What does 'Delete Node at End' mean in a linked list?
It means removing the last node from the linked list, so the second last node becomes the new end.
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beginner
In a singly linked list, why do we need to traverse the list to delete the last node?
Because each node only knows the next node, we must find the second last node to update its next pointer to null.
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beginner
What happens if we try to delete the last node in an empty linked list?
Nothing happens because the list is empty; there is no node to delete.
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intermediate
What is the time complexity of deleting the last node in a singly linked list?
O(n), because we need to traverse the list to find the second last node.
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intermediate
Show the JavaScript code snippet to delete the last node from a singly linked list.
function deleteAtEnd(head) {
if (!head) return null;
if (!head.next) return null;
let current = head;
while (current.next.next) {
current = current.next;
}
current.next = null;
return head;
}
Click to reveal answer
What pointer do we update when deleting the last node in a singly linked list?
AThe previous pointer of the last node
BThe head pointer
CThe next pointer of the second last node
DThe next pointer of the last node
✗ Incorrect
We update the next pointer of the second last node to null to remove the last node.
What is the result of deleting the last node from a list with only one node?
AThe list remains the same
BAn error occurs
CThe head points to the deleted node
DThe list becomes empty
✗ Incorrect
Deleting the only node leaves the list empty (head becomes null).
Which of these is true about deleting the last node in a singly linked list?
AIt requires traversing the list to find the second last node
BIt can be done in O(1) time without traversal
CIt requires updating the head pointer always
DIt is impossible
✗ Incorrect
Because nodes only point forward, we must find the second last node to update its next pointer.
What happens if you try to delete the last node from an empty list?
AThe list crashes
BNothing, the list stays empty
CA new node is added
DThe head pointer is set to a new node
✗ Incorrect
Deleting from an empty list does nothing; the list remains empty.
In the code snippet for deleting the last node, what does 'current.next = null' do?
ARemoves the last node by breaking the link
BAdds a new node at the end
CMoves the head pointer
DDeletes the entire list
✗ Incorrect
Setting current.next to null removes the last node by breaking the link to it.
Explain step-by-step how to delete the last node in a singly linked list.
Think about how nodes point only forward and how to find the node before the last.
You got /5 concepts.
Write a simple JavaScript function to delete the last node from a singly linked list and explain its logic.
Use a loop to find the node before the last and then remove the last node.
You got /5 concepts.
Practice
(1/5)
1. What does the operation Delete Node at End do in a singly linked list?
easy
A. Adds a new node at the end of the linked list
B. Removes the first node from the linked list
C. Removes the last node from the linked list
D. Adds a new node at the beginning of the linked list
Solution
Step 1: Understand the linked list structure
A singly linked list is a chain of nodes where each node points to the next node, ending with a node pointing to null.
Step 2: Identify what deleting the last node means
Deleting the last node means removing the node that points to null, effectively shortening the list by one node at the end.
Final Answer:
Removes the last node from the linked list -> Option C
Quick Check:
Delete Node at End = Remove last node [OK]
Hint: Last node points to null; delete it to remove end [OK]
Common Mistakes:
Confusing delete at end with delete at start
Thinking it adds a node instead of removing
Assuming it deletes a middle node
2. Which of the following is the correct syntax to delete the last node in a singly linked list in JavaScript?
easy
A. list.deleteEnd();
B. list.pop();
C. list.deleteNodeAtEnd();
D. list.removeLastNode();
Solution
Step 1: Recognize common JavaScript linked list methods
JavaScript arrays use pop() to remove the last element; custom linked lists often implement similar methods.
Step 2: Identify the standard method name
Among the options, pop() is the standard method name used to remove the last element in many list implementations.
Final Answer:
list.pop(); -> Option B
Quick Check:
pop() removes last element [OK]
Hint: pop() usually removes last element in lists [OK]
Common Mistakes:
Using non-standard method names
Confusing delete with remove
Assuming deleteEnd() is built-in
3. Consider the following JavaScript code for a singly linked list deletion at end:
class Node {
constructor(data) {
this.data = data;
this.next = null;
}
}
class LinkedList {
constructor() {
this.head = null;
}
deleteAtEnd() {
if (!this.head) return null;
if (!this.head.next) {
this.head = null;
return;
}
let current = this.head;
while (current.next.next) {
current = current.next;
}
current.next = null;
}
}
let list = new LinkedList();
list.head = new Node(1);
list.head.next = new Node(2);
list.head.next.next = new Node(3);
list.deleteAtEnd();
let result = [];
let temp = list.head;
while(temp) {
result.push(temp.data);
temp = temp.next;
}
console.log(result);
What will be printed?
medium
A. [1, 2, 3]
B. [2, 3]
C. [1]
D. [1, 2]
Solution
Step 1: Understand the initial list and deletion
The list starts as 1 -> 2 -> 3. The deleteAtEnd() method removes the last node (3).
Step 2: Trace the deletion and final list
After deletion, the list becomes 1 -> 2. The loop collects these values into the array [1, 2].
Final Answer:
[1, 2] -> Option D
Quick Check:
Deleting last node removes 3, leaving [1, 2] [OK]
Hint: Deleting end removes last node, so last value drops [OK]
Common Mistakes:
Forgetting to update the second last node's next to null
Assuming the head changes incorrectly
Not handling single-node list case
4. The following code tries to delete the last node of a singly linked list but causes an error:
deleteAtEnd() {
let current = this.head;
while (current.next) {
current = current.next;
}
current = null;
}
What is the main problem?
medium
A. It sets the local variable to null but does not update the list
B. It does not handle empty list case
C. It deletes the head node instead of last node
D. It causes infinite loop
Solution
Step 1: Analyze the loop and pointer update
The loop moves current to the last node, but setting current = null only changes the local variable, not the list's links.
Step 2: Understand why the last node is not removed
To remove the last node, the previous node's next must be set to null. This code misses that step.
Final Answer:
It sets the local variable to null but does not update the list -> Option A
Quick Check:
Local variable null doesn't remove node [OK]
Hint: Update previous node's next, not local pointer [OK]
Common Mistakes:
Setting current to null instead of previous.next
Not checking for single-node list
Ignoring empty list case
5. You have a singly linked list with nodes: 10 -> 20 -> 30 -> 40. You want to delete the last node and then add a new node with value 50 at the end. Which sequence of operations correctly achieves this?
hard
A. Call deleteAtEnd(), then call addAtEnd(50)
B. Call addAtEnd(50), then call deleteAtEnd()
C. Call deleteAtEnd() twice, then addAtEnd(50)
D. Call deleteAtEnd(), then addAtStart(50)
Solution
Step 1: Delete the last node
Calling deleteAtEnd() removes the node with value 40, list becomes 10 -> 20 -> 30.
Step 2: Add new node at the end
Calling addAtEnd(50) adds a new node with value 50 at the end, list becomes 10 -> 20 -> 30 -> 50.
Final Answer:
Call deleteAtEnd(), then call addAtEnd(50) -> Option A
Quick Check:
Delete last then add new last node [OK]
Hint: Delete last first, then add new node at end [OK]
Common Mistakes:
Adding before deleting causes wrong order
Deleting twice removes too many nodes
Adding at start changes list order
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