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DSA Javaprogramming~10 mins

Recursion vs Iteration When Each Wins in DSA Java - Interactive Comparison Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to calculate factorial using recursion.

DSA Java
int factorial(int n) {
    if (n == 0) {
        return 1;
    } else {
        return n * factorial([1]);
    }
}
Drag options to blanks, or click blank then click option'
A1
Bn + 1
Cn - 1
Dn
Attempts:
3 left
💡 Hint
Common Mistakes
Using n + 1 causes infinite recursion.
Using n or 1 does not reduce the problem size.
2fill in blank
medium

Complete the code to calculate factorial using iteration.

DSA Java
int factorial(int n) {
    int result = 1;
    for (int i = 1; i <= [1]; i++) {
        result *= i;
    }
    return result;
}
Drag options to blanks, or click blank then click option'
An - 1
Bn
Ci
Dresult
Attempts:
3 left
💡 Hint
Common Mistakes
Using n - 1 excludes the last multiplication.
Using i or result in the condition is incorrect.
3fill in blank
hard

Fix the error in the recursive Fibonacci function to avoid infinite recursion.

DSA Java
int fibonacci(int n) {
    if (n <= 1) {
        return n;
    } else {
        return fibonacci([1]) + fibonacci(n - 2);
    }
}
Drag options to blanks, or click blank then click option'
An - 1
Bn + 1
C1
Dn
Attempts:
3 left
💡 Hint
Common Mistakes
Using n + 1 causes infinite recursion.
Using n or 1 does not correctly reduce the problem size.
4fill in blank
hard

Fill both blanks to complete the iterative Fibonacci function.

DSA Java
int fibonacci(int n) {
    if (n <= 1) return n;
    int a = 0, b = 1, c;
    for (int i = 2; i <= [1]; i++) {
        c = a + b;
        a = [2];
        b = c;
    }
    return b;
}
Drag options to blanks, or click blank then click option'
An
Bb
Ca
Dc
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong loop limit causes incorrect results.
Assigning a = a or a = c breaks the Fibonacci sequence.
5fill in blank
hard

Fill all three blanks to create a recursive function that sums elements of an array.

DSA Java
int sumArray(int[] arr, int index) {
    if (index == [1]) {
        return 0;
    }
    return arr[[2]] + sumArray(arr, [3]);
}
Drag options to blanks, or click blank then click option'
Aarr.length
Bindex
Cindex + 1
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using 0 as base case index causes infinite recursion.
Not incrementing index in recursive call causes infinite loop.

Practice

(1/5)
1. Which scenario is best suited for using recursion instead of iteration?
easy
A. When the problem can be divided into similar smaller problems
B. When you want to avoid function call overhead
C. When memory usage must be minimal
D. When the problem requires simple repeated loops

Solution

  1. Step 1: Understand recursion use case

    Recursion works well when a problem can be broken down into smaller similar problems, like tree traversals or factorial calculation.
  2. Step 2: Compare with iteration scenarios

    Iteration is better for simple repeated loops or when minimizing overhead and memory is critical.
  3. Final Answer:

    When the problem can be divided into similar smaller problems -> Option A
  4. Quick Check:

    Recursion fits divide-and-conquer problems = A [OK]
Hint: Recursion fits problems breaking into smaller similar parts [OK]
Common Mistakes:
  • Thinking iteration is always better for all problems
  • Ignoring function call overhead in recursion
  • Confusing recursion with simple loops
2. Which of the following is the correct syntax to write a recursive method in Java?
easy
A. public void recurse() { recurse(); }
B. public void recurse() { while(true) recurse(); }
C. public void recurse() { if(condition) recurse(); }
D. public void recurse() { for(int i=0; i<10; i++) recurse(); }

