N Queens Problem in DSA Java - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the main goal of the N Queens Problem?

To place N queens on an N×N chessboard so that no two queens attack each other. This means no two queens share the same row, column, or diagonal.

beginner

How do we check if a queen placement is safe in the N Queens Problem?

We check three conditions: no other queen in the same column, no other queen in the same major diagonal, and no other queen in the same minor diagonal.

intermediate

What technique is commonly used to solve the N Queens Problem?

Backtracking is used. It tries placing queens row by row and backtracks if a conflict is found, exploring all possible safe placements.

intermediate

Why is backtracking suitable for the N Queens Problem?

Because it systematically explores all possible queen placements and abandons paths that lead to conflicts early, saving time and effort.

advanced

What is the time complexity of the N Queens Problem using backtracking?

The worst-case time complexity is O(N!), because each queen placement reduces the options for the next queen, but many branches are pruned.

In the N Queens Problem, what does a 'safe' position mean?

A No other queen in the same row only

B No other queen in the same row, column, or diagonal

C No other queen in the same column only

D No other queen in the same diagonal only

A safe position means no queen attacks another, so no queens share the same row, column, or diagonal.

Which algorithmic technique is primarily used to solve the N Queens Problem?

A Greedy algorithm

B Dynamic programming

C Backtracking

D Divide and conquer

Backtracking tries all possible placements and backtracks when conflicts occur.

How many queens must be placed on the board in the N Queens Problem?

A N queens on an N×N board

B N queens on a 2N×2N board

C N/2 queens on an N×N board

D N queens on an N×(N-1) board

The problem requires placing N queens on an N×N board.

What happens if a queen placement leads to no safe positions for the next queen?

A The algorithm stops

B The board size is increased

C The queen is removed permanently

D The algorithm backtracks to try a different position

Backtracking means going back to try other options when stuck.

Which of these is NOT a constraint for queen placement in the N Queens Problem?

A No two queens in the same color square

B No two queens in the same column

C No two queens in the same diagonal

D No two queens in the same row

The color of the square does not affect queen attacks.

Explain how backtracking helps solve the N Queens Problem step-by-step.

Think about trying positions and undoing moves when stuck.

Describe how to check if a queen's position is safe on the board.

Remember queens attack vertically and diagonally.

Practice

1. What is the main goal of the N Queens Problem?

easy

A. Place queens only on the diagonal cells of the board

B. Place N queens on an NxN chessboard so that no two queens attack each other

C. Count the total number of queens on the board

D. Find the shortest path for a queen to move across the board

Solution

1. Step 1: Understand the problem statement

   The N Queens Problem requires placing N queens on an NxN chessboard so that no two queens threaten each other.

2. Step 2: Identify the correct goal

   This means no two queens share the same row, column, or diagonal.

3. Final Answer:

   Place N queens on an NxN chessboard so that no two queens attack each other -> Option B

4. Quick Check:

   Goal = Place queens safely [OK]

Hint: Remember: no two queens can share row, column, or diagonal [OK]

Common Mistakes:

• Thinking queens can share the same row or column
• Confusing the problem with counting queens
• Assuming queens only attack diagonally

2. Which of the following Java method signatures is correct for a recursive function solving the N Queens Problem?

easy

A. static int solveNQueens(int[][] board, int n, int row)

B. public void solveNQueens(int n, int row, int[][] board)

C. public static boolean solveNQueens(int row, int n, int[][] board)

D. boolean solveNQueens(int n, int[][] board, int row)

Solution

1. Step 1: Check method signature correctness

   The recursive method should return a boolean indicating success/failure, take current row, board size, and board state.

2. Step 2: Validate parameter order and modifiers

   public static boolean solveNQueens(int row, int n, int[][] board) matches this: public static boolean solveNQueens(int row, int n, int[][] board)

3. Final Answer:

   public static boolean solveNQueens(int row, int n, int[][] board) -> Option C

4. Quick Check:

   Correct signature = public static boolean solveNQueens(int row, int n, int[][] board) [OK]

Hint: Recursive method returns boolean and takes current row first [OK]

Common Mistakes:

• Wrong return type (e.g., void instead of boolean)
• Incorrect parameter order
• Missing static keyword if required

