A circular linked list is a linked list where the last node points back to the first node, forming a circle. There is no null at the end.
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intermediate
Why is deleting a node from a circular linked list different from a singly linked list?
Because the last node points back to the head, we must update the last node's next pointer if we delete the head. Also, we must handle the circular link carefully to avoid breaking the circle.
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intermediate
What steps do you follow to delete a node with a given value from a circular linked list?
1. Find the node to delete and its previous node. 2. If the node is the only node, set head to null. 3. If deleting head, update head to next node. 4. Update previous node's next pointer to skip the deleted node. 5. Maintain the circular link.
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beginner
What happens if you delete the only node in a circular linked list?
The list becomes empty, so the head pointer should be set to null to indicate the list has no nodes.
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intermediate
How do you handle deleting the head node in a circular linked list?
You find the last node to update its next pointer to the new head (which is head.next), then update the head pointer to head.next.
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In a circular linked list, what does the last node point to?
AItself
BNull
CThe first node
DThe previous node
✗ Incorrect
In a circular linked list, the last node points back to the first node, forming a circle.
What should you do if the node to delete is the only node in the circular linked list?
ASet head to null
BSet head to itself
CDo nothing
DCreate a new node
✗ Incorrect
If the only node is deleted, the list becomes empty, so head should be set to null.
When deleting the head node in a circular linked list, what must you update?
AOnly the head pointer
BThe last node's next pointer and the head pointer
COnly the last node's next pointer
DNothing
✗ Incorrect
You must update the last node's next pointer to the new head and update the head pointer itself.
If you want to delete a node with value X, what is the first step?
AFind the node with value X and its previous node
BDelete the head node
CSet head to null
DCreate a new node
✗ Incorrect
You first find the node to delete and its previous node to update pointers correctly.
What happens if you forget to update the last node's next pointer when deleting the head?
AThe head pointer will be null
BThe list remains circular
CThe list will have duplicate nodes
DThe list will break and no longer be circular
✗ Incorrect
If the last node's next pointer is not updated, the circular link breaks and the list is corrupted.
Explain how to delete a node from a circular linked list, including special cases.
Think about how the circle is maintained and what happens if the node is head or the only node.
You got /4 concepts.
Describe the difference between deleting a node in a singly linked list and a circular linked list.
Focus on how the end of the list is connected.
You got /3 concepts.
Practice
(1/5)
1. What happens when you delete the head node from a circular linked list with multiple nodes?
easy
A. The head moves to the next node and the list remains circular
B. The list becomes empty immediately
C. The last node points to null breaking the circle
D. The list throws an error and stops
Solution
Step 1: Understand the head deletion in circular list
When the head node is deleted, the next node becomes the new head.
Step 2: Maintain circular link
The last node's next pointer is updated to point to the new head, keeping the list circular.
Final Answer:
The head moves to the next node and the list remains circular -> Option A
Quick Check:
Head deletion updates head and last node pointer [OK]
Hint: Head deletion shifts head and keeps circle intact [OK]
Common Mistakes:
Assuming list becomes empty after head deletion
Breaking the circular link by setting last node to null
Not updating the last node's next pointer
2. Which of the following is the correct syntax to delete a node with value `key` from a circular linked list in JavaScript?
easy
A. function deleteNode(head) { /* code */ }
B. function deleteNode(key, head) { /* code */ }
C. function deleteNode(head, key) { /* code */ }
D. function deleteNode() { /* code */ }
Solution
Step 1: Identify function parameters for deletion
The function needs the head of the list and the key value to delete the correct node.
Step 2: Confirm correct parameter order
The common and clear order is (head, key) to access the list and the target value.
Final Answer:
function deleteNode(head, key) { /* code */ } -> Option C
Quick Check:
Parameters: head and key in order [OK]
Hint: Function needs head and key parameters in order [OK]
Common Mistakes:
Swapping parameter order causing confusion
Missing key parameter to identify node
Using no parameters making deletion impossible
3. What will be the output after deleting node with value 3 from this circular linked list: 1 -> 3 -> 5 -> 7 -> (back to 1)? <pre>function deleteNode(head, key) {
if (!head) return null;
let curr = head, prev = null;
do {
if (curr.data === key) {
if (prev) prev.next = curr.next;
else {
let temp = head;
while (temp.next !== head) temp = temp.next;
head = curr.next;
temp.next = head;
}
break;
}
prev = curr;
curr = curr.next;
} while (curr !== head);
return head;
}
// After deletion, print list starting from head
medium
A. 1 -> 5 -> 7 -> (back to 1)
B. 3 -> 5 -> 7 -> (back to 3)
C. 1 -> 3 -> 5 -> 7 -> (back to 1)
D. 5 -> 7 -> 1 -> (back to 5)
Solution
Step 1: Locate node with value 3
The code loops through nodes and finds node with data 3.
Step 2: Delete node 3 and update links
Since node 3 is not head, prev.next skips node 3 and points to node 5, maintaining circular link.
Final Answer:
1 -> 5 -> 7 -> (back to 1) -> Option A
Quick Check:
Node 3 removed, list links updated [OK]
Hint: Skip deleted node by linking previous to next [OK]
Common Mistakes:
Not updating previous node's next pointer
Deleting head incorrectly when key is not head
Breaking circular link by missing last node update
4. Identify the bug in this code snippet for deleting a node from a circular linked list:
function deleteNode(head, key) {
if (!head) return null;
let curr = head;
while (curr.next !== head) {
if (curr.next.data === key) {
curr.next = curr.next.next;
return head;
}
curr = curr.next;
}
return head;
}
medium
A. Infinite loop due to missing break
B. Does not handle deletion when head node has the key
C. Deletes multiple nodes with the key instead of one
D. Returns null even if list is not empty
Solution
Step 1: Analyze loop and deletion logic
The loop checks curr.next for key but never checks head node itself.
Step 2: Identify missing head deletion case
If head node contains key, this code does not delete it, causing incorrect behavior.
Final Answer:
Does not handle deletion when head node has the key -> Option B
Quick Check:
Head node deletion missing in logic [OK]
Hint: Always check head node separately for deletion [OK]
Common Mistakes:
Ignoring head node deletion case
Assuming loop covers all nodes including head
Not updating head pointer when head is deleted
5. Given a circular linked list with nodes 10 -> 20 -> 30 -> 40 -> (back to 10), how would you delete the last node (40) and maintain the circular structure? Choose the correct approach.
hard
A. Swap last node data with head and delete head
B. Set head to null directly to delete last node
C. Change last node's next to null to break the circle
D. Traverse to node before last, set its next to head, and delete last node
Solution
Step 1: Find node before last node
Traverse list until node.next.next equals head, identifying node before last.
Step 2: Update next pointer and delete last node
Set node before last's next pointer to head, removing last node and keeping list circular.
Final Answer:
Traverse to node before last, set its next to head, and delete last node -> Option D
Quick Check:
Update second last node's next to head [OK]
Hint: Link second last node directly to head [OK]
Common Mistakes:
Breaking circle by setting next to null
Deleting head instead of last node
Not updating pointers causing broken list
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