Array Deletion at Beginning in DSA Javascript - Time & Space Complexity
We want to understand how long it takes to remove the first item from an array.
How does the work grow when the array gets bigger?
Analyze the time complexity of the following code snippet.
const arr = [1, 2, 3, 4, 5];
arr.shift(); // removes the first element
console.log(arr);
This code removes the first element from the array and shifts the rest left.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Shifting all elements after the first one to the left by one position.
- How many times: For an array of size n, this shift happens n-1 times.
When the array size grows, the number of shifts grows almost the same way.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 9 shifts |
| 100 | 99 shifts |
| 1000 | 999 shifts |
Pattern observation: The work grows roughly in a straight line with the array size.
Time Complexity: O(n)
This means the time to delete the first element grows directly with the array size.
[X] Wrong: "Removing the first element is always fast and constant time like popping the last element."
[OK] Correct: Removing the first element requires moving all other elements, so it takes longer as the array grows.
Knowing this helps you choose the right data structure when you need fast removals at the start, like using a linked list instead of an array.
"What if we used a linked list instead of an array? How would the time complexity of deleting the first element change?"
Practice
shift() method do to an array in JavaScript?Solution
Step 1: Understand the
Theshift()methodshift()method removes the first element from an array and returns that element.Step 2: Compare with other array methods
pop()removes the last element,unshift()adds at the beginning, andpush()adds at the end.Final Answer:
Removes the first element and returns it -> Option DQuick Check:
shift()removes first element [OK]
- Confusing shift() with pop()
- Thinking shift() adds elements
- Mixing shift() with unshift()
arr in JavaScript?Solution
Step 1: Identify the method to remove first element
The method to remove the first element isshift().Step 2: Check other options
pop()removes last element,unshift()adds elements at start, anddeleteis not a valid array method.Final Answer:
arr.shift() -> Option AQuick Check:
Useshift()to remove first element [OK]
- Using pop() instead of shift()
- Trying to use delete() on arrays
- Confusing unshift() with shift()
let arr = [10, 20, 30, 40]; let removed = arr.shift(); console.log(arr); console.log(removed);
Solution
Step 1: Apply
shift()on the arrayshift()removes the first element (10) fromarrand returns it.Step 2: Check the updated array and removed value
After removal,arrbecomes [20, 30, 40], andremovedstores 10.Final Answer:
[20, 30, 40] and 10 -> Option AQuick Check:
shift() removes first element 10 [OK]
- Expecting last element removed
- Confusing returned value with array
- Not updating array after shift()
nums:let nums = [5, 10, 15]; nums.remove(0); console.log(nums);
Solution
Step 1: Check the method used
The methodremove()does not exist for JavaScript arrays.Step 2: Identify correct method to remove first element
To remove the first element, useshift()instead ofremove().Final Answer:
remove() is not a valid array method -> Option BQuick Check:
Use shift() to remove first element, not remove() [OK]
- Using remove() instead of shift()
- Assuming remove() exists in JS arrays
- Not checking method names carefully
data = [1, 2, 3, 4, 5], you want to remove the first two elements efficiently. Which code snippet correctly achieves this?Solution
Step 1: Understand each method's effect
shift(2)is invalid;shift()removes one element from start and takes no arguments.splice(0, 2)removes two elements starting at index 0 in one call.pop()removes from end, not start.slice(2)returns a new array without first two elements but does not modify original.Step 2: Choose the best method to remove first two elements
splice(0, 2)removes first two elements efficiently and modifies the original array.Final Answer:
data.splice(0, 2); -> Option CQuick Check:
splice(0, 2) removes first two elements [OK]
- Using pop() which removes from end
- Using slice() which does not modify original array
- Using shift(2) which is invalid
Ready to prove it?
Pass the test and this pattern moves unknown