3. What will be the output of the following Java code snippet for N=4?

public class NQueensTest {
    static int count = 0;
    public static void main(String[] args) {
        int n = 4;
        int[][] board = new int[n][n];
        solveNQueens(0, n, board);
        System.out.println(count);
    }
    static boolean solveNQueens(int row, int n, int[][] board) {
        if (row == n) {
            count++;
            return true;
        }
        boolean res = false;
        for (int col = 0; col < n; col++) {
            if (isSafe(row, col, board, n)) {
                board[row][col] = 1;
                res = solveNQueens(row + 1, n, board) || res;
                board[row][col] = 0;
            }
        }
        return res;
    }
    static boolean isSafe(int row, int col, int[][] board, int n) {
        for (int i = 0; i < row; i++) {
            if (board[i][col] == 1) return false;
        }
        for (int i = row, j = col; i >= 0 && j >= 0; i--, j--) {
            if (board[i][j] == 1) return false;
        }
        for (int i = row, j = col; i >= 0 && j < n; i--, j++) {
            if (board[i][j] == 1) return false;
        }
        return true;
    }
}

medium

A. 2

B. 4

C. 1

D. 0

Solution

1. Step 1: Understand the code logic

   The code counts all valid solutions for 4 queens on a 4x4 board using backtracking.

2. Step 2: Recall known result for 4 queens

   It is a well-known fact that there are 2 valid solutions for the 4 queens problem.

3. Final Answer:

   2 -> Option A

4. Quick Check:

   Number of solutions for N=4 = 2 [OK]

Hint: Remember: 4 queens have exactly 2 solutions [OK]

Common Mistakes:

• Assuming only 1 solution exists
• Confusing number of solutions with board size
• Ignoring backtracking resets

4. Identify the bug in this snippet of the N Queens solver:

static boolean isSafe(int row, int col, int[][] board, int n) {
    for (int i = 0; i < row; i++) {
        if (board[i][col] == 1) return false;
    }
    for (int i = row, j = col; i >= 0 && j >= 0; i--, j--) {
        if (board[i][j] == 1) return false;
    }
    for (int i = row, j = col; i >= 0 && j <= n; i--, j++) {
        if (board[i][j] == 1) return false;
    }
    return true;
}

medium

A. It incorrectly checks columns beyond the board size

B. It does not check the left diagonal upwards

C. It does not check the current row for other queens

D. It misses checking the lower diagonals for threats

Solution

1. Step 1: Analyze the safety checks

   The column check and upper-left diagonal are correct.

2. Step 2: Identify the bug in upper-right diagonal

   The loop condition 'i >= 0 && j <= n' allows j to reach n (e.g., when col = n-1, after first iteration j = n), causing ArrayIndexOutOfBoundsException on board[i][n].

3. Final Answer:

   It incorrectly checks columns beyond the board size -> Option A

4. Quick Check:

   Upper-right diagonal: j <= n causes out-of-bounds [OK]

Hint: Always verify loop bounds in diagonal checks to avoid index errors [OK]

Common Mistakes:

• Forgetting off-by-one errors in diagonal loop conditions
• Overlooking array bounds in upper-right diagonal traversal
• Confusing upper vs lower diagonal checks

5. You want to modify the N Queens solver to print all distinct solutions for N=4. Which approach is best to achieve this?

hard

A. Stop recursion as soon as the first solution is found to save time

B. Place all queens in the first row and check if they attack each other

C. Use a greedy algorithm to place queens in the first available safe spot in each row

D. Modify the recursive function to store each valid board configuration in a list instead of returning after first success

Solution

1. Step 1: Understand the requirement

   We want to find and print all distinct solutions, not just one.

2. Step 2: Choose the correct approach

   Modifying the recursive function to continue searching after finding a solution and storing each valid board is the correct approach.

3. Step 3: Eliminate wrong options

   Stopping after first solution won't find all solutions. Greedy algorithm to place queens in the first available safe spot in each row and placing all queens in the first row and check if they attack each other are incorrect strategies.

4. Final Answer:

   Modify the recursive function to store each valid board configuration in a list instead of returning after first success -> Option D

5. Quick Check:

   Store all solutions by continuing recursion [OK]

Hint: Keep searching after each solution to collect all boards [OK]

Common Mistakes:

• Stopping recursion after first solution
• Using greedy instead of backtracking
• Placing multiple queens in one row