 <-> 10 <-> null
C. 10 -> 20 -> null
D. null

Solution

  1. Step 1: Insert 10 into empty list

    Since head is null, head becomes node with data 10.
  2. Step 2: Insert 20 at the end

    Traverse to last node (10), set its next to new node 20, and new node's prev to 10.
  3. Step 3: Print list

    Traverse from head: 10 <-> 20 <-> null is printed.
  4. Final Answer:

    10 <-> 20 <-> null -> Option A
  5. Quick Check:

    Insertion appends nodes in order [OK]
Hint: Insertion appends nodes at end, so order is insertion order [OK]
Common Mistakes:
  • Confusing order of nodes after insertion
  • Using single arrow -> instead of double <->
  • Printing null instead of list contents
4. Identify the error in the following doubly linked list insertion method and select the correct fix:
insert(data) {
  const newNode = new Node(data);
  if (!this.head) {
    this.head = newNode;
    return;
  }
  let current = this.head;
  while (current.next) {
    current = current.next;
  }
  current.next = newNode;
  // Missing line here
}
medium
A. Add 'newNode.prev = current;' after 'current.next = newNode;'
B. Add 'current.prev = newNode;' after 'current.next = newNode;'
C. Add 'this.head.prev = newNode;' after 'current.next = newNode;'
D. No fix needed; code is correct

Solution

  1. Step 1: Understand pointer updates in insertion

    When adding newNode after current, newNode.prev must point back to current.
  2. Step 2: Identify missing pointer assignment

    Code sets current.next = newNode but does not set newNode.prev = current, breaking backward link.
  3. Final Answer:

    Add 'newNode.prev = current;' after 'current.next = newNode;' -> Option A
  4. Quick Check:

    Backward link must be set for doubly linked list [OK]
Hint: Always set newNode.prev to current when inserting at end [OK]
Common Mistakes:
  • Forgetting to set newNode.prev
  • Setting current.prev instead of newNode.prev
  • Assuming no fix needed
5. You want to implement a method to delete a node with a given value from a doubly linked list. Which of the following steps is NOT necessary for correctly removing the node?
hard
A. Update the previous node's next pointer to skip the deleted node.
B. Update the next node's prev pointer to skip the deleted node.
C. Traverse the list backwards from tail to find the node.
D. Set the deleted node's next and prev pointers to null.

Solution

  1. Step 1: Understand deletion pointer updates

    To remove a node, update previous node's next and next node's prev to bypass it.
  2. Step 2: Check necessity of clearing deleted node pointers

    Setting deleted node's next and prev to null helps garbage collection and avoids dangling pointers.
  3. Step 3: Analyze traversal direction

    Traversing backwards from tail is not necessary; forward traversal from head suffices to find node.
  4. Final Answer:

    Traverse the list backwards from tail to find the node. -> Option C
  5. Quick Check:

    Forward traversal is enough to find node for deletion [OK]
Hint: Deletion needs pointer updates, not backward traversal [OK]
Common Mistakes:
  • Thinking backward traversal is required
  • Ignoring pointer updates on neighbors
  • Not clearing deleted node pointers
Recommended

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10 questions~5 mineasy hard