A dequeue is a data structure where elements can be added or removed from both the front and the rear ends.
Click to reveal answer
beginner
Name the four main operations of a dequeue.
The four main operations are: insertFront, insertRear, deleteFront, and deleteRear.
Click to reveal answer
beginner
What happens when you perform deleteFront on an empty dequeue?
Since the dequeue is empty, deleteFront cannot remove any element and usually returns an error or null.
Click to reveal answer
beginner
How does deleteRear operation work in a dequeue?
deleteRear removes the element from the rear end of the dequeue and returns it, reducing the dequeue size by one.
Click to reveal answer
intermediate
Why is a dequeue useful compared to a normal queue?
A dequeue is more flexible because it allows insertion and deletion from both ends, unlike a normal queue which only allows these operations at fixed ends.
Click to reveal answer
Which operation removes an element from the front of a dequeue?
AinsertRear
BdeleteFront
CinsertFront
DdeleteRear
✗ Incorrect
deleteFront removes the element from the front end of the dequeue.
What is the result of deleteRear on a dequeue with elements [1, 2, 3] (front to rear)?
ARemoves 3
BRemoves 1
CRemoves 2
DNo removal
✗ Incorrect
deleteRear removes the element at the rear, which is 3.
Which operation adds an element to the front of a dequeue?
AinsertFront
BdeleteFront
CinsertRear
DdeleteRear
✗ Incorrect
insertFront adds an element at the front end of the dequeue.
If a dequeue is empty, what happens when deleteFront is called?
ARemoves last element
BRemoves from rear
CAdds an element
DReturns error or null
✗ Incorrect
You cannot remove from an empty dequeue; it returns error or null.
Which data structure allows insertion and deletion from both ends?
AStack
BQueue
CDequeue
DLinked List
✗ Incorrect
Dequeue supports insertion and deletion at both front and rear ends.
Explain the deleteFront and deleteRear operations in a dequeue with an example.
Think about removing elements from both ends and how the dequeue changes.
You got /4 concepts.
Describe why a dequeue is more flexible than a normal queue and give a real-life example.
Consider how people can enter or leave from both ends in some situations.
You got /3 concepts.
Practice
(1/5)
1. What is a dequeue in data structures?
easy
A. A stack that allows only last-in, first-out operations
B. A queue where elements can only be added at the front
C. A list that only allows insertion at the middle
D. A double-ended queue where elements can be added or removed from both ends
Solution
Step 1: Understand the definition of dequeue
A dequeue is a data structure that allows insertion and deletion from both front and rear ends.
Step 2: Compare options with definition
A double-ended queue where elements can be added or removed from both ends correctly describes a dequeue. Options A, B, and D describe other structures or incorrect behaviors.
Final Answer:
A double-ended queue where elements can be added or removed from both ends -> Option D
Quick Check:
Dequeue = Double-ended queue [OK]
Hint: Dequeue means double-ended queue, both ends allowed [OK]
Common Mistakes:
Confusing dequeue with stack or normal queue
Thinking elements can only be added at one end
Assuming dequeue is a type of list
2. Which of the following is the correct syntax to add an element 5 at the front of a dequeue named dq in JavaScript using an array?
easy
A. dq.pushFront(5);
B. dq.unshift(5);
C. dq.addFront(5);
D. dq.insertFront(5);
Solution
Step 1: Recall JavaScript array methods for front insertion
JavaScript arrays use unshift() to add elements at the front.
Step 2: Match method with options
Only dq.unshift(5); uses unshift(5), which is correct. Other options are invalid methods.
Final Answer:
dq.unshift(5); -> Option B
Quick Check:
Array front insert = unshift() [OK]
Hint: Use unshift() to add at front in JS arrays [OK]
Common Mistakes:
Using pushFront which is not a JS array method
Confusing push (adds at end) with front insertion
Assuming addFront or insertFront exist in JS arrays
3. What will be the output of the following code?
let dq = [];
dq.push(10);
dq.unshift(20);
dq.push(30);
dq.shift();
console.log(dq);
medium
A. [10, 30]
B. [20, 10, 30]
C. [20, 30]
D. [10, 20, 30]
Solution
Step 1: Trace each operation on the dequeue array
Start with empty dq = []. push(10) adds 10 at end: [10]. unshift(20) adds 20 at front: [20, 10]. push(30) adds 30 at end: [20, 10, 30]. shift() removes front element (20): [10, 30].
Step 2: Determine final state of dq
After all operations, dq is [10, 30].
Final Answer:
[10, 30] -> Option A
Quick Check:
After shift(), front removed, dq = [10, 30] [OK]
Hint: Remember shift() removes front, push() adds end [OK]
Common Mistakes:
Confusing shift() with pop()
Mixing order of unshift and push
Forgetting shift() removes front element
4. Identify the error in the following dequeue operation code:
let dq = [];
dq.push(1);
dq.popFront();
console.log(dq);
medium
A. popFront() is not a valid JavaScript array method
B. push() cannot be used on empty arrays
C. popFront() should be pop() to remove last element
D. dq should be initialized as a Dequeue object, not array
Solution
Step 1: Check JavaScript array methods used
JavaScript arrays do not have a method named popFront(). The correct method to remove front element is shift().
Step 2: Identify the error
Using popFront() causes a runtime error as it is undefined.
Final Answer:
popFront() is not a valid JavaScript array method -> Option A
Quick Check:
popFront() invalid in JS arrays [OK]
Hint: Use shift() to remove front, pop() for end [OK]
Common Mistakes:
Assuming popFront() exists like pop()
Confusing pop() with front removal
Not knowing shift() removes front element
5. You have a dequeue implemented as a JavaScript array dq with elements [5, 10, 15, 20]. You want to remove the element 5 from the front and add 25 at the rear, then remove the element 20 from the rear and add 30 at the front. What will be the final state of dq?
hard
A. [30, 5, 10, 15, 25]
B. [10, 15, 25, 30]
C. [30, 10, 15, 25]
D. [10, 15, 20, 25, 30]
Solution
Step 1: Remove front element
Start dq = [5, 10, 15, 20]. Remove front element 5 using shift(): dq = [10, 15, 20]. Rear is now 20.
Step 2: Remove rear, add rear, add front
Remove rear element 20 using pop(): dq = [10, 15]. Add 25 at rear using push(): dq = [10, 15, 25]. Add 30 at front using unshift(): dq = [30, 10, 15, 25].