Why Delete Node at Beginning in DSA Javascript?

The Big Idea

What if you could remove the first item instantly without moving everyone else?

The Scenario

Imagine you have a line of people waiting to buy tickets. If the first person leaves, everyone else has to move forward manually to fill the gap.

The Problem

Manually shifting everyone forward is slow and confusing. You might lose track of who is next or accidentally skip someone.

The Solution

Using a linked list, you can simply remove the first person by changing the start point to the next person, without moving anyone else.

Before vs After

✗ Before

let queue = ["Alice", "Bob", "Charlie"];
queue.shift(); // removes first but shifts all elements

✓ After

let head = {value: "Alice", next: {value: "Bob", next: {value: "Charlie", next: null}}};
head = head.next; // removes first node by moving head

What It Enables

You can quickly remove the first item without touching the rest, making operations fast and simple.

Real Life Example

In a printer queue, when a print job finishes, it is removed instantly from the front so the next job starts immediately.

Key Takeaways

Manual shifting is slow and error-prone.

Linked lists let you remove the first node by just moving the head pointer.

This makes deleting at the beginning fast and easy.

Practice

1. What happens to the head pointer when you delete the first node in a singly linked list?

easy

A. It moves to the next node in the list

B. It becomes null immediately

C. It points to the last node

D. It remains unchanged

Solution

1. Step 1: Understand the head pointer role

   The head pointer points to the first node in the list.

2. Step 2: Effect of deleting the first node

   Deleting the first node means the head must now point to the second node, which becomes the new first node.

3. Final Answer:

   It moves to the next node in the list -> Option A

4. Quick Check:

   Head points to next node after deletion [OK]

Hint: Head always moves to next node when deleting first [OK]

Common Mistakes:

• Assuming head becomes null even if list has more nodes
• Thinking head points to last node after deletion
• Not updating head pointer at all

2. Which of the following is the correct syntax to delete the first node in a singly linked list in JavaScript?

easy

A. delete head;

B. head.next = head;

C. head = head.next;

D. head = null.next;

Solution

1. Step 1: Understand how to move head pointer

   To delete the first node, assign head to head.next to skip the first node.

2. Step 2: Check each option

   head = head.next; correctly assigns head to head.next. head.next = head; reverses pointers incorrectly. delete head; deletes the variable but not the node. head = null.next; is invalid syntax.

3. Final Answer:

   head = head.next; -> Option C

4. Quick Check:

   Assign head to head.next to delete first node [OK]

Hint: Use head = head.next to remove first node [OK]

Common Mistakes:

• Using delete keyword incorrectly
• Assigning head.next to head instead of head to head.next
• Using invalid syntax like null.next

3. Consider the following linked list code in JavaScript:

class Node {
  constructor(data) {
    this.data = data;
    this.next = null;
  }
}

let head = new Node(10);
head.next = new Node(20);
head.next.next = new Node(30);

// Delete first node
head = head.next;

// Print list
let current = head;
let result = [];
while(current) {
  result.push(current.data);
  current = current.next;
}
console.log(result);

What will be printed?

medium

A. []

B. [10, 20, 30]

C. [30]

D. [20, 30]

Solution

1. Step 1: Initial linked list nodes

   The list has nodes with data 10 -> 20 -> 30.

2. Step 2: Deleting first node by head = head.next

   Head moves from node 10 to node 20, so node 10 is removed.

3. Step 3: Printing remaining nodes

   Starting from new head (20), the list is 20 -> 30, so result array is [20, 30].

4. Final Answer:

   [20, 30] -> Option D

5. Quick Check:

   After deletion, list starts at 20 [OK]

Hint: Deleting first node skips first data in output [OK]

Common Mistakes:

• Printing original list without deletion
• Confusing head.next with head
• Forgetting to update head pointer

4. The following code attempts to delete the first node of a linked list but causes an error:

head.next = head.next.next;

What is the problem with this code if head points to the first node?

medium

A. It deletes the second node instead of the first node

B. It causes a runtime error if head.next is null

C. It correctly deletes the first node

D. It sets head to null incorrectly

Solution

1. Step 1: Analyze what head.next = head.next.next does

   This changes the next pointer of the first node to skip the second node, effectively deleting the second node.

2. Step 2: Check if first node is deleted

   The head pointer still points to the first node, so the first node is not deleted.

3. Final Answer:

   It deletes the second node instead of the first node -> Option A

4. Quick Check:

   head.next changes second node, not head itself [OK]

Hint: Changing head.next skips second node, not first [OK]

Common Mistakes:

• Thinking this deletes the first node
• Ignoring possible null pointer if list has one node
• Confusing head and head.next pointers

5. You have a singly linked list with nodes: 5 -> 10 -> 15 -> 20. Write a function in JavaScript to delete the first node and return the new head. What will be the list after deletion?

hard

A. 20

B. 10 -> 15 -> 20

C. 15 -> 20

D. 5 -> 10 -> 15 -> 20

Solution

1. Step 1: Write function to delete first node

   Function returns head.next to skip first node:
   function deleteFirstNode(head) { return head ? head.next : null; }

2. Step 2: Apply function to list 5 -> 10 -> 15 -> 20

   New head points to node with data 10, so list becomes 10 -> 15 -> 20.

3. Final Answer:

   10 -> 15 -> 20 -> Option B

4. Quick Check:

   Deleting first node moves head to second node [OK]

Hint: Return head.next to delete first node [OK]

Common Mistakes:

• Returning head instead of head.next
• Not handling empty list (null head)
• Deleting wrong node by changing next pointers incorrectly