Solution

  1. Step 1: Identify valid recursive call

    A recursive method must have a base condition to stop calling itself, so it uses if(condition) before recursion.
  2. Step 2: Check options for base condition

    public void recurse() { if(condition) recurse(); } uses if(condition) recurse(); which is correct. Others cause infinite recursion or misuse loops.
  3. Final Answer:

    public void recurse() { if(condition) recurse(); } -> Option C
  4. Quick Check:

    Base condition needed for recursion = D [OK]
Hint: Recursive calls must have a stopping condition [OK]
Common Mistakes:
  • Writing recursion without base condition
  • Using loops inside recursion incorrectly
  • Confusing infinite recursion with iteration
3. What will be the output of the following Java code?
public class Test {
  static int count = 0;
  public static void recurse(int n) {
    if (n == 0) return;
    count++;
    recurse(n - 1);
  }
  public static void main(String[] args) {
    recurse(3);
    System.out.println(count);
  }
}
medium
A. 4
B. 3
C. 0
D. StackOverflowError

Solution

  1. Step 1: Trace recursive calls

    recurse(3) calls recurse(2), then recurse(1), then recurse(0) which returns without incrementing count.
  2. Step 2: Count increments

    count increments at n=3, 2, 1, so total increments = 3.
  3. Final Answer:

    3 -> Option B
  4. Quick Check:

    Count increments per call except base = 3 [OK]
Hint: Count increments before recursive call, base stops at zero [OK]
Common Mistakes:
  • Counting base case call as increment
  • Expecting stack overflow due to small input
  • Miscounting recursive calls
4. Identify the error in this iterative factorial method and fix it:
public static int factorial(int n) {
  int result = 1;
  for (int i = 1; i <= n; i++) {
    result = result * i;
  }
  return result;
}

// Called with factorial(-3)
medium
A. Missing return statement
B. Infinite loop due to wrong loop condition
C. No error, returns 1 for negative input
D. Should check for negative input to avoid incorrect result

Solution

  1. Step 1: Analyze loop behavior with negative input

    For n = -3, loop condition i <= n is false at start (1 <= -3), so loop never runs and returns 1 incorrectly.
  2. Step 2: Add input validation

    Factorial is undefined for negative numbers, so method should check and handle negative input before loop.
  3. Final Answer:

    Should check for negative input to avoid incorrect result -> Option D
  4. Quick Check:

    Validate input before iteration = A [OK]
Hint: Always validate inputs before loops in iterative methods [OK]
Common Mistakes:
  • Ignoring negative inputs in factorial
  • Assuming loop runs for negative n
  • Missing input validation
5. You need to process a large dataset with unknown depth of nested structures. Which approach is better and why?

Options:
A) Use recursion for simplicity but risk stack overflow.
B) Use iteration with explicit stack to handle unknown depth safely.
C) Use recursion with no base case to ensure all data is processed.
D) Use iteration with fixed loop count assuming max depth known.
hard
A. Use iteration with explicit stack to handle unknown depth safely.
B. Use recursion for simplicity but risk stack overflow.
C. Use recursion with no base case to ensure all data is processed.
D. Use iteration with fixed loop count assuming max depth known.

Solution

  1. Step 1: Understand problem constraints

    Unknown depth means recursion might cause stack overflow if too deep.
  2. Step 2: Compare recursion and iteration

    Iteration with an explicit stack simulates recursion safely and avoids overflow.
  3. Step 3: Evaluate incorrect options

    Use recursion with no base case to ensure all data is processed. is wrong due to no base case causing infinite recursion. Use iteration with fixed loop count assuming max depth known. assumes fixed depth which is unsafe.
  4. Final Answer:

    Use iteration with explicit stack to handle unknown depth safely. -> Option A
  5. Quick Check:

    Iteration + explicit stack avoids recursion limits = B [OK]
Hint: Use explicit stack iteration for unknown or deep recursion [OK]
Common Mistakes:
  • Ignoring stack overflow risk in recursion
  • Assuming fixed depth for iteration
  • Missing base case in recursion
